similar to: [Bug 1649] New: CreateObject : Mismatch auth between pubkey and password

http://bugzilla.mindrot.org/show_bug.cgi?id=937 Summary: ssh2 pubkey auth broken by user:style syntax Product: Portable OpenSSH Version: -current Platform: All OS/Version: OpenBSD Status: NEW Severity: normal Priority: P2 Component: sshd AssignedTo: openssh-bugs at mindrot.org ReportedBy:

-----BEGIN PGP SIGNED MESSAGE----- Hash: RIPEMD160 hi all, i have two OSX boxes set up for ssh via pubkey auth only. i'm setting up rsync comms for the first time. i have rsyncd running on box A. no-auth rsync from box B to/from box A's rsyncd works as expected. rsync@B to/from rsyncd@A using pubkey-auth'd-ssh trasport: rsync --verbose --stats --recursive -e "ssh -F

I'm running a Debian VPS that was originally configured with OpenSSH 5.5 and I could use pubkey auth without issue. A few days ago, I decided to compile and install OpenSSH 6.2 for the AES-GCM support, and now I cannot login to my server with pubkey auth. I can't seem to figure out what the problem is, and when I replace the new sshd with the one originally included with my server, it

I have sshd server sshd -V ... OpenSSH_6.7p1, OpenSSL 1.0.1j 15 Oct 2014 ... running on linux/64 with cat sshd_config ... PubkeyAuthentication yes PasswordAuthentication no ChallengeResponseAuthentication no

Hello ml, i've set up a ssh server with public-key authentication. But soon i realized that wrong pubkey authentications are not shown in the logs. So i wrote a small patch for monitor.c included as attachement. patch against 3.8.1p1 $ patch -p0 < /path/to/keyauth-loggin.patch Kindly regards, Jan Gehring

https://bugzilla.mindrot.org/show_bug.cgi?id=937 Patric Stout <patric.stout at gmail.com> changed: What |Removed |Added ---------------------------------------------------------------------------- CC| |patric.stout at gmail.com --- Comment #1 from Patric Stout <patric.stout at gmail.com> 2011-09-10

https://bugzilla.mindrot.org/show_bug.cgi?id=1526 Summary: SSH key prompt if public key missing and pubkey auth fails Product: Portable OpenSSH Version: 5.1p1 Platform: Other OS/Version: Mac OS X Status: NEW Severity: normal Priority: P4 Component: ssh-agent AssignedTo:

https://bugzilla.mindrot.org/show_bug.cgi?id=2678 Bug ID: 2678 Summary: PubKey Authentication fails when more than one user/group ACL is set on any Path component to authorized_keys Product: Portable OpenSSH Version: 5.3p1 Hardware: amd64 OS: Linux Status: NEW

https://bugzilla.mindrot.org/show_bug.cgi?id=2082 Bug ID: 2082 Summary: Please add pubkey fingerprint to authentication log message Classification: Unclassified Product: Portable OpenSSH Version: 6.2p1 Hardware: All OS: All Status: NEW Severity: enhancement Priority: P5

I am trying to use F-Secure SSH on a RH7.1 machine to connect using any pubkey method to an OpenSSH on a Debian 'woody' stable server (with current Debian security patches). Interactive password authentication works. But I have been unable to get any of the "passwordless" pubkey methods to work. I am trying to automate a copy where only ssh is allowed through the firewalls.

https://bugzilla.mindrot.org/show_bug.cgi?id=1523 Summary: Log public key identifier on pubkey login Product: Portable OpenSSH Version: 5.1p1 Platform: All OS/Version: All Status: NEW Severity: enhancement Priority: P2 Component: sshd AssignedTo: unassigned-bugs at mindrot.org ReportedBy:

Hi, first of: my familiarity with OpenSSH/Pam code-base is very limited.. Please excuse me if some of this does not make any sense or seems stupid! I'm investigating if it is possible for a PAM module to find out which public key was accepted (when 'AuthenticationMethods publickey,keyboard-interactive' is used). From my digging in the source, it seems it is currently not. Would

On Thu, Dec 18, 2014 at 2:01 AM, Damien Miller <...> wrote: > On Wed, 17 Dec 2014, Dmt Ops wrote: > >> vi /etc/ssh/sshd_config >> ... >> - ChallengeResponseAuthentication no >> + ChallengeResponseAuthentication yes >> + KbdInteractiveAuthentication yes >>

Hi. The error message 'AuthorizedKeyCommandUser \"%s\" not found' in user_key_command_allowed2() should inform about non-existing username, not about command. --- auth2-pubkey.c 14 Nov 2012 08:04:02 -0000 1.36 +++ auth2-pubkey.c 14 Feb 2013 16:50:04 -0000 @@ -480,7 +480,7 @@ pw = getpwnam(username); if (pw == NULL) { error("AuthorizedKeyCommandUser

HD Moore from MetaSploit has noted that, given a pubkey (and not the corresponding private key, as might be found in authorized_keys), he can determine if he'd be able to log into an account. It's a small thing, but he's using it for very interesting recon/deanonymization. He'll be releasing a paper shortly, not overplaying the characteristic, but certainly showing it can be used

The patch to enable FIPS mode for openssh 6.0p1 missed two instances of the ssh client trying to use MD5. It causes pubkey-based authentication to fail in FIPS mode. I have copied the missing changes from auth2-pubkey.c into sshconnect2.c. Here is a patch: diff -cr openssh-6.0p1/sshconnect2.c openssh-6.0p1-patched/sshconnect2.c *** openssh-6.0p1/sshconnect2.c Sun May 29 07:42:34 2011 ---

http://bugzilla.mindrot.org/show_bug.cgi?id=1011 Summary: Multiple log entries for successful pubkey authentication Product: Portable OpenSSH Version: 4.0p1 Platform: All OS/Version: All Status: NEW Severity: normal Priority: P2 Component: sshd AssignedTo: openssh-bugs at

can someone confirm this: http://bugzilla.mindrot.org/show_bug.cgi?id=29 Authentication refused: realpath /home/user/.ssh/authorized_keys failed: The file access permissions do not allow the specified action.

https://bugzilla.mindrot.org/show_bug.cgi?id=937 Damien Miller <djm at mindrot.org> changed: What |Removed |Added ---------------------------------------------------------------------------- Status|RESOLVED |CLOSED --- Comment #5 from Damien Miller <djm at mindrot.org> --- Set all RESOLVED bugs to CLOSED with release

hi guys... I need your help to make a simple program made on visual basic 6.0 to connect to a database using an string connection. Not ODBC! Please I'ld appreciate your help.