similar to: Scatter plot - using colour to group points?

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs

Hi all :) Using lm_sensors, I can see few temperature indicator. M/B Temp: +39?C (low = +15?C, high = +40?C) sensor = thermistor CPU Temp: +33?C (low = +15?C, high = +45?C) sensor = thermistor Temp3: +53?C (low = +15?C, high = +45?C) sensor = diode What is that Temp3? It's the hottest. Which one is the best to use if I want to use lm_sensor as a general

Hello there, after I solved many problems in the last days with R I wanted to complete my plot. I used ylab=expression(paste("log(",mu,"/",cm^2,"/VS)")) to have greek symbols and to change cm^2 to cm?. Also cm^-3 I have in another plot, but it cuts my ^2 to _ in the y-axis. here is the code and I attach the plot: jpeg(file="Tabh2.jpg",quality=100)

i have a time Series of IBM closing px from 1/1/2000 to today I want to graph the time serie by dividing the graph by year and month all the monthly graphs with the same year will go to one page. so from 1/1/2000 to 11/19/2010. i will have 11 pages, and each page will have 12 graphs (jan to dec) except for 2010. I am able to do it in R, but when i use sweave, I can only print the last page.

Hi all, I have a C code in Linux, it has 7 pointers and compile e run OK, but when I run in R happens problems with calloc function, it returns NULL. ############################################### > int *temp1,*temp2,*temp3,*temp4; temp1 = (int *)calloc(col,sizeof(int)); if(temp1 == NULL){ printf("\n\n No Memory1!"); exit(1); } temp2 = (int *)calloc(col,sizeof(int));

Dear all, I am working on a data set in which I have sequentially measured egg temperatures ("eggtemp") in birds incubating in different ambient temperatures ("treat", sample data set below), "id" is not replicated within treatment. id treat eggtemp 1 79 3 30.90166 2 42 3 34.94044 3 10 3 32.69945 4 206 3 36.64127 5 23 3 31.80055 6

temp = "~aparch(" temp1 = paste(temp,1, sep = "") temp2 = paste(temp1,1, sep = ",") temp3 = paste(temp2, ")",sep = "") temp 3 is a character but I want to convert to formula object. How do I do this? -- View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html Sent from the R help mailing

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Full_Name: Jim Breaux Version: 1.9.0 OS: WinXP Submission from: (NULL) (209.78.110.135) dir.create() is reporting a warning that a directory already exists when in fact the directory does NOT already exist. However, the erroneous behavior does not manifest itself until dir.create() has been called at least once to create a directory that DOES already exist. For example: # Create a directory

Hi, I am writing a function to plot a pdf of a distribution, GNL.pdf.fn = function(x,mu,sigma,alpha,beta,rho) { y = x-rho*mu cf.fn = function(s){ cplex = complex(1,0,1) temp1 = alpha*beta*exp(-sigma*s^2/2) temp2 = (alpha-cplex*s)*(beta+cplex*s) out = (temp1/temp2)^rho out } temp.fn = function(s){ (Mod(cf.fn(s)))*cos(Arg(cf.fn(s))-s*y) } int.fn =

Naresh, I am not sure how you are creating your data.frame so it has no, I think, column names. There are two scenarios including one where it is not really a valid data.frame and one where it can be handled before any other use as shown below. If it cannot be used, you might need to modify how your SQL or the function you call creates it so it includes either names it chooses or that you supply.

Hi, temp3<- read.table(text=" ID CTIME WEIGHT HM001 1223 24.0 HM001 1224 25.2 HM001 1225 23.1 HM001 1226 NA HM001 1227 32.1 HM001 1228 32.4 HM001 1229 1323.2 HM001 1230 27.4 HM001 1231 22.4236 #changed here to test the previous solution ",sep="",header=TRUE,stringsAsFactors=FALSE) ?tempnew<- na.omit(temp3) ?grep("\\d{4}",temp3$WEIGHT) #[1] 7 9 #not correct

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

I have a controller that gets a list of employees (which has an "include => [:salaries, :incentives, :billablegoals, :reviews]"). I then need it to iterate through each employee and determine their current active goal based on the "effective date." After playing around with it a bunch, I got the following to work. Only problem is that if I remove the "@employees.each {

There you go, once again helping strengthen ;) John Get Outlook for iOS<https://aka.ms/o0ukef> ________________________________ From: R-help <r-help-bounces at r-project.org> on behalf of avi.e.gross at gmail.com <avi.e.gross at gmail.com> Sent: Tuesday, January 28, 2025 12:01:25 AM To: 'Naresh Gurbuxani' <naresh_gurbuxani at hotmail.com>; r-help at r-project.org

Hi everyone I am new to R and have a question about missing values. I am trying to do a cluster analysis of monthly temperatures and my data are 14 columns with spatial coordinates (lat,lon) and 12 monthly values: /lat - lon - temp1 - //temp2 - temp3 - .... - //temp12/ If I omit missing values (my missing values are 99.00) with /mydata <- na.omit(mydata)/ every row with a

#If I have two lists as follows a1<- array(1:6, dim=c(2,3)) a2<- array(7:12, dim=c(2,3)) l1<- list(a1,a2) a3<- array(1:4, dim=c(2,2)) a4<- array(5:8, dim=c(2,2)) l2<- list(a3,a4) #how can I create a new list with the mean across all arrays within the list, so all components are included? As an example for [[1]]; cbind((l1[[1]][,1]+l2[[1]][,1])/2,

On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote: > Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. > > Something like: > > Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;? > > Prices <- dbGetQuery(con, myquery) > SetDT(Prices) > Prices[,

Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. Something like: Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;? Prices <- dbGetQuery(con, myquery) SetDT(Prices) Prices[, date = as.Date(date)] R CMD check say ?no visible binding for global variable ?date?? Sent

This solution worked. Thanks Sent from my iPhone > On Jan 28, 2025, at 3:09?PM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > > ?On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote: >> Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns. >> Something like: >> Myquery <- ?SELECT date,