Displaying 20 results from an estimated 200 matches similar to: "Problem with GROUP()"
2018 Feb 25
1
reshaping column items into rows per unique ID
Hi Allaisone,
I took a slightly different approach but you might find this either as or
more useful than your approach, or at least a start on the path to a
solution you need.
df1 <-
data.frame(CustId=c(1,1,1,2,3,3,4,4,4),DietType=c("a","c","b","f","a","j","c","c","f"),
2013 Sep 02
1
R dataframe and looping help
HI,
You may try this:
dat1<- read.table(text="
CustID TripDate Store Bread Butter Milk Eggs
1 2-Jan-12 a 2 0 2 1
1 6-Jan-12 c 0 3 3 0
1 9-Jan-12 a 3 3 0 0
1 31-Mar-13 a 3 0 0 0
2 31-Aug-12 a 0 3 3 0
2 24-Sep-12 a 3 3 0 0
2 25-Sep-12 b 3 0 0 0
",sep="",header=TRUE,stringsAsFactors=FALSE)
dat2<- dat1[,-c(1:3)]
res<- lapply(seq_len(ncol(dat2)),function(i)
2004 Sep 11
3
SAS to R migration questions
Hi,
I'd like to get away from SAS, but I don't really know R well enough at
this point to know if it would be good for this project. I tried to
describe the essence of the project below without getting bogged down in
details.
It starts when I receive a data flat file. There's lots of columns, but
the relevant ones are:
custid (customer ID number)
saledt (date of sale)
2018 Feb 25
0
reshaping column items into rows per unique ID
I believe you need to spend time with an R tutorial or two: a data frame
(presumably the "table" data structure you describe) can *not* contain
"blanks" -- all columns must be the same length, which means NA's are
filled in as needed.
Also, 8e^5 * 7e^4 = 5.6e^10, which almost certainly will not fit into any
local version of R (maybe it would in some server version --
2018 Feb 25
4
reshaping column items into rows per unique ID
Hi All
I have a datafram which looks like this :
CustomerID DietType
1 a
1 c
1 b
2 f
2 a
3 j
4 c
4 c
4 f
And I would like to reshape this so I can
2006 Apr 26
5
accessing created_on causes type error
I assume that this is some newbie stupidity, but I haven''t found my
way around this problem. I have an ActiveRecord object fetched
from the database, and I need to evaluate the contents of the
updated_on field. However, *any* attempt to access that data in the
program results in a TypeError with the message ''no implicit conversion
from nil to integer''.
cust =
2009 Jun 07
2
How do I construct a one matrix from another? (newbie)
Apologies if this is an obvious question but I am teaching myself R and the
occasional push in the right direction is much appreciated?
I have a data.frame containing data that looks like this
CustID itemID
1 a
1 b
2 c
3 a
3 c
I want to assemble the vector of all the items bought by a particular
customer and can't quite see how to do it.
What is the best
2017 Oct 09
1
Help RFM analysis in R (i want a code where i can define my own breaks instead of system defined breaks used in auto_RFM package)
Hi Hemant,
Here is an example that might answer your questions. Please don't run
previous code as it might not work.
I define the break values as arguments to the function
(rbreaks,fbreaks,mbreaks) If you want the breaks to work, make sure that
they cover the range of the input values, otherwise you get NAs.
# expects a three (or more) column data frame where
# column 1 is customer ID,
2010 Jun 14
4
Unable to pickup an extension, trying everything
Hello list,
I try to pick up a ringing extension but nothing works.
To be clear, I'm trying to pick up extension 10.
[Jun 14 17:37:34] -- Executing [**10 at from-TESTCORP:4]
Pickup("SIP/testcorp3-00000041", "10 at 123456") in new stack
[Jun 14 17:37:34] NOTICE[16555]: app_directed_pickup.c:159 pickup_exec:
No target channel found for 10.
[Jun 14 17:37:34] --
2017 Oct 09
0
Help RFM analysis in R (i want a code where i can define my own breaks instead of system defined breaks used in auto_RFM package)
I'm getting all the rows as NA in Cscore and almost most of the
observation in R and F and M are also NA.
what can be the reason for this. also suggest me the appropriate solution.
On 9 October 2017 at 15:51, Jim Lemon <drjimlemon at gmail.com> wrote:
> Hi Hemant,
> Here is an example that might answer your questions. Please don't run
> previous code as it might not work.
