similar to: how to calculate the statistics of a yearly window with a rolling step as 1 day?

Hello Guys. I have updated the code,tests,documentation,makefile entries and the registry entry of the* *TfIdf patch as per the feedback.Please do let me know if any additional changes are required before the patch can be merged, -Regards -Aarsh On Sun, Mar 3, 2013 at 2:50 PM, aarsh shah <aarshkshah1992 at gmail.com> wrote: > Hello guys.I have sent a pull request for the code and

I have searched the forums but I am having trouble trying accomplish two specific plots. I am not sure if this is a very basic task but I am having a lot of trouble Here is my data frame: date prod_daily price 1 2003-08-15 12050 4.83 2 2003-08-18 12050 4.94 3 2004-08-10 12300 5.78 4 2004-08-11 12300 5.64 5 2004-08-12 12300

Hi all. Since our NT4 PDC is on it's last legs, I've been motivated to once again try to use samba's vampire functionality. Unfortunately I'm actually doing worse than last year ... My smb.conf: [global] socket options = TCP_NODELAY SO_RCVBUF=8192 SO_SNDBUF=8192 interfaces = 10.146.0.254/255.255.0.0 encrypt passwords = yes printing = cups

Hi all, I am plotting a financial time series, but I need a more detailed X-Axis. Example: x <- zoo(rnorm(1:6000), as.Date("1992-11-11")+c(1:6000)) plot(x) The X-Axis is labeled "1995", "2000" and "2005". I would need either "1995", "1997", etc. or maybe yearly I used google first, then look at "?plot.zoo" but

I have some data set which is available from 2005-2010 . I would like plot monthly maps out of it. So how I should write loop that can plot this yearly data to for every month and write title for individual months too. -- View this message in context: http://r.789695.n4.nabble.com/Plotting-monthly-maps-from-yearly-data-tp4391704p4391704.html Sent from the R help mailing list archive at

v="IBM" library(quantmod) v v1=getSymbols(v) to.yearly(v1) =============================== when i pass the value through a variable in to.yearly() function it shows the error msg like "Error in try.xts(x) : Error in UseMethod("as.xts") : no applicable method for 'as.xts' applied to an object of class "character"" i need the result of OHLC

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by =

Sorry, this is my first time to post. I have a big data set: first colume is date (ex: 2008-2-150, the second is time (10:30:00), and the following columes are variaty measurement data. Every 30 min, I have one data. I want to find an effecient way to calculate the hourly, daily, monthly and yearly average, and plot them, and eventually use these average data to do further analysis. Thanks!

Dear R-experts, Sorry if I've overlooked a simple solution here. I have calculated a proportion of the number of observations which meet a criteria, applied to five years of data. How can I break down this proportion statistic for each year? For example (data in zoo format): open high low close hc lc 2004-12-29 4135 4135 4106 4116 8 -21 2004-12-30 4120 4131

What is the problem with having huge online mailboxes? Just choose a good european provider that has encryption all the way through to their storage platform. I had exactly the same idea about migrating. You have to think twice about moving emails around of users. They do not like it ;) I have created an 'archive' environment on a distributed filesystem, and it takes me quite a lot

> >First of all, thanks for your answer. > >> What is the problem with having huge online mailboxes? Just choose a > good european provider that has encryption all the way through to their> storage platform. > >We already have a European ISP with a standard e-mail server. I wanted to keep our own mail server on premises, so that it is not exposed on >the

On Sun, 2009-07-26 at 13:17 +0200, Poersching wrote: > stvienna wiener schrieb: > > Hi all, > > > > I am plotting a financial time series, but I need a more detailed X-Axis. > > > > Example: > > x <- zoo(rnorm(1:6000), as.Date("1992-11-11")+c(1:6000)) > > plot(x) > > > > The X-Axis is labeled "1995", "2000"

Hi, I need to perform calculations on subsets of a data frame: DF = data.frame(read.table(textConnection(" A B C D E F 1 a 1995 0 4 1 2 a 1997 1 1 3 3 b 1995 3 7 0 4 b 1996 1 2 3 5 b 1997 1 2 3 6 b 1998 6 0 0 7 b 1999 3 7 0 8 c 1997 1 2 3 9 c 1998 1 2 3 10 c 1999 6 0 0 11 d 1999 3 7 0 12 e 1995 1 2 3 13 e 1998 1 2 3 14 e 1999 6

Hi all: I am new to e-mail servers and I am evaluating Dovecot. Not really the best combination. 8-) I am trying to find a balance between legal data retention requirements and online mailbox size. I do not want huge online mailboxes, as doing offline, rotating data backups could then take forever (among other reasons). I would rather avoid online (cloud) backups (data protection etc.). If I

First of all, thanks for your answer. > What is the problem with having huge online mailboxes? Just choose a > good european provider that has encryption all the way through to their> storage platform. We already have a European ISP with a standard e-mail server. I wanted to keep our own mail server on premises, so that it is not exposed on the Internet. The current server fetches (and

Dear all, I have a big data matrix and I want to convert those data into weekly basis which means 7 days needs to be avaraged and aggregate a single value > dput(test) structure(list(locid = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,