similar to: R help

Hi, I want to use a more accurate value of exp(1).  The value given by R is 2.718282. I want a value which has more than 15 decimal places. Can anyone let me know how can I increase the accuracy level. Actually there are some large multipliers of exp(1) in my whole expression, and I want a more accurate result at the last step of my program, and for that I need to use highly accurate value

Hi I was trying to have a graph whose axes are X axis: m, Y axis: var[X ((a,b) in suffix, and (n,d) in the power)]. X ((a,b) in suffix, and (n,d) in the power)- X^(n,d) _ (a,b). Actually I require many plots involving different values of a,b,n,d, so need to keep this complicated notation. The expression() didn't work out for this case. Can anyone help me out. Thanks, in advance.

Hi, I wanted to compute the value of the function ifn at certain values of n. But I am receiving the following error when I was using the following code(given at the end). Error: evaluation nested too deeply: infinite recursion / options(expressions=)? I feel that since the function Grx is recursively related, perhaps making the code too complicated too handle. Can anyone let me know if

Hi, I was trying to have a graph whose axes are of the following type: X axis: n and Y axis: var[U ((a,b) in suffix, and (n,d) in the power)]. U ((a,b) in suffix, and (n,d) in the power)- U^(n,d) _ (a,b). Actually I require many plots involving different values of a,b,n,d, so need to keep this complicated notation. The code I used: plot(n, hn$h_pg,

Hello, I want to draw a histogram of the mean of sample observations drawn from multivariate t distribution. I am getting the following error corresponding to the code I used. Though I am getting the graph, but I am curious to know the warning message. Warning messages: 1: In if (freq) x$counts else { : the condition has length > 1 and only the first element will be used 2: In if (!freq)

Hello R users, I have two data sets like the following. Form of dataset: data: X1 X2 X3 X4 X5 1902 RE 3 594 9 1903 RE 3 1340 7 1904 AA 3 760 14 1908 RE 4 1759 18 1909 EX 2 387 1 2901 AU 6 3116

Hi R-users, I was plotting the differences of the variances of the three estimators- T^(1), T^(2), T^(3), ofcourse taking two at a time. I was using the expression() in the legend function in order to show which line correspond to which of the difference, but the following that I had used didn't gave desired result. I would be grateful, if you help me out. plot(n, pg,

Hello everyone! I want to use density function of R to compute the density at x(=0, say). But it is giving me the 5-number summary and mean of the data and densities at that point. I just want the densities at different values specified by me. Can anyone let me know how can I find that? For example Thanks in advance for your help. Shant [[alternative HTML version deleted]]

Hi, I wanted to compute the value of the function ifn at certain values of n. But I am receiving the following error when I was using the following code(given at the end). Error: evaluation nested too deeply: infinite recursion / options(expressions=)? I feel that since the function Grx is recursively related, perhaps making the code too complicated too handle. Can anyone let me know if

Hello, I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 ) While using this I am getting the following error. Can anyone please help me out. Error in uniroot(function(x) x * (3^x) * log(4) - x * log(4/3) - (3^x) + : f() values at end points not of opposite sign.

Hi! Can anyone please let me know what numerical integration procedure does the integrate function in package stats follow? Thank you in advance Shant [[alternative HTML version deleted]]

Hi, I want to find a value of n1. I used the following code but I am getting the error - Error in as.vector(x, mode) : cannot coerce type 'closure' to vector of type 'any' n=10 a_g<-(1/(n*(n-1)))*((pi/3)*(n+1)+(2*sqrt(3)*(n-2))-4*n+6) a_s<-function(n1) { t1=(n1-1)/2; (t1*(gamma(t1)/gamma(n1/2))^2)/2-1-a_g } xm<-solve(a_s) Can anyone help me out. Thanks in

Hi, I was plotting or creating a map for Texas school districts using the shape file of Texas. I could not find any other helpful mail in the mailing list. txshp<-read.shape(system.file("S:\\Districts_10_11.shp", package="maptools")) Error- read.shape no found. But read.shape is there in maptools. If anyone can help me out it will be great. Thanks in advance. Shant

Hello all, I was going to solve (n-m)! * (n-k)! = 0.5 *n! * (n-m-k)! for m when values of n and k are provided n1<-c(10,13,18,30,60,100,500)         # values of n kx<-seq(1,7,1);                               # values of k slv2<-lapply(n1,function(n){    slv1<-lapply(kx,function(k){              lhs<-function(m)              {                

Dear R users, I am new users of this software. I want to make box plot. Here, i have simulated data set with following commands: x<-matrix(rnorm(90),nrow=10,ncol=9) x a<-matrix(c(1,1,1,1,1,2,2,2,2,2),nrow=10,ncol=1) xx<-cbind(a,x)

n=10 x1<-(1:n)/n y1<-rnorm(n,x1^2,1) m=20 x2<-(1:m)/m The value of y2 will be rnorm (m, x2^2,1) if none of the elements of x2 is same as x1, but for every same elements in x1 and x2, the value of y2 will be same as y1. I know the following is correct, but for large vectors, this won't work efficiently as this is taking longer time. Can you please let me know how to write the

Dear R-users, I have a complex line by xy-values (ordered by z). And I would like to get interpolated y-values on the positions of x = 0:600. How do I get the correct points? x=c(790,790,790,790,790,786,783,778,778,766,763,761,761,761,715,628,521,350,160,134,134,129,108,101,93,111,161,249,288,243,139,45,7)

Dear Rui and UseRs,[a text file has also been attached, in case the format of my email is difficult to get]I am extremely sorry that I am bothering you once again, but I?ll have to get to the bottom of it. The following command sp <- lapply(split(agg, agg$st), function(x) x[order(x$year, x$month), ]) gave me an output with monthly mean of population(as under). i am not able to apply

Hi, again i am stuck in my presentation, and i have never learn R before in my life but need this to be done, so please help me out for a favour: http://www.nabble.com/file/p20333155/kew.dat kew.dat run this in R and these comes up: Month Year Rain 1 Jan 1900 74.400000 2 Feb 1900 80.500000 3 Mar 1900 23.600000 4 Apr 1900 23.600000 5 May 1900 25.100000 6

Hi, I noticed that as.Date() could not convert date string to date type if the dates are very old. For example, if the date string is "1-Mar-50", then as.Date() would convert this to "2050-03-01", NOT "1950-03-01". This seems to be the behavior of as.Date() for dates older than 1969-1-1, and it is not documented in the R as.Date() documentation. It seems very strange