similar to: How to delete rows using conditions on all columns

I have a data with the sequence of events with millions records and more than 24 time stamped variables. sample data: 1 2 3 4 5 6 7 8 9 10 A A A C C C B B D D D D D D D C C C C C B B A C A C C C D D I want to predict sequence for next 3 period. How this can be achieved using R. Is there any package/function in R do this. I have gone through the document for package "TraMineR" but not

Hi all, Here I am trying to implement the switch() function to choose value of a variable depending on the value of an input variable :   temp1 <- "1"               temp1.name <- switch(temp1,                                   1 == "aa",                                   2 == "bb",                                   3 == "cc",

Hi, I have a data.frame that is date ordered by row number - earliest date first and most current last. I want to create a couple of new columns that show the max and min values from other columns *so far* - not for the whole data.frame. It seems this sort of question is really coming from my lack of understanding about how R intends me to limit myself to portions of a data.frame. I get the

this is a bad question but I can't figure it out and i've tried. if i sort the 2 column matrix , temp1, by the first column, then things work as expected. But, if I sort the 1 column matrix, temp2, then it gets turned coerced to a vector. I realize that I need to use drop=FALSE but i've put it in a few different places with no success. Thanks. temp1 <-

i'm sorry. i had an error in my previous code because i left out a letter in the rownames. while fixing that, i also found a solution. so i'm sorry for the confusion. below is my fix. temp2 <- matrix(rnorm(10),nc=1,nrow=10) rownames(temp2) <-

Hi, I'm not a member of the list, but I think I've run across a (minor) bug. The rsync web page directed me to this list for bug reports. Anyway, I've described it below (including a simple test case with exact commands to reproduce and the output I get from those commands). I hope this helps. Let me know if any more information is needed. Elijah P.S. If it isn't a bug,

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

Hello, I am hoping someone can help tackle the problem below, for which I require a fast solution. It feels like there should be an elegant approach, but I am drawing blanks. Take a vector 'x' with random values > 0: x = runif(10,1,5) Assume some reasonably small positive value 'delta': delta = 0.75 The task is to find a solution vector 'y' of same length as

On 11 Feb 2010, at 06:53, Vikrant Shimpi wrote: > Dear Luka , > I am using qcc package in R to plot SPC charts. BUt while plotting > R chart I had a error. My question is it necessary while plotting > R Chart the group sample size must be < 25 ?. Because when I took > group sample size as 1000 it gave me error, till I took group sample > size as 26, But as sooon as

Dear R-help, I have a character vector, some elements will be numeric, some not, and some even empty. E.g.: temp1 <- c("abcd"," 2 ","") I'm only interested in the numeric elements, the rest I can just throw away. It is easy enough to loop through the vector: temp <- try(eval(parse(text=temp1[1])), silent=TRUE); class(temp) # try-error temp <-

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

i have a time Series of IBM closing px from 1/1/2000 to today I want to graph the time serie by dividing the graph by year and month all the monthly graphs with the same year will go to one page. so from 1/1/2000 to 11/19/2010. i will have 11 pages, and each page will have 12 graphs (jan to dec) except for 2010. I am able to do it in R, but when i use sweave, I can only print the last page.

I have a GeForce 8800GT that I am trying to lower the fan speed on. I can change the fan RPM from high to not-as-high but I want more control over it. It is too loud and it was quieter with the blob. Maybe the temps are too high to make it quieter. # echo 1 >/sys/devices/pci0000:00/0000:00:02.0/0000:01:00.0/i2c-6/6-002e/pwm1_enable # sensors fam15h_power-pci-00c4 Adapter: PCI adapter power1:

Hi all- I am stumped. The code in A. returns errors at lines 14 and 15 and fails to load series1 and series2. However, in B., if temp1 and temp2 are called again (which returns a "Table exists" error; see lines 14-17 in B.) series1 and series2 load correctly. Any ideas? Also-I am open to any suggestions to improve the code as I am a horrific programmer. Thanks A. 1 >

I have a question about the output given below after running few lines of code. Surely a 101 query! MF_Data <- read.csv("MF_Data_F.txt", header = F, sep="|") temp <- head(MF_Data) #Get the sample Data temp1 <- subset(temp, select= c(V1,V4,V6)) #where V1, V4, V6 are the col names .. to Get the relevant data names(temp1) <- c('Ticker',

Hi, I am using eigen to get an eigen decomposition of a square, symmetric matrix. For some reason, I am getting a column in my eigen vectors (the 52nd column out of 601) that is a column of all NAs. I am using the option, symmetric=T for eigen. I just discovered that I do not get this behavior when I use the option EISPACK=T. With EISPACK=T, the 52nd eigenvector is (up to rounding error) a

Hi all, hope you having a nice day, I ahve this weird results with identical (probably I am not understanding correctly what it does ...) I have these two data frames and I issue : > identical(temp, temp1) [1] FALSE However, these data frames are Nx2 and when I issue: > identical(temp[,2], temp1[,2]) [1] TRUE > identical(temp[,1], temp1[,1]) [1] TRUE and the results from str >

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

I stumbled onto this working on an update to coxph. The last 6 lines below are the question, the rest create a test data set. tmt585% R R version 2.12.2 (2011-02-25) Copyright (C) 2011 The R Foundation for Statistical Computing ISBN 3-900051-07-0 Platform: x86_64-unknown-linux-gnu (64-bit) # Lines of code from survival/tests/singtest.R > library(survival) Loading required package: splines

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs