similar to: splash screen

Dear List, Suppose we have a variable K.JUN defined as (with 1=wet, 0=dry): K.JUN1984 = c(1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1) K.JUN1985 = c(0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1) K.JUN1986 = c(0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1)

Hello, Currently using a freely available MS Windows file system driver, Ext2Fsd, to communicate (read/write) with external media formatted EXT3 (Linux volume) from within MS Windows. Curious to know if Samba is able to support communication (read/write) with external media formatted EXT3 (Linux volume) from within the MS Windows environment? Looking forward to your reply. Thanks. Best,

I think need to do something like this: dat<-data.frame(state=sample(id=rep(1:5,each=200),1:3, 1000, replace=T,prob=c(0.7,0.05,0.25)),V1=runif(1,10,1000),V2=rnorm(1000)) rle.dat<-rle(dat$state) temp<-1 out<-data.frame(id=1:length(rle.dat$length)) for(i in 1:length(rle.dat$length)){ temp2<-temp+rle.dat$length[[i]] out$V1[i]<-mean(dat$V1[temp:temp2])

why? > rle Run Length Encoding lengths: int [1:1650061] 2 2 8 2 4 5 6 3 26 46 ... values : chr [1:1650061] "4bbf9e94cbceb70c BG bg" "4fbbf2c67e0fb867 SK sk" ... > as.data.frame(rle) Error in as.data.frame.default(vertices.rle) : cannot coerce class '"rle"' into a data.frame it seems that rle.df <-

I want to make a histogram from the lengths vector which is part of the output of rle. But I don't know how to access that vector so that I use it as an argument of hist(). What argument must I use so that I use the lengths vector as an input to hist()? Example output is: Run Length Encoding lengths: int [1:4] 1 2 3 3 values : num [1:4] -1 1 -1 1 A printout of the function rle() may

Hello there R-help, I'm not sure if this should be posted here - so apologies if this is the case. I've found a problem while using rle and am proposing a solution to the issue. Description: I ran into a niggle with rle today when working with vectors with NA values (using R 2.31.0 on Windows 7 x64). It transpires that a run of NA values is not encoded in the same way as a run of other

Hallo, I have an other problem, I have this vector signData with an alternation of 1 and -1 that corrispond to the duration of two different percepts. I extracted the durations like this: signData<- scan("dataTR10.txt") dur<-rle(signData)$length Now I would like to extract only the positive duration, e.g. signData <- c(1,1,1,1,-1,-1,-1,1,1,-1,-1) posduration <- c(4,2) I

Dear R Community - I hope you might be able to provide some guidance regarding the use of the rle function. I have a set of time-series data where a measured value is recorded every 30 seconds after the start of an experiment. Many of the measured values repeat and I am interested only in the values when there is a change. If I turn the measured values into a vector, the rle function works

Hi group, This is how my test file looks like: Chr start end sample1 sample2 chr2 9896633 9896683 0 0 chr2 9896639 9896690 0 0 chr2 14314039 14314098 0 -0.35 chr2 14404467 14404502 0 -0.35 chr2 14421718 14421777 -0.43 -0.35 chr2 16031710 16031769 -0.43 -0.35 chr2 16036178 16036237 -0.43 -0.35 chr2 16048665 16048724 -0.43 -0.35 chr2 37491676 37491735 0 0 chr2 37702947 37703009 0 0

Hi All, A twitter user, Mike fc (@coolbutuseless) mentioned today that he was surprised that repeated NAs weren't treated as a run by the rle function. Now I know why they are not. NAs represent values which could be the same or different from eachother if they were known, so from a purely conceptual standpoint there is no way to tell whether they are the same and thus constitute a run or

Hi, Do you have instructions on how to create my own Graphical Splash Screen for use with SysLinux? -- Peace and Long Life, Matt

I suppose it could be possible to patent something and let the patent expire so that it is registered at the patent office but not enforcable. No one else could patent it then. I get curious about the RLE patent. I heard Someone has a patent on run length encoding and I wonder how long they have had it because I remember RLE code running on a sinclair spectrum in the 80's before the whole

Hi, I'm relatively new to R, so I don't know the full list of base (or popular add-on packages) functions and tools available. For example, I tripped across mention of rle() in a message about some other problem. rle() turned out to be a handy shortcut to splitting some of my data by magnitude (vaguely like a sequence-based histogram). So I thought I'd ask: what small, or

Full_Name: Jeff Hallman Version: 1.2.2 OS: Solaris Submission from: (NULL) (132.200.32.33) > rle(c(1, NA, 1) $lengths [1] 3 $values [1] 1 should be as in Splus: $lengths [1] 1 1 1 $values [1] 1 NA 1 The Splus implementation (which works fine in R) is: rle <- function(x){ if(!is.atomic(x)) stop("Argument must have an atomic mode") if(length(x) == 0)

Dear all, I would like to task you if you know a rle version that can work also in a non consecutive way too. B.R Alex [[alternative HTML version deleted]]

getnybble() needs to return four bits at a time from every byte. During rle decode, rows are rounded to an integer number of bytes. The rle length needs to be able to hold values > 255. Signed-off-by: Chas Williams <3chas3 at gmail.com> --- core/graphics.c | 35 +++++++++++++++++++++-------------- 1 file changed, 21 insertions(+), 14 deletions(-) diff --git a/core/graphics.c

Dear R-users, Say that I have a sequence of zeroes and ones: x <- c(1,1,1,0,0,0,0,1,1,1,0,0,0,0,1,1,1,0,0,0,0) The sequences of ones represent segments and I want to report the starting and endpoints of these segments. For example, in 'x', the first segment starts at location 1 and ends at 3, and the second segment starts at location 8 and ends at location 10. Is there an efficient

Hello everybody, I have problem with a lapply command, which rather proves that I don't fully understand it. I want to extract from a list that consists of dataframes, the length of the first sequences from a given variable (its part of a simulation exercises). Below is code which does the job, but I think it should be possible to make it more compact. ### Example Data dat <-list()

I'm running rle() on a long vector, and get a result which looks like > uc Run Length Encoding lengths: int [1:16753] 1 1 1 1 1 1 1 1 1 1 ... values : int [1:16753] 29462748 22596107 18322820 14323315 12684505 9909036 7296916 6857692 5884755 5883697 ... I can print uc$names or uc$levels separately. Is there any way to print them together as tuples, looking like (29462748, 1)

Dear List, I have a series of dates and I am needing to know the greatest length of continuous dates - i.e. the number of dates before a break in the series.? For example, below there are three continuous series of dates with lengths 4, 6, and 8.? How can I count the number of continuous dates?? rle() will do it for constant integers, but I can't figure a way to modify it for continuous