Displaying 20 results from an estimated 10000 matches similar to: "[Bug 943] sftp will not send from a named pipe"
2005 Nov 05
1
[Bug 943] sftp will not send from a named pipe
http://bugzilla.mindrot.org/show_bug.cgi?id=943
djm at mindrot.org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|REOPENED |RESOLVED
Resolution| |WONTFIX
------- Comment #4 from djm at mindrot.org 2005-11-06 03:53 -------
2007 Jun 22
4
[Bug 943] sftp will not send from a named pipe
http://bugzilla.mindrot.org/show_bug.cgi?id=943
Damien Miller <djm at mindrot.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|REOPENED |RESOLVED
Resolution| |WONTFIX
CC| |djm
2005 Apr 21
1
[Bug 943] sftp will not send from a named pipe
http://bugzilla.mindrot.org/show_bug.cgi?id=943
djm at mindrot.org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|NEW |RESOLVED
Resolution| |WONTFIX
------- Additional Comments From djm at mindrot.org 2005-04-21 18:34
2004 Dec 06
0
[Bug 943] sftp will not send from a named pipe
http://bugzilla.mindrot.org/show_bug.cgi?id=943
------- Additional Comments From djm at mindrot.org 2004-12-06 17:22 -------
Created an attachment (id=747)
--> (http://bugzilla.mindrot.org/attachment.cgi?id=747&action=view)
allow upload/download from fifo
This is one of those cases where the correct behaviour isn't immediately
obvious: I'm not sure that sftp should try to
2019 Jun 22
2
sftp client: upload from pipe
Damien Miller wrote:
> IIRC it's there because reads on named pipes can hang if nothing is
> attached to them
And what is the problem with that? It should break nothing if this named
pipe was passed to sftp explicitly (I'm not talking about recursively
uploading of directory that contains named pipes). Besides, there is
O_NONBLOCK if it would be very necessary.
> and because
2013 Apr 30
1
ADF test --time series
Hi all,
I was running the adf test in R.
CODE 1:
adf.test(data$LOSS)
Augmented Dickey-Fuller Test
data: data$LOSS
Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775
alternative hypothesis: stationary
CODE 2:
adf.test(diff(diff(data$LOSS)))
Augmented Dickey-Fuller Test
data: diff(diff(data$LOSS))
Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01
alternative
2010 Oct 29
3
Dickey Fuller Test
Dear Users, please help with the following DF test:
=====
library(tseries)
library(timeSeries)
Y=c(3519,3803,4332,4251,4661,4811,4448,4451,4343,4067,4001,3934,3652,3768
,4082,4101,4628,4898,4476,4728,4458,4004,4095,4056,3641,3966,4417,4367
,4821,5190,4638,4904,4528,4383,4339,4327,3856,4072,4563,4561,4984,5316
,4843,5383,4889,4681,4466,4463,4217,4322,4779,4988,5383,5591,5322,5404
2007 Dec 08
2
time series tests
Hi all,
Can anyone clear my doubts about what conclusions to take with the following what puts of some time series tests:
> adf.test(melbmax)
Augmented Dickey-Fuller Test
data: melbmax
Dickey-Fuller = -5.4075, Lag order = 15, p-value = 0.01
alternative hypothesis: stationary
Warning message:
p-value smaller than printed p-value in: adf.test(melbmax)
2013 Jun 23
1
Scaling Statistical
Short question: Is it possible to use statistical tests, like the Augmented
Dickey-Fuller test, in functions with for-loops? If not, are there any
alternative ways to scale measures?
Detailed explanation: I am working with time-series, and I want to flag
curves that are not stationary and which display pulses, trends, or level
shifts.
>df
DATE ID VALUE2012-03-06 1
2009 Mar 24
0
Unit root
I am confused by obtaining different results when testing for unit root when using different packages. I have 2625 price entries for which I want to determine whether they exhibit unit root. First I test using adf.test from tseries package by running:
> adf.test(P, k=30)
Augmented Dickey-Fuller Test
data: P
Dickey-Fuller = -4.685, Lag order = 30, p-value = 0.01
alternative hypothesis:
2005 Feb 17
1
SFTP batch mode patch
Hi,
We do a lot of automated file transfers with SFTP, and found this small
patch very helpful. The main effect is to tell the underlying SSH client
that it's operating in batch mode. Patch is against 3.9p1.
