similar to: GoogleEarth

Hi Does anyone out there have GoogleEarth running on linux ? - I'm loathed to buy another pc and install windows on it for just one app, but its such a cool show that I may have to. So before I go and do that, I thought I might check out all possibilities of avoiding this unseemly (Bush sic?) reversification :-) Thanks. zc

I recently upgraded wine from 0.9.7 to 0.9.12 and while checking out that things were working I started up Google Earth but had the following error in terminal: Message from syslogd@TheVoid at Sun May 7 02:40:26 2006 ... TheVoid kernel: Bad page state at free_hot_cold_page (in process 'GoogleEarth.exe', page c125be60) Message from syslogd@TheVoid at Sun May 7 02:40:26 2006 ... TheVoid

Patches item #14375, was opened at 2007-10-02 13:12 You can respond by visiting: http://rubyforge.org/tracker/?func=detail&atid=220&aid=14375&group_id=35 Category: None Group: None Status: Open Resolution: None Priority: 3 Submitted By: Christopher Bludau (count_cb) Assigned to: Nobody (None) Summary: bigdemo/wxScrolledWindow - paint bug with scrolled window Initial Comment: I found

Hi all, I get two different results when using sum() and the switch na.rm. The result is correct when na.rm=FALSE. Linux Redhat 7.3, R version 1.6.1. I've had no luck searching the mail archives, so I was hoping somebody could explain/check this one for me. I will need to apply the function to missing data, simple as it is. Code: x<-matrix(runif(20,0,5)%/%1,4,5) # random matrix

Hi All, After a lengthy battle just to get the package installed, I am not able to actually use Rgraphviz to generate any plots. I tried just using the sample code in the documentation (http://www2.warwick.ac.uk/fac/sci/moac/people/students/peter_cock/r/rgraphviz/) and I get the following: *> > library(Rgraphviz) > test.matrix<-matrix(rep(c(0,1,0,0), 9), ncol=6, nrow=6) >

Hello, I am using the following code to create ppp files from csv data and map shape files, but I am getting some errors which I have been unable to fix by searching them online: library(spatstat) library(maps) library(maptools) NYC2<-readShapePoly("nybb.shp") # this is a map of the NYC boroughs without waterways and no census tract divisions (but it does include lines separating

DeaR comRades: I have a 2D spatial binomial process as shown in the data and code below. I am plotting the number of trials and the number of successes in the spatial binomial experiments and would like to draw the spatial cells were the trials and successes were counted, i.e. a partial grid in the plot only for those cells where there is a number. The cells are 2x2 km cells. The count of Trials

Hi, I noticed the following problem with xy.coords() in R 2.2.1-patched (version info at the foot of this email) and R 2.3.0 unstable (subversion no: r37123): > xy.coords(x = matrix(1:20, ncol = 2)) Error in xy.coords(x = matrix(1:20, ncol = 2)) : argument "y" is missing, with no default > xy.coords(x = matrix(1:20, ncol = 2), y = NULL) $x [1] 1 2 3 4 5 6 7 8 9

Dear, I am trying to visualise a time-progressing line (it's supposed to represent spread patterns) using brew package and Google Earth. The idea is to have a function which takes start and end point geographic coordinates, as well as number of intervals to chop the path up, and returns the collection of points segmenting this line. Unfortunately my calculations fail for large distances,

SUMMARY: Specific problem: I'm regridding biomass-burning emissions from a global/unprojected inventory to a regional projection (LCC over North America). I need to have boundaries for Canada, Mexico, and US (including US states), but also Caribbean and Atlantic nations (notably the Bahamas). I would also like to add Canadian provinces and Mexican states. How to put these together? General

What is plot.new? How can I fix this data or add plot.new so it works? > library(maps) > library(splancs) > area = 6*4 > lambda = 1.5 > N = rpois(1,lambda*area) > u = runif(N,-2,4) > v = runif(N,0,4) > plot(u,v,asp=1) > h = chull(u,v) > h = c(h,h[1]) > plot(u[h],v[h],"1",asp=1) Error in plot.xy(xy, type, ...) : invalid plot type '1' >

Hi, I am new to R and am a very basic user. I'm importing SHP files, adding plots of random locations within my polygon (these files have GPS data), and then want to save these plots (intact with added points) as KML files to look at in GoogleEarth (or possibly as SHP files which I can then convert into KML). This is as far as I've gotten (code below) and am lost as to next steps, Any

What is plot.new? and how can i get it to work so i can load other data? > library(splancs) > area = 6*4 > lambda = 1.5 > N = rpois(1,lambda*area) > u = runif(N,-2,4) > v = runif(N,0,4) > plot(u,v,asp=1) > h = chull(u,v) > h = c(h,h[1]) > plot(u[h],v[h],"1",asp=1) Error in plot.xy(xy, type, ...) : invalid plot type '1' >

Please bear with me for a really stupid question... I have a Radeon HD 4550 video card and currently run the Catalyst driver, fglrx_6_9_0-8.741-1. I use the "package managed" method for installing, allowing me keep track of what's what: [rj at madeleine ~]$ su Password: [root at madeleine rj]# grep fglrx /var/log/yum* /var/log/yum.log:May 20 12:37:07 Updated:

Dear all,   I have the following written example > coords <- "51°30'48.58\"N" > > as.integer(strsplit(coords, "°")[[1]][1]) [1] 51 > as.integer(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][1]) [1] 30 > as.numeric(strsplit(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][2],

Hello! My code below creates a data frame and a plot for it. However, I can't figure out how to add a legend that is not ON the plot itself, but outside of it (e.g., to the right of my graph or below it). I tried something: I put a line par(xpd=T, mar=par()$mar+c(0,0,0,4)) right before my plot command), but that screwed up all my gridlines - they covered all graph and do not coincide with

Hello, everybody! I have a code below that creates a data set and then a stacked bar chart based on that data set. No need to look at it - just notice please that my horizontal axis is a date varible (x=my.data$date). I have a question about the last 2 lines of this code: grid(nx=NULL,ny=NULL,col = "lightgray", lty = "dotted",lwd = par("lwd")) axis(1, las = 2) Could

Hello! The code below works - if you run it you'll see a stacked area chart generated based on the data example. I only have one understanding question about the legend location (the very last snippet of code): legend(par()$usr[2], mean(par()$usr[3:4]), rev(order.of.vars), xpd=T, bty="n", pch=15, col=all.colors[rev(order.of.colors)]) I see that par()$usr[2] = 14763.72

Hi, I read some posts from the mailing list on the same problem, but it seems that i still cannot solve this problem. I only want to generate some simulated data. #Generate 2500 observations-it works without errors > coords<-as.matrix(expand.grid(seq(0,100,length.out=50), seq(0,100,length.out=50))) #SimData is a user-written function > SimBinData<-SimData(n=2500,coords=coords,

The R-1.2.1 builds have gone fairly smoothly on most of my UNIX architectures, but there were many warnings reported by the picky SGI compiler that could be eliminated in future releases. Generally, I have found the SGI compilers very helpful in ferreting out portability problems, unused and/or obsolete variables, unexpected datatype coercions, etc., and they compile faster than any other