Displaying 20 results from an estimated 2000 matches similar to: "DID's Now Offering Romania Bucharest 4021+ and 4031+"
2006 Apr 12
1
DID'S Romania - Bucharest
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2006 May 28
3
Asterisk Radius Module
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2013 Sep 06
0
CentOS Dojo Bucharest, Romania Live Streams
hi Guys,
We are live streaming the Dojo sessions today ( thanks to hostway for
getting this up ).
The live streams will be at http://www.centos.org/media.html once the
sessinos start. The scheduled kick off is 10am localtime ( UTC +3 )
- KB
--
Karanbir Singh
+44-207-0999389 | http://www.karan.org/ | twitter.com/kbsingh
GnuPG Key : http://www.karan.org/publickey.asc
2006 Jan 08
0
DTMF relay problem
hey all,
I'm trying to double forward a DID , from PSTN to SIP DID then to my *.
Double forwarding my DID , but the Digits are not getting relayed correctly
... sending double digits and sometimes missing digits?
Is here anywhere I can put a delay on DTMF? Or a different solution for
this?
I use asterisk 1.2.1 , centos 4.2 , codec ulaw
Let me know oliver@wvg-tele.com
Oliver
World
2011 Dec 01
1
Can't get off Europe/Bucharest timezone
Hello Everyone,
The timezone is set correctly on the OS America/Toronto:
mv /etc/localtime /etc/localtime.bak
cp /usr/share/zoneinfo/America/Toronto /etc/localtime
I even tried adding the timezone setting to sip.conf:
timezone=America/Toronto
However. Asterisk wants to be in Bucharest? Thinking
about it, I want to be in Bucharest!
Cheers,
Nick.
2006 Jun 08
0
new DID's
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2006 Mar 04
1
What hardware to use for ISDN in Romania
Hello everyone.
My land-line provider (Romtelecom) has a very nice offer for ISDN. All in
all they offer me a digital land-line with 1 base number + 2 MSN's and that
would make a grate addition to my full-time home office.
Romtelecom say they're providing EURO-ISDN and the line is compatible with
any euro-isdn compliant equipment. They say they'll install a NT at my
office and this
2005 Jun 29
1
Romania metropolitan
OOPS <blush>
http://vcalinus.gemenii.ro/quaggarealms.html
is what should have been posted by me...
This deals with the metropolitan / other issues, I think. I can''t read
it...
--
gypsy
2006 Oct 03
0
Some help needed in Romania with some settings
Hi,
My name is Monenci Nicolae. I'm from Romania, an i have a problem that i
could not find any answer on net.
I have an "Samba version 3.013" instaled.
I have atach-ed the smb.conf that i have configured my self.
So my problem is:
I have a network of 10 PC. (5 windows XP, 2 windows 2000,
3 windows NT)
I have installed 1 new PC with windows XP.
After i installed
2020 Apr 13
3
detect ->
Using => and <= instead of -> and <- would make things easier, although the
precedence would be different.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Apr 13, 2020 at 1:43 AM Adrian Du?a <dusa.adrian at gmail.com> wrote:
> Thank you for your replies, this actually has little to do with the
> regular R code but more to signal what in my package QCA is referred
2016 Apr 12
3
formula argument evaluation
I have a simple function such as:
foo <- function(x) {
call <- lapply(match.call(), deparse)
testit <- capture.output(tryCatch(eval(x), error = function(e) e))
if (grepl("Error", testit)) {
return(call$x)
}
}
and I would like to detect a formula when x is not an object:
# this works
> foo(A + B)
[1] "A + B"
# but this doesn't
>
2016 Apr 12
2
formula argument evaluation
On Tue, Apr 12, 2016 at 2:08 PM, Duncan Murdoch <murdoch.duncan at gmail.com>
wrote:
> [...]
>
> It never gets to evaluating it. It is not a legal R statement, so the
parser signals an error.
> If you want to pass arbitrary strings to a function, you need to put them
in quotes.
I see. I thought it was parsed inside the function, but if it's parsed
before then quoting is the
2016 Apr 13
2
formula argument evaluation
I suppose it would work, although "=>" is rather a descriptive symbol and
less a function.
But choosing between quoting:
"A + B => C"
and a regular function:
A + B %=>% C
probably quoting is the most straightforward, as the result of the foo()
function has to be a string anyways (which is parsed by other functions).
On Tue, Apr 12, 2016 at 6:20 PM, Richard M.
2020 Apr 15
1
detect ->
You are right. >= is not as evocative as =>. Perhaps > and < would do?
%=>% and %<=% would work.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Wed, Apr 15, 2020 at 12:41 AM Adrian Du?a <dusa.adrian at gmail.com> wrote:
> Dear Bill,
>
> I already tried this, and it would have been great as (currently) the
> sufficiency relation is precisely
2020 Apr 13
3
detect ->
Adrian,
Indeed, this has come up in a few places, but as Gabor says, there is no
such thing as right hand assignment at any point after parsing is complete.
This means the only feasible way to detect it, which a few projects do I
believe, is process the code while it is still raw text, before it goes
into the parser, and have clever enough regular expressions.
The next question, then, is why
2016 Apr 12
0
formula argument evaluation
Would making it regular function %=>%, using "%" instead of quotes,
work for you?
On Tue, Apr 12, 2016 at 11:09 AM, Adrian Du?a <dusa.adrian at unibuc.ro> wrote:
> On Tue, Apr 12, 2016 at 2:08 PM, Duncan Murdoch <murdoch.duncan at gmail.com>
> wrote:
>> [...]
>>
>> It never gets to evaluating it. It is not a legal R statement, so the
> parser
2020 Apr 13
2
detect ->
I searched and tried for hours, to no avail although it looks simple.
(function(x) substitute(x))(A <- B)
#A <- B
(function(x) substitute(x))(A -> B)
# B <- A
In the first example, A occurs on the LHS, but in the second example A is somehow evaluated as if it occured on the RHS, despite my understanding that substitute() returns the unevaluated parse tree.
Is there any way, or is
2020 Apr 15
0
detect ->
Dear Bill,
I already tried this, and it would have been great as (currently) the sufficiency relation is precisely "=>"... but:
foo <- function(x) return(substitute(x))
foo(A => B)
Error: unexpected '>' in "foo(A =>"
It seems that "=>" is a syntactic error for the R parser, while "<=" is not because it denotes less than or
2004 May 27
4
extract columns using their names
Hello,
Is there a way to extract multiple columns from a dataframe using their
names instead of their numbers?
Currently I use:
data2 <- data1[, c(1,3,9)]
And I am looking for something like
data2 <- data1[, c("XX","YY","ZZ")]
I use the same dataframe for many purposes, and I run codes that change
the order of the columns every time.
Many thanks,
Adrian
2016 Apr 13
0
formula argument evaluation
%=>% would have precendence ('order of operations') problems also.
A + B %=>% C
is equivalent to
A + ( B %=>% C)
and I don't think that is what you want.
as.list(quote(A + B %=>% C)) shows the first branch in the parse tree. The
following function, str.language, shows the entire parse tree, as in
> str.language(quote(A + B %=>% C))
`quote(A + B %=>%