Thanks,
Jeremy Monin
Sysadmin and open-source developer
diff -ur openssh-3.9p1-orig\sftp.c openssh-3.9p1\sftp.c
--- openssh-3.9p1-orig\sftp.c Sat Jul 17 02:12:08 2004
+++
2009 May 15
1
Dickey-Fuller Tests with no constant and no trend
R has a Dickey-Fuller Test implementation (adf.test) that tests for unit
roots in an autoregressive process with a constant and linear trend. Is
there a DF implementation that doesn't use the constant or trend?
Thanks,
Jake.
--
View this message in context: http://www.nabble.com/Dickey-Fuller-Tests-with-no-constant-and-no-trend-tp23565210p23565210.html
Sent from the R help mailing list
2017 Dec 19
0
kernel: blk_cloned_rq_check_limits: over max segments limit., Device Mapper Multipath, iBFT, iSCSI COMSTAR
Hi,
WARNING: Long post ahead
I have an issue when starting multipathd. The kernel complains about "blk_cloned_rq_check_limits:
over max segments limit".
The server in question is configured for KVM hosting. It boots via iBFT to an iSCSI volume. Target
is COMSTAR and underlying that is a ZFS volume (100GB). The server also has two infiniband cards
providing four (4) more paths over SRP
2016 Jan 15
0
JDataFrame API
> On Jan 15, 2016, at 12:35 PM, Thomas Fuller <thomas.fuller at coherentlogic.com> wrote:
>
> Hi Simon,
>
> Thanks for your feedback. -- this is an observation that I wasn't
> considering when I wrote this mainly because I am, in fact, working
> with rather small data sets. BTW: There is code there, it's under the
> bitbucket link -- here's the direct
2006 Apr 06
1
How to implement an iterative unit root test
Hello,
How can an interative unit root test be implemented in R?
More specifically, given a time series, I wish to perform the Dickey
Fuller Test on a daily basis for say the last 100 observations. It would
be interative in the sense that this test would be repeated each day for
the last 100 observations.
Given the daily Dickey Fuller estimates of delta for the autoregressive
process
d(Y(t))
2009 May 08
2
Override sip.conf settings in extensions.conf? Possible?
Hi all...
Does anyone know if it is possible to override sip.conf settings in extensions.conf
(for example: session-minse=90) without needing to create an overarching peer in sip.conf
and selecting it specifically in the dial plan?
I'm on the 1.4 stable code base and looking to implement session-timers on certain call
flows in a modular dial plan.
Thanks,
Josh Fuller josh.fuller at
2010 Nov 12
1
Problem with TC
I''m trying to use the traffic control features of Shorewall. I share
my network with some guys, and I have a tcclasses file like this:
#Hunter Fuller
eth0 100 1500kbit full 50
tos-maximize-throughput
#(other guy''s name)
eth0 110 1500kbit full 50
tos-minimize-delay
etc., based on their personal preferences.
Then
2014 Dec 07
4
syslinux 6.03 does not boot some kernels
>Date: Sat, 6 Dec 2014 09:12:19 -0500
>From: Gene Cumm <gene.cumm at gmail.com>
>To: Ady <ady-sf at hotmail.com>
>Subject: Re: [syslinux] syslinux 6.03 does not boot some kernels
>
>On Fri, Dec 5, 2014 at 9:51 AM, Ady <ady-sf at hotmail.com> wrote:
>>
>> It sounds as if syslinux.efi 6.03 is only capable of booting a Linux
>> kernel 3.3+ with an
2019 Jun 21
2
sftp client: upload from pipe
Hi,
the sftp client from openssh package can't upload data from local pipe
to remote file. For example, such a command fails:
$ cat file | sftp -b <(echo 'put /dev/stdin /directory/filename') -i ~/.ssh/key user at remote.host
sftp> put /dev/stdin /directory/filename
/dev/stdin is not a regular file
What is a purpose for such a behaviour and limitation? As experiment,
I removed
2007 Aug 16
2
ADF test
Hi all,
Hope you people do not feel irritated for repeatedly sending mail on Time series.
Here I got another problem on the same, and hope I would get some answer from you.
I have following dataset:
data[,1]
[1] 4.96 4.95 4.96 4.96 4.97 4.97 4.97 4.97 4.97 4.98 4.98 4.98 4.98 4.98 4.99 4.99 5.00 5.01
[19] 5.01 5.00 5.01 5.01 5.01 5.01 5.02 5.01 5.02 5.02 5.03 5.03 5.03