similar to: Converting list of lists into dataframes

Displaying 20 results from an estimated 4000 matches similar to: "Converting list of lists into dataframes"

2018 May 10
2
using for loop with data frames.
Hi, Is it possible use a loop to process many data frames in the same way? For example, if I have three data frames, all with same variables df_bs_id1 <- read.csv("test1.csv",header =TRUE) df_bs_id2 <- read.csv("test2.csv",header =TRUE) df_bs_id3 <- read.csv("test3.csv",header =TRUE) How could I would implement a code loop that , for instance, would
2011 Apr 13
2
setting pairwise comparisons of columns
Hi, I have a number of genes (columns) for which I want to examine pairwise associations of genotypes (each row is an individual)...For example (see data below), I would like to compare M1 to M2, M2 to M3, and M1 to M3 (i.e. does ac from M1 tend to be found with bc from M2 more often than expected.) Down stream I will be performing chi square tests for each pair. But I am looking for a way to
2009 Dec 03
2
Dataframe help
Hi there I have two dataframes Dataframe_1 column_1 colum_2 121 12345 145 1675 167 2765 Dataframe_2 column_1 column2 121 abc 345 lmn 167 efg I want a resulting dataframe 121 12345 abc 167 2765 efg how do i go abt it Ramya -- View this message in context: http://n4.nabble.com/Dataframe-help-tp947934p947934.html Sent from the R
2010 May 31
2
accessing a data frame with row names
Readers, I have entered a file into r: ,column1,column2 row1,0.1,0.2 row2,0.3,0.4 using the command: dataframe<-read.table("/path/to/file.csv",header=T,row.names=1) When I try the command: dataframe[,2] I receive the response: NULL I was expecting: row1 0.2 row2 0.4 What is my error with the syntax please? Yours, r251 mandriva2009
2004 Nov 23
5
number of pairwise present data in matrix with missings
is there a smart way of determining the number of pairwise present data in a data matrix with missings (maybe as a by-product of some statistical function?) so far, i used several loops like: for (column1 in 1:99) { for (column2 in 2:100) { for (row in 1:500) { if (!is.na(matrix[row,column1]) & !is.na(matrix[row,column2])) { pairs[col1,col2] <- pairs[col1,col2]+1
2009 May 14
2
Function to read a string as the variables as opposed to taking the string name as the variable
I am writing a custom function that uses an R-function from the reshape package: cast. However, my question could be applicable to any R function. Normally one writes the arguments directly into a function, e.g.: result=cast(table1, column1 + column2 + column3 ~ column4, mean) (1) I need to be able to write this statement as follows: result=cast(table1, string_with_columns ~
2006 Jan 04
3
matrix math
I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column
2008 Feb 26
1
Split data.frames depeding values of a column
Hello to all is there a function wich splits a data.frame (column1,column2,column3,....) into data1 <-(column1,column3....) #column2 = 1 data2 <-(column1,column3....) #column2 = 2 data3 <-(column1,column3....) #column2 = 3 ... Regards Knut
2006 Jun 07
4
Question: coding protected methods
Apologies first, because I need to ramp up on Ruby and coding Ruby in Rails, however it''s my 3rd day with this beast :) so I''m asking : When I added protected methods to the model before it was like: protected method.................... end Would this be a valid way to write a protected method as well ?: attr_protected :column1, :column2 Perhaps this particular call
2009 Jun 17
6
script help
Hi ? I have a file. list.txt (two columns) ? column1??? column2 name??????? address ? ? I need to put in the letter file letter.txt eg: ? Dear: Chloe Address: CA ? Can I use this ? for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt ? Thank you for your help ? ? ? ? ? __________________________________________________________________ Looking for the perfect gift?
2009 Jun 15
2
Help with syntax error
Hi, I have written boxplot commands of this form before, but I don''t quite understand why the function call is reporting a syntax error in this instance. All parameters passed to the function are strings. Thanks in advance. Payam > simplevar <- function(wframe,column1,column2) { + tframe <- get(wframe) + x1 <- which(names(wframe)==column1) + x2 <-
2013 Mar 21
2
Displaying median value over the horizontal(median)line in the boxplot
Hi, set.seed(45) test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data apply(test1,2,function(x) sprintf("%.1f",median(x))) #columnA columnB # "44.5"? "10.2" par(mfrow=c(1,2)) lapply(test1,function(x) {b<-
2004 Oct 25
2
Reading sections of data files based on pattern matching
I am about to write general functions to read the output of simulations models. These model generate output files with different sections which I want to analyze plot etc. Since this will be used many people at the department I wanted to make sure that will do this in the best way. For instance I want to read a snippets of data from a text that look like this.
2010 Feb 27
1
New Variable from Several Existing Variables
I am new to R, but have been using SAS for years. In this transition period, I am finding myself pulling my hair out to do some of the simplest things. An example of this is that I need to generate a new variable based on the outcome of several existing variables in a data row. In other words, if the variable in all three existing columns are "Yes", then then the new variable should
2003 Aug 07
2
Question about 'NA'
Hi all, Ive got a database with 10 columns (different variables) for 100 subjects, each column with different # of NA's. I'd like to know if it is possible to use a function to exclude the NA's using only a specific column, lets say: Data2 <- omit.exclude(Data1$column1) ??, then Data3 <- omit.exclude(Data1$column2) and so on I tried the code above but with no results Thanks
2009 Jul 07
2
How to separate the string?
Hi everyone, Hi want to separate the string(column1) for example column1 column2 column3 column4 column5 column6 bear b e a r cat c a t tiger t i g e r I know how to do this in excel where using MID function. Now I want to solve it using R. The list of strings is in
2009 Aug 12
2
Symbolic references - passing variable names into functions
Hello All, I am trying to write a function which would operate on columns of a dataframe specified in parameters passed to that function. f = function(dataf, col1 = "column1", col2 = "column2") { dataf$col1 = dataf$col2 # just as an example } The above, of course, does not work as intended. In some languages one can force evaluation of a variable, and then
2006 May 09
9
Active Record HELP!!!!!
Hello, Can someone kindly tell what the heck creating a relationship does in active record? I understand the idea of joining the tables and such. But how do I use it? Is it available in a scaffold? How about when I want to view a record and want to see all the joined data from the other table? Do I have to manually code the data I want from the other table? Does this automatically make the
2010 Feb 09
3
split strings in a vector and convert it to a data.frame
hi, I have a vector full of strings like; xy_100_ab xy_101_ab xy_102_ab xy_103_ab I want to seperate each string in three pieces and the separator should be the "_" at the end I want a data.frame like: column1 column2 column3 xy 100 ab xy 101 ab xy 102 ab xy 103 ab I tried strsplit but I couldn't figure out how to convert the list I get into a data.frame. I just
2012 Jun 12
4
How to index a matrix with different row-number for each column?
here's my question: suppose I have a matrix: mt<-matrix(1:12,ncol=6) now I have a vector vt<-c(1,2,2,2,1,2) which means I want to get: the 1st row for column1; the 2nd row for column2; the 2nd row for column3; the 2nd row for column4; ... that what I want is this vector: 1,4,6,8,9,12 Does anyone know how to do this fast? I know I can use for-loop to travel all columns,but