similar to: dtmf problem

Hi, I have two accounts with broadvoice. Now, I want to be able to distinguish between them. I though that this would be simple by adding "/EXTEN" at the end of the register statement. For example: register => num1:pass@sip.broadvoice.com/1000 Unfortunately, this is not working. When I call into my box I hear busy tone. My config looks like this: [root@voip asterisk]# cat sip.conf

Hi All, I have been trying to plot multiple line plots with different colors on one figure. in my example below I was able to plot cat vs num1 as a dot plot connected with lines but was not able to do that for cat vs num2 and I do not know how to add the third plot cat vs num3. below is my code df <- data.frame(cat=1:10, num1=rnorm(10), num2=rnorm(10), num3=rnorm(10)) plot(df$num1,

Hi I would like to normalize my data by one of the variables in long format. My data is like this: > t1<-data.frame(id=rep(1:3,rep(3,3)),dt=rep(1:3,rep(9,3)),var=c('num1','num2','norm'),value=rnorm(27)) > t1 id dt var value 1 1 1 num1 -1.83276256 2 1 1 num2 1.57034303 3 1 1 norm 0.60008563 4 2 1 num1 -0.96893477 5 2 1 num2 0.30423346 6

Hello, I have a list (mode and class are list) in R that is many elements long and of the form: >length(list) [1] 5778 >list[1:4] $ID1 [1] "num1" $ID2 [1] "num2" "num3" $ID3 [1] "num4" $ID4 [1] NA I'd like to convert the $ID2 value to be in one element rather than in two.?? It shows up as c(\"num2\", \"num3\") if I try to use

Hi, I am trying to simultaneously remove duplicate variables from two or more variables in a small R data.frame. I am trying to reproduce the SAS statements from a Proc Sort with Nodupkey for those familiar with SAS. Here's my example data : test <- read.csv("test.csv", sep=",", as.is=TRUE) > test date var1 var2 num1 num2 1 28/01/11 a 1 213 71 2

Dear Users, I have one problem here, I tried many time and even read a few notes on writing function but still..... Can anyone help me on how to simplify Part B (please refer the programming below), so that I don't have to repeat the calculation of "num" and "r" ? Thank you very much..every help is very much appreciated... ## Part A n=1400 m=matrix(c(0,0,0,0),4,1)

hi, running dovecot-0.99.10-rc2 on NetBSD, client is Entourage on MacOS 9.2. sylpheed on NetBSD does not show this behaviour. --snip-- Jun 23 16:28:15 host imap(user): file mail-index.c: line 619 (mail_index_lookup_uid_range): assertion failed: (first_uid > 0 && last_uid > 0) --snap-- any hints? thanks, TOM -------------- next part -------------- A non-text attachment was

I want to count attributes of IDs: --8<---------------cut here---------------start------------->8--- z <- data.frame(id=c(10,20,10,30,10,20), a1=c("a","b","a","c","b","b"), a2=c("x","y","x","z","z","y"),

Description: 'lapply' returns a list of the same length as 'X', each element of which is the result of applying 'FUN' to the corresponding element of 'X'. I expect that when I do > lapply(vec,f) f would be called _once_ for each component of vec. this is not what I see: parse.num <- function (s) { cat("parse.num1\n"); str(s) s

I believe this may be more related to analysis than it is to R, per se. Suppose I have the following function that I wish to integrate: ff <- function(x) pnorm((x - m)/sigma) * dnorm(x, observed, sigma) Then, given the parameters: mu <- 300 sigma <- 50 m <- 250 target <- 200 sigma_i <- 50 I can use the function integrate as: > integrate(ff, lower= -Inf, upper=target)

Hi all- I have a dataset (year, month, hour, co2(ppm), num1,num2) [49,] 2006 11 0 383.3709 28 28 [50,] 2006 11 1 383.3709 28 28 [51,] 2006 11 2 383.3709 28 28 [52,] 2006 11 3 383.3709 28 28 [53,] 2006 11 4 383.3709 28 28 [54,] 2006 11 5 383.3709 28 28 [55,] 2006 11 6 383.3709 28 28 [56,] 2006 11 7 383.3709 28 28 [57,] 2006

Hi! I have data (also in attached file) in the following form: num1 num2 num3 int1 fac1 fac2 cha1 cha2 Date POSIXt 1 1 f q 1900-01-01 1900-01-01 01:01:01 2 1.0 1316666.5 2 a g r z 1900-01-01 01:01:01 3 1.5 1188830.5 3 b h s y 1900-01-01 1900-01-01 01:01:01 4 2.0 1271846.3 4 c i t x 1900-01-01 1900-01-01 01:01:01 5 2.5 829737.4 d j u w 1900-01-01 6 3.0

Hi! I have data (also in attached file) in the following form: num1 num2 num3 int1 fac1 fac2 cha1 cha2 Date POSIXt 1 1 f q 1900-01-01 1900-01-01 01:01:01 2 1.0 1316666.5 2 a g r z 1900-01-01 01:01:01 3 1.5 1188830.5 3 b h s y 1900-01-01 1900-01-01 01:01:01 4 2.0 1271846.3 4 c i t x 1900-01-01 1900-01-01 01:01:01 5 2.5 829737.4 d j u w 1900-01-01 6 3.0

Hi all- I am wondering about using the mapply function to multiple data frames. Specifically, I would like to do a t-test on a subset of multiple data frames. All data frames have the same structure. Here is my code so far: f<-function(x,y) { test<-t.test(x$col1[x$col3=="num",],v$col2[x$col3=="num",],paired=T,alternative="greater") out<-test$p.value

Hi, I am looking for a way to read tables that have general structure of characterTag num1 num2 ... i.e. one character column followed by an unknown to the caller (but fixed throughout the file) number of numeric columns. I wanted to improve the speed of read.table by using colClasses, but that seemed to require knowledge of the actual number of columns in the file. For example I tried

hi, To post, and to reply to a post, i have to goto my email. Now, if there is a web interface to these mailing list, things would be easier.

Hello, I've got a data frame with a mix of numeric, integer and factor columns. I'd like to pull out (or just operate only on) the numeric/integer columns. Every thing I've found in searches is about how to subset by rows, or how to operate assuming you have the column names.  I'd like to pull by type. Thanks! Barry [[alternative HTML version deleted]]

Currently as the first column in a data frame I have string values in the format xx_yy - I want to create a new column with just the substring xx (for each row in turn). Three possible ways to do this might be (1) split the string by '_' using strsplit and paste the first of the resulting variables into a new column, but I have been unable to do this for each row of my data frame in turn

Thanks to the R creators for such a great statistical system. Thanks to the R help list, I have (finally) gotten far enough in R to have a question I hope to be worth posting. I'm using the recode function from John Fox's car package and have encountered some unexpected behavior. Consider the following example: ## Begin cut-and-paste example require( car ) set.seed(12345) nn <-

Hello everyone... I would like to create a chart (see below), how can I do it with R? Any help, suggestion, samples... will be greatly appreciated. Thanks... Avi http://r.789695.n4.nabble.com/file/n2545921/DotChart.jpg -- View this message in context: http://r.789695.n4.nabble.com/Create-Dot-Chart-tp2545921p2545921.html Sent from the R help mailing list archive at Nabble.com.