similar to: Converting factor into date

Hallo I am teaching a very elementary intro course about R, and want to show the students how to find the distribution of the maximum of rolling two balanced die. Is there perhaps a more elegant way to do this, other than the way I am using below? (I would like to show them two ways - the one shown here, and perhaps and improved/elegant approach (showing off the "beauty" of R.

Hi All: If I download yahoo data by getSymbols() in R, the date column gets accompanied along with the downloaded data. There is no column header for the date column to access separately. What is the way to eliminate the date column? If I want to draw a xy scatter plot with the downloaded price (suppose AAPL vs NASDAQ), I think the date column is creating problem and the plot function is not

Dear r-help, I would like to select a subset of levels from a factor variable in a data frame and return a data frame. The data set consists of 3 variables, 2 of which are factors (Site, Fish) and one numeric (Datavalue) as follows: Site Fish Datavalue AB 2-1 2.3 AB 2-1 2.4 AB 2-1 2.2 AB 2-2 2.6 AB 2-2 2.5 AB 2-2 2.7 AB 2-3

Hi , I am trying to convert the date as factor to date using "as.date" function in R. I have the date in the following format 2008-01-01 02:30 I tried to use the following command : as.Date(mydata$Date, format="%y-%m-%d ") Can somebody help me with this ? I was able to convert the format with no hour but getting difficulty with hour included. Thank you.

In the following data.frame there are 6 columns, but 7 are written to the CSV file. install.packages("pmlr") library(pmlr) data(enzymes) write.table(enzymes, sep=",", eol="\n",file="albert.csv")

Thanks, Here's the error, for example: > install.packages("mgcv") Installing package into 'C:/Users/pl39/Documents/R/win-library/3.4' (as 'lib' is unspecified) trying URL 'https://mirrors.nics.utk.edu/cran/bin/windows/contrib/3.4/mgcv_1.8-23.zip' Content type 'application/zip' length 2775362 bytes (2.6 MB) downloaded 2.6 MB package 'mgcv'

I am a raw novice to R, playing around with a mini .csv dataset created in Excel. I can read it in and the data looks OK in Excel and upon initial inspection in R: hikes <- read.csv("/Users/eproper/Desktop/hikes.csv", header=TRUE) print(hikes) does exactly what it is supposed to do. Two of the variables are genuine strings, but the others ought to be numeric, and R will calculate

Here is my model with interaction terms and control variables (I changed variables names for easy read): reg1 <- lm(y ~ x1*x2*x3 +control1 + control2 + control3) x1 ranges from 0 to 6; x2 from 0 to 5; and x3 from 0 to 4. All three are discrete ordinal variables; but I will treat them as continuous variables. (a) How can I see the predicted values of y for each of these scenarios (210

I doubt your actual file looks like the mess that made it to my email software (below) because you posted HTML-format email. Read the Posting Guide, and in particular figure out how to send plain text email. You might try the "anytime" contributed package, though I suspect it too will choke on your mess. Otherwise, that will pretty much leave only a brute-force series of regular

Hello, I have some unbalanced panel data that is measured on weekdays only (i.e., excluding Saturday and Sunday). I would like to get the number of days between dates such that the number of days between a Friday and a Monday is 1 (and not 3). Here is some code to illustrate my problem: library('Hmisc'); DATE <-

Do you have other instances of R open at the time you are doing this? Did you already have mgcv installed in your personal library when you tried installing it again? There is clearly something preventing you from writing to your library, or at least to specific packages in your library. On Tue, 27 Mar 2018, Paul Lantos wrote: > Thanks, > > Here's the error, for example: >

I deleted my library, reinstalled R, and had the same issue -- couldn't install anything into its newly created library. -----Original Message----- From: Jeff Newmiller [mailto:jdnewmil at dcn.davis.ca.us] Sent: Tuesday, March 27, 2018 2:26 PM To: Paul Lantos <paul.lantos at duke.edu> Cc: r-help at r-project.org Subject: RE: [R] unable to move temporary installation of package Do you

Dear R users, I have two n*1 integer vectors, y1 and y2, where n is very very large. I'd like to compute elbp = 4^(y1) * 5^(y2) * sum_{i=0}^{max(y1, y2)} [{ (y1-i)! * (i)! * (y2-i)! }^(-1)]; that is, I need to compute "elbp" for each (y1, y2) pair. So I made R code like below, but I don't think it's efficient Would you plz tell me how to avoid this "for"

Hi,? I have a data set with various date formats in one column and not sure how to unify it.Here is a few formats: 02091702/22/170221201703/17/160015-08-239/2/1500170806May-2-201522-March-2014 I tried parse_date_time from lubridate library but it failed.Thanks so much.?Best,Farnoosh [[alternative HTML version deleted]]

Dear R users, I am facing a pretty a unusual problem while converting character to numeric. Any input would be appreciated. Below is the code and error faced: --------------------------------------- *> str(cmie.dts)* *'data.frame': 4397 obs. of 1 variable:* * $ INE001A01036: chr "1482181740.000000" "1482181740.000000" "1482181740.000000"

R-listers, I have noticed several posts on issues with difftime producing NA's but they have been for older versions of R. Here's the issue associated with difftime that I am dealing with in R 2.12.2. > preciptime = strptime("01/10/2007 14:00",format="%m/%d/%Y %H:%M") > class(preciptime) [1] "POSIXlt" "POSIXt" > # Now using difftime, this

Hi, I am running Linux (64 bit) R, compiled under gnu compilers. I am looking to compile a Fortran program with the ifort (the intel compiler) and then be able to import that as a library into my version of R. I am using the flags FC=ifort and SHLIB_FCLD=ifort, however ifort does not seem to recognize the libR.so file. Does any one have experience with this/know of a a way to load an ifort

Hi all, When I use rbind() or rbind.data.frame() to add a row to an existing dataframe, it appears that attributes for the column of type "factor" are dropped. I see the following post with same problem. However i did not see any reply to the following posting offering a solution. Could someone please help.

Hi all, I'm writing a function that summarizes objects, however, when a Date variable is present in the objects it doesn't work. How can I handle with this problem? D

Hi, Let say I have a date variable: > ?asd <- as.Date("2012-01-03") > asd [1] "2012-01-03" Now, I want to express this date like 3/1/2012. can somebody help me how to achieve that? Thanks,