similar to: FW: rsa_public_encrypt() exponent too small or not odd

I am attempting to deploy OpenSSH. The trouble is I keep getting the rsa_public_encrypt() exponent too small or not odd with the SSH 1 or 1.5 protocols. I can't get OpenSSH to communicate with itself with any protocal other than SSH 2. Platform notes: HP-UX 11.00 Dart 51 64bit OpenSSL 0.9.6 Zlib 1.1.3 Cflags: -Ae I have tried with and without optimizations. I noticed that this problem

Hello, I have compiled OpenSSL-0.9.7d - the lastest version and when OpenSSH-3.7.1p2 is compiled with this ssl library [0.9.7d], I am getting the following error when SSH-1 connection is done. I am using HP-UX IPF box and I am doing 32 bit compilation only. Even I have changed the optimization level for OpenSSL and no use. Any clue why this problem is occuring? Advance thanks, Kumaresh

We are in the process of converting over to openssh at UNC. I've built openssh 2.20p1 for all supported platforms at UNC: AIX 4.3 AIX 4.2 Linux 2.2 Solaris 2.7 Solaris 2.6 SGI 6.5 We been running for about a month now and have only one reported problem--which came up today: When running ssh on a machine running SGI 6.5 you get the following error: %ssh overlord rsa_public_encrypt()

Hello, I tried building OpenSSH-2.9p1 on AIX 4.3.3(ML6) with gcc. I included the --with-tcp-wrappers flag in configure. Configure went just fine, make went just fine, but 'make install' failed with the following error: exec(): 0509-036 Cannot load program ./ssh-keygen because of the following errors: 0509-130 Symbol resolution failed for /usr/local/lib/libwrap.a(libwrap.so)

I have a local library with functions that interrogates an institution-specific web API, so is not of interest to anyone outside of Mayo. For some reason the R CMD INSTALL command fails. See below: Build the library, then install it. tmt-local2127% R CMD build dart * checking for file ?dart/DESCRIPTION? ... OK * preparing ?dart?: * checking DESCRIPTION meta-information ... OK * installing

It's hard to diagnose this without your package sources / a reproducible example. Shot in the dark: one thing worth checking is that you don't have an entry in your `.Rbuildignore` that's removing files you don't expect it to (maybe that's causing R to strip out the 'doc/index.html' file) Kevin On Fri, May 15, 2015 at 12:54 PM, Therneau, Terry M., Ph.D. <therneau

I know this is off-topic to the list, but someone asked me to make the information that I garnered about Dell Poweredge systems available to the list. So, here it is. Basically, after a search on dejanews, I came across this article: http://x5.dejanews.com/getdoc.xp?AN=430135686&CONTEXT=917266543.1696071777&hitnum=19 In it, someone states that there are drivers for the PERC RAID

I am getting failure of build and check, for an Rd file that has a long argument list. Guess diagnosis: a quoted string beyond a certain point in the argument list is fatal. Example: Use the function below, create an Rd file for it with prompt(). Move the .Rd file to the man directory (no need to edit it) and try building dart.control <- function(server=c("production",

Hello, I'm using the fArma package to estimate Hurst exponent by R/S method. I've some measurements in the following format: Call_number Call_duration I'm using the following steps. Am new to R, so it would help if someone could please confirm if my steps are correct. Further, this method seems to give a value H ~= 0.8 (> 0.5). Is the use of R/S method to estimate H OK? >

Hello, I'm using fArma package to estimate the value of Hurst exponent using R/S method. However, for a certain set of data I get H ~ 1.8. How do I interpret this? Following are the output that I get for this set: > mean(data[,2]) [1] 400.5433 > sd(data[,2]) [1] 1139.786 > > rsFit(data[,2], levels = 64) Title: Hurst Exponent from R/S Method Call: rsFit(x = data[, 2], levels

Dear R users, The function lmacfPlot( ) in fBasics, returns a list including the Hurst Exponent. I get sometimes a value for Hurst Exponent using lmacfPlot bigger than 1 which is theoretically incorrect. What could be reason ? From the related documents, I could not find how the Hurst Exponent in lmacfPlot is estimated. Could you please say how it is estimated here? Thank you so

Hello... to openssh-unix-dev at mindrot.org cc djm at ibs.com.au devel platform: linux intel redhat 6.2beta http://violet.ibs.com.au/openssh/files/openssh-1.2.2.tar.gz from rpm at same. I am NOT subscribed to the openssh-unix-dev list. I ran into a problem using openssh-1.2.2 with openssl-0.9.5. With openssl 0.9.5 you can now compile shared libraries without idea, rc5 and rsa. openssl

What field is httr in the DESCRIPTION? Hadley On Thu, Jul 9, 2015 at 10:26 AM, Therneau, Terry M., Ph.D. <therneau at mayo.edu> wrote: > I have a local library 'dart' that imports "httr". It has routines that > access central patient data such as birth date, so it is heavily used > locally but of no interest to anyone else. > > The httr library (and 300

Dear All, I am a novice when it comes to time-series analysis and at the moment I am actually interested in calculating the Hurst exponent of a time series. This question has already been asked quite some time ago http://bit.ly/98dZsi and I trust some progress has been made ever since. I was able to find some functions in the packages http://cran.r-project.org/web/packages/Rwave/index.html

I have a local library 'dart' that imports "httr". It has routines that access central patient data such as birth date, so it is heavily used locally but of no interest to anyone else. The httr library (and 300 others) are in a shared directory, referenced by everyone in the biostatistics group via adding this location to the .libPaths in their default .Rprofile.

Dear R experts, I really have difficulty when I try to deal with this question. suppose X is a square symmetric matrix. The exponent of X is defined by the matrix limit as following: exp(X) = lim (I + X/n)^n, note: the limit is from n to infinite. How can I write R function for the above? Thank you very much -- View this message in context:

I'm trying to make a function that will output the exponent... so f2(2,2) = 4 and f2(2,3)=8. But I don't want to just use the x^n function, I want to do it another way, and without a recursion. I did the follow code but for some reason it doesn't work. Help please? f2 <- function(x, n) #without recursion { y <- 1 if (n==0) {return(1)} else { if (length(y) < (n+1) { y

If you think this message is more appropriate for samba-technical, let me know. I thought I'd try the general list first. I recently replaced a Novell Netware file/print server with Redhat Linux 6.1(Kernel 2.2.12) running Samba 2.0.5a-12 installed from the RPMS on the Redhat disc. The clients are all Windows 95 workstations. Everything works wonderfully...except... My client is a law firm

Dear all, I would like to (i) produce boxplot graphs with axis in logarithm in base 10 and (ii) showing the values on the axis in 10^exponent format rather than 10E+exponent. To illustrate with an example, I have some widely spread data that I chart plot using boxplot() [figure on the left]; the log="y" option of boxplot() I obtained the natural logarithm conversion of the data and

Dear all, Has anyone worked on coding for calculating Lyapunov Exponent for a time series data? or any package is available for computing Lyapunov? Please advice and many thanks in advance. Catherine X Wang