similar to: Calculate the difference using ave

Displaying 20 results from an estimated 3000 matches similar to: "Calculate the difference using ave"

2009 Jul 13
1
Times series adjustment
Dear all, I want make correction depth of a bathymetric data set. To do so, I have the depth data set sample every second (a depth at each second) in one hand, and in the other hand, I have a tide variation level data set sample every 250 ms. The time register in each data sets (tide and bathymetric) is express in seconds followinf this format : hh:mm:ss.ss I would like to rectify the depth
2007 May 01
2
Polar graph of time and tide
I have been trying to visualize times of lowest tides, month by month. I have tide predictions with times either in unix time or a text format, and heights in feet or meters. I had been able to derive the clock times of each prediction. I would now like to graph this data with points showing heights as "r" and times as "theta", from 0000 to 2355. There is a seasonal
2012 Mar 28
3
Urgent - I really need some help lme4 model avg Estimates
Hello all, If someone could take a little time to help me then I would be very grateful. I studied piping plovers last summer. I watched each chick within a brood for 5 minutes and recorded behaviour, habitat use and foraging rate. There were two Sites, the first with 4 broods and the second with 3 broods. http://r.789695.n4.nabble.com/file/n4511178/Table_PP_Maslo_et_al.png As the data within a
2018 Mar 22
1
Calculate weighted proportions for several factors at once
Hi, I have a grouped data set and would like to calculate weighted proportions for a large number of factor variables within each group member. Rather than using dplyr::count() on each of these factors individually, the idea would be to do it for all factors at once. Does anyone know how this would work? Here is a reproducible example: ############################################################
2012 Mar 23
3
Using MuMIn - error message
Hello, I hope that you can bare with me. I am new to models, but I think I have a pretty godd understanding of how to run them now, including how to use AICc and Anova. The issue is that I have many factors that I wish to compare so doing each one at a time would take forever. I came across the MuMIn package and I was so excited, however I am getting an error message and i don't know why.
2011 Aug 18
2
Best way/practice to create a new data frame from two given ones with last column computed from the two data frames?
Dear expeRts, What is the best approach to create a third data frame from two given ones, when the new/third data frame has last column computed from the last columns of the two given data frames? ## Okay, sounds complicated, so here is an example. Assume we have the two data frames: df1 <- data.frame(Year=rep(2001:2010, each=2), Group=c("Group 1","Group 2"), Value=1:20)
2009 Sep 16
1
re-code missing value
Dear all, I have partial data set with four colums. First column is "site" with three factors (i.e., A, B, and C). From second to fourth columns (v1 ~ v3) are my observations. In the observations of the data set, "." indicates missing value. I replaced "." with NA. To replace "." with NA, I used two steps. First, I replaced "." with NA, and
2013 Feb 26
2
merging or joining 2 dataframes: merge, rbind.fill, etc.?
#I want to "merge" or "join" 2 dataframes (df1 & df2) into a 3rd (mydf). I want the 3rd dataframe to contain 1 row for each row in df1 & df2, and all the columns in both df1 & df2. The solution should "work" even if the 2 dataframes are identical, and even if the 2 dataframes do not have the same column names. The rbind.fill function seems to work. For
2009 Feb 10
1
aggregate taking way too long to count.
Folks, I'm checking the structure of a dataframe for duplicate parameters at a site station (i.e depth should be measured once, not twice), using aggregate to count each parameter within a site station. The fake data below has only 26000 rows, and takes roughly 14 seconds. My real data has 750000 rows and I had to stop execution after about an hour. The by() function is faster, but I
2017 Jul 13
2
about plotting a special case
Thanks, Jim. The code works, but I don't understand why you use q1090 <- quantile(DF1$B, probs=c()), rather than DF1$A? Also, how to add a legend for both points DF1 and DF2? On Wed, Jul 12, 2017 at 8:25 PM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > Here is the first plot: > > plot(DF1$A,DF1$B,pch=19,col="red") > meanA<-mean(DF1$A) >
2012 Jul 11
4
Help with loop
Hi, I have two dataframes: The first, df1, contains some missing data: cola colb colc cold cole 1 NA 5 9 NA 17 2 NA 6 NA 14 NA 3 3 NA 11 15 19 4 4 8 12 NA 20 The second, df2, contains the following: cola colb colc cold cole 1 1.4 0.8 0.02 1.6 0.6 I'm wanting all missing data in df1$cola to be replaced by the value of df2$cola.