2017 Oct 09
2
Help RFM analysis in R (i want a code where i can define my own breaks instead of system defined breaks used in auto_RFM package)
I seriously doubt that you are running the code I sent. What you have
probably done is to run your data, which has a different date format,
without changing the breaks or the date format arguments. As you
haven't provided any example that shows what you are doing, I can't
guess what the problem is.
Jim
On Mon, Oct 9, 2017 at 9:40 PM, Hemant Sain <hemantsain55 at gmail.com> wrote:
2017 Oct 10
0
Help RFM analysis in R (i want a code where i can define my own breaks instead of system defined breaks used in auto_RFM package)
Hello Jim,
i have converted all my variable data type according to your attached
example including date, and my dataset looks like this.
ID purchase date
1234 10.2 2017-02-18
3453 18.9 2017-03-22
7689 8 2017-03-24
but when I'm passing the data
2010 Sep 09
1
syntax error, unexpected '<token>'
Hello list,
getting warning : *syntax error, unexpected '<token>'*
dialplan :
exten => pbx,n,Macro(CheckNetworkProblems,${custID})
exten => pbx,n,NoOp(status = ${STATUS})
exten => pbx,n,GoToIf($["${STATUS}"="congestion"]?backup:nocongestion)
CLI :
[Sep 9 12:27:07] -- Executing [pbx at cust:15]
NoOp("SIP/test13-0000002a",
2006 May 04
0
Eliminating For Loop in Comparison and Replacement
Hi,
I have two dataframes: (Fails, Refurb) each is identical in structure.
The structure has columns consisting of the following: EquipID(Equipment
Identification), CustID(Customer Identification), FailTimes(Time
Equipment Failed). The for loop below is part of a larger Monte Carlo
simulation involving the reliability of equipment and customers.
for (i in 1:length(Fails$CustID)){
j<-1
2010 Mar 04
0
Availstatus returns 20 ?
Hello list.
ChanIsAvail returns 20 for ${AVAILSTATUS}. What does this '20' mean ??
...
exten => 1,n,ChanIsAvail(SIP/sin10)
exten => 1,n,NoOp(chanisavail == ${AVAILSTATUS})
...
[Mar 4 15:10:16] -- Executing [1 at sin:7]
ChanIsAvail("IAX2/testlocal-14088", "SIP/sin10") in new stack
[Mar 4 15:10:16] -- Executing [1 at sin:8]
2004 Apr 04
1
How to improve this code?
Hi all,
I've got some functioning code that I've literally taken hours to
write. My 'R' coding is getting better...it used to take days :)
I know I've done a poor job of optimizing the code. In addition, I'm
missing an important step and don't know where to put it.
So, three questions:
1) I'd like the resulting output to be sorted on distance (ascending)
and
2018 May 14
1
Unable to build 'lld' on Mac OS 10.9
Hi All,
I am trying to build the 'lld' linker on Mac OS 10.9, but during the build, I am getting the errors. Following are the steps that I have followed:
1. I have downloaded the ‘llvm-stable’ source code from the following location:
https://github.com/llvm-mirror/llvm/tree/stable
2. Machine details(on which llvm source code isbeing built) are as follows:
$ sw_vers
2007 Oct 24
7
NameError in CustomersController#index
I''m new to Rails. I finished the Cookbook tut. no problem. I''m
trying to start a project of my own, follow the same instructions but
the difference is I created the database myself.
After I create the scaffolds and try them out I get this error
NameError in CustomersController#index
uninitialized constant Customer
RAILS_ROOT: ./script/../config/..
Application Trace |
2017 Oct 11
0
RFM analysis
Hi Hemant,
Let's take it one step at a time. Save this code as "qdrfm.R" in your
R working directory: It includes the comments I added last time and
fixes a bug in the recency scoring.
qdrfm<-function(x,rbreaks=3,fbreaks=3,mbreaks=3,
date.format="%Y-%m-%d",weights=c(1,1,1),finish=NA) {
# if no finish date is specified, use current date
if(is.na(finish))
2009 Mar 01
1
php agi and get_data errors.
Hallo,
I'm using a self-made script to get the code a user enters on my applications.
Sadly, the code doesn't work, i push the digits, but the result is
always an empty data.
(code=200, result=1, data= '').
Here is the code:
set_time_limit(99999999999999);
require('phpagi.php');
$agi = new AGI();
$agi->answer();
function printdebug($a) {
global $agi;