similar to: Generating Sequence of Dates

Hello All: I have the following question # instantiate a date current = as.Date("2009/10/25") #generate a sequence of dates in the future future_dates = seq(current,by='1 week',length=53) Question: How to generate a sequence of past dates starting one week in the past relative to the current date. Obviously, what I wrote below is not correct. I think I can write a for loop and

Hello, I have the starting date in UNIX_TIME LONG number (number of milliseconds since 1970 jan 1st). Is there a way to generete the sequence of dates with monthly interval in POSIXct format like 2000-01-01 2000-02-01 2000-03-01 etc Thanks [[alternative HTML version deleted]]

hits=-2.6 tests=BAYES_00 X-USF-Spam-Flag: NO Dear List, Say I have the following sequence of dates [*]: start <- as.Date("2005-01-05", format = "%Y-%d-%m") end <- as.Date("2007-10-07", format = "%Y-%d-%m") my.dates <- seq(start, end, by = "days") What I would like to generate is a sequence of dates, by month that goes from the first

Hi: I have a dataframe named 'spring' and I am trying to add a new variable named 'IdDate' This line of code works fine: spring$idDate <- seq(as.Date("2008-07-01"),as.Date("2009-06-30"),by="week") But I don't want to hardcode the year because it will be used again the following year Is it possible to just generate dates with the month and

Hi My data looks like this startDate="2008-06-01" dateRange =c( "2008-10-01","2008-12-01") Is there any method to find the week number from the startDate range ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Week-number-from-a-date-tp4410223p4410223.html Sent from the R help mailing list archive at Nabble.com.

Hi I need to add an year to and date field in the dataframe. Please help me X Date 1 2008-01-01 2 2008-02-01 3 2003-03-01 Thanks in advance -- View this message in context: http://r.789695.n4.nabble.com/Adding-a-year-to-existing-date-tp4078930p4078930.html Sent from the R help mailing list archive at Nabble.com.

I understand that the two following loops should produce the exact same output. However, they do not. It appears that looping directly through the sequence of Date objects somehow makes them be coerced to numeric: > date1 = "20130301" > date2 = "20130302" > > d1 = as.Date(date1, format="%Y%m%d", tz="GMT") > d2 = as.Date(date2,

Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".

Hello all, As an example, consider the following dataframe > df<-data.frame(id=c("b","b","a","a","a"),ord=c(2,1,1,3,2)) > dates<-as.Date(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92"),"%m/%d/%y") > df$dates<-dates which was ordered with >

Dear R-users, First of all, I'm sorry if this is a simple question. I want a daily date series which will be a sequence. E.g. starting from 07/03/1962 to 12/03/1997. Thanks in advance. I want to paste this date series with the data series I have. Thanks & Regards, Sumanta Basak.

Hello All: I am trying to generate a sequence of dates using library(chron). Using the following code, I got most of what I want, dts <- seq.dates("01/02/1998", "01/10/2001", by="day") dts <- dts[!is.weekend(dts)] a sequence of weekdays only (no weekend dates), with first observation appearing as 01/02/98 and the last 01/10/01. But I would

Hi I have a data-frame which look like this X1 X2 X3 1 3 5 2 4 6 3 6 1 I want to apply a formula Y=6*X1 + 7*X2 + 8*X3 for every row Thanks in Advance -- View this message in context: http://r.789695.n4.nabble.com/how-to-call-a-function-for-each-row-tp4122906p4122906.html Sent from the R help mailing list archive at Nabble.com.

Hi I have set of records seperated by a separator say "$$$" i want to get the values in a dataframe. eq qwer$$12$$qwre ewrtr$7789$ewwe I want the output as\ V1 V2 V3 qwer 12 qwre ewrtr 7789 ewwwe Please help me ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Help-in-splitting-the-records-tp4650827.html Sent from

Pardon the barrage of time series related questions, but another issue I'm trying to solve is how to determine a sequence of dates a la seq.dates() except going BACKWARDS in time, e.g. if seq.dates() allowed for the "to" variables to be set alone, rather than the from=. Ultimately, I'd like to have a set of dates preceding a given date in predefined intervals (the same ones

Hi I have a data frame and i need to change the date format in it. my dataframe X Date 1 1/1/2009 2 2/1/2009 3 3/1/2009 I need to change it to 2009-01-01 -- View this message in context: http://r.789695.n4.nabble.com/changing-date-format-in-a-dataframe-tp4076411p4076411.html Sent from the R help mailing list archive at Nabble.com.

hi I have a data like thursday, November 20,2012. I'm not able to convert into data format in R Can anyone please help ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/read-the-date-format-tp4635245.html Sent from the R help mailing list archive at Nabble.com.

Hi I have a find the class of each variable of the data set which is given as input. I can able to find the string and the numeric variable. Not able to find if the variable is date or not Can any one help me. ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/how-to-get-a-date-variable-from-a-dataset-tp4639038.html Sent from the R help

Hi I have a function y= x^2 min =10 max=20 increment=0.1 I want to find the value of y for the value of x between min and max by step increment. how to get the values using apply function instead of for loop ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Help-required-in-using-apply-instead-of-for-loop-tp4344350p4344350.html Sent from the

There seem to be a bug in the seq.dates function in the chron package for R 2.0. Please see below: when the specified frequency is "months", seq.dates does not return the end of the specified interval all the time: > seq.dates(from = "05/31/04", to = "12/31/04", by = "months") [1] 05/31/04 06/30/04 07/31/04 08/31/04 09/30/04 10/31/04 11/30/04 Ciprian

I would like a sequence of dates with a time step of 15 minutes starting: 1/1/2006 00:00:00 - 12/31/2006 23:45:00 function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } this is the piece of code I use to read in zoo objects for any help I would be grateful I have tried sequence and I can not seem to get it to work -- Let's not