2011 Nov 30
1
Replace columns in a data.frame randomly splitted
Dear community, I'm working with the data.frame attached ( http://r.789695.n4.nabble.com/file/n4122926/df1.xls df1.xls ), let's call it df1. I typed: df1<- read.xls("C:/... dir .../df1.xls",colNames= TRUE, rowNames= TRUE) Then I splited randomly df1 using splitdf function (http://gettinggeneticsdone.blogspot.com/2011/03/splitting- dataset-revisited-keeping.html)
2013 Jun 10
1
modify and append new rows to a data.frame using ddply
Hi, I have a data.frame that contains a variable act which records the duration (in seconds) of two states (wet-dry) for several individuals (identified by Ring) over a period of time. Since I want to work with daytime (i.e. from sunrise till sunset) and night time (i.e. from sunset till next sunrise), I have to split act from time[i] till sunset and from sunset until time[i+1], and from time[k]
2009 Dec 13
1
xtabs - missing combination
Dear list, I am trying to make a contingency table with xtabs but I am getting a 0 where I expect a 'NA'. Here is a simple example: options(stringsAsFactors = FALSE) rn <- LETTERS[1:4] df1 <- data.frame(r07 = rep(rn, each=4), r08 = rep(rn, 4), value = 1:16) xtabs(value ~ r07 + r08, df1) # Delete the combination [A, C] df1 <- df1[-3,] # Set 'value'
2024 Jun 15
2
code for year month day hr format
Thank you Rui. I ran the following script df1 <- read.table("solar_hour", header = TRUE) df1$date <- as.Date(paste(df1$year, df1$hour), format = "%Y %j", origin = "2012-08-01-0") df2 <- df1[c("date", "IMF", "SWS", "SSN", "Dst", "f10")] head(df1) #To display all the rows print(df2). It gave me this
2005 Jun 29
3
return NA
A<-c(1,2,NA,7,5) B<-c(3,4,1,4,1) C<-c(6,5,6,NA,9) D<-c(8,7,4,6,2) df1<-cbind(A,B,C,D) for(i in seq(1,ncol(df1)-1, by=2)) { ifelse(df1[,i]=="NA",df1[,i+1]=="NA",df1[,] ) } Tried several variations but none worked. I wish to find any NA's in column's 1 or 3 and change the numerical value to the right of the " NA"'s . In this case I
2010 Nov 19
3
Still confused with lapply
Hello, I would like to replace a for loop with lapply in order to speed up the treatment of my data (I've read lapply can help to do it). At the end of the message, you will find a simple example (function is more complex and data frames is more than 1 million of rows) of what I would like to do, that is applying the same calculation to all the rows of the data frame (knowing that I cannot
2007 May 05
1
loop in function
Dear Mailing-List, I think this is a newbie question. However, i would like to integrate a loop in the function below. So that the script calculates for each variable within the dataframe df1 the connecting data in df2. Actually it takes only the first row. I hope that's clear. My goal is to apply the function for each data in df1. Many thanks in advance. An example is as follows: df1
2016 Jun 23
2
Asignar a un dataframe un id de otro dataframe en función de intervalos con fechas
Hola a todxs, No encuentro la manera de hacer algo que aparentemente parece muy sencillo: Tengo dos dataframe, en el primero tengo una serie de códigos con hora de inicio y hora de fin y en el segundo otros códigos asociados a una hora; Lo que necesito es crear una nueva variable en el segundo data frame que indique a qué intervalo del primer data frame (df1$id) pertenece cada nivel del segundo
2011 May 12
2
Simple order() data frame question.
Clearly, I don't understand what order() is doing and as ususl the help for order seems to only confuse me more. For some reason I just don't follow the examples there. I must be missing something about the data frame sort there but what? I originally wanted to reverse-order my data frame df1 (see below) by aa (a factor) but since this was not working I decided to simplify and order by