similar to: Delete files with system command on Windows 7

Dear R-specialists, I am trying to create a Makefile that will first convert all my .Rnw files into .tex files and then, that will run the LaTeX compiler to produce a pdf document. This issue has been discussed before. Hence, I've basically adapted a Makefile I found at http://n4.nabble.com/R-Sweave-R-and-complex-latex-projects-td810020.html#a810023 to make it compatible with a Windows

On Wed, 2012-01-25 at 15:55 +0000, Xen patchbot-unstable wrote: > # HG changeset patch > # User Keir Fraser <keir@xen.org> > # Date 1327506767 0 > # Node ID 4271634e4c86568b6bf2241ebf9be4a82ab430bf > # Parent a2a8089b1ffbf5757ca3191cb8f74a5f1ed7fed1 > docs: Remove outdated LaTex documentation. Nice. > @@ -82,7 +70,7 @@ > $(MAKE) -C xen-api clean >

Hi, This is a follow-up to the problem reported here: https://stat.ethz.ch/pipermail/r-devel/2010-September/058460.html After I updated R-2.12 to 2010-09-13 r52905 on the Bioc build system, some of the packages that have a Makefile in <pkg>/inst/doc still don't build on Windows. For example, 'R\bin\R.exe CMD build adSplit' gives: * checking for file

Hello, The other day Justin Peter presented a mini program to plot a topographic map with an overlay of the worldHires. I seemed interesting so I checked the ETOPO5 site and find that there is a new file ETOPO1 with a 1 minute grid. I downloaded it and tried a similar procedure. Now the ETOPO1.gz is 1 Gb and the uncompressed file is 5 Gb. They do not fit into my laptop. I tried the following

Hello, I'm running R2.10, Eclipse, StatEt and MikTex 2.8 to create Sweave documents, and everything seems to work great, until today... I was trying to add citations from a Bibtex file, but I just got [?] citations. However, if I open the .tex file that StatEt created in MikTex and run the latex+bibtex+pdflatex command, the citations are present. Does anyone know how to either configure

Dear R-help, I am using Sweave and pdflatex to generate a large report from data contained in my database (Postgres via RODBC). Currently, I work with a single R/Sweave file, containing several "chapter" indications for the Latex engine. My master tex file sets the document class, and includes the introduction, the main Sweave file, and a conclusions and reference file. I use a makefile

Dear R folks, One of the fantastic new tools in R is `Sweave'. I have tested it so much that I know it works and produces fine documentation, and with (GNU) Emacs/ESS it is nice to work with, too. I started to have a look at including some Swoven (is that a strong verb?) documentation with my R package, but it seems that there is no model to copy among those packages that I have installed in

On 30/09/16 20:10, Reid Kleckner wrote: > On Mon, Sep 19, 2016 at 4:42 AM, Jonas Maebe <jonas-devlists at watlock.be > <mailto:jonas-devlists at watlock.be>> wrote: > > So, can I use invoke and landingpad without using any of the other > exception handling intrinsics? (in combination with a dummy personality > function) Or will LLVM in all cases insist on

So I have this fairly basic migration bit of code class AddCounterCache < ActiveRecord::Migration def self.up add_column ''products'', ''backlog_items_count'', :integer, :default => 0 end def self.down remove_column ''products'', ''backlog_items_count'' end end What I want to do in that is automatically

Hello! If I have a vector vec <- c(FALSE, FALSE, TRUE, FALSE, TRUE, TRUE, FALSE FALSE) I can I create the following order of numbers based on vector vec: 1, 2, 2, 3, 3, 3, 4, 5 Whenever there is a FALSE I increase the number (starting with 1). Whenever there is a TRUE I set the same number as the previous FALSE has been assigned to. I would be happy for any input Cheers, Syrvn -- View

Hi, let's assume I have the following vector a: 1 5 23 How can I use R to duplicate the elements so that my new vector looks like: 1 1 5 5 23 23 Many thanks, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/Duplicate-elements-of-a-vector-tp3879561p3879561.html Sent from the R help mailing list archive at Nabble.com.

On 03/26/2014 11:36 AM, Geoffrey Irving wrote: > I am trying to compute conservative lower and upper bounds for the > square of a double. I have set the rounding mode to FE_UPWARDS > elsewhere, so the code is > > struct Interval { > double nlo, hi; > }; > > Interval inspect_singleton_sqr(const double x) { > Interval s; > s.nlo = x * -x; > s.hi = x *

In fact my first vignette full stop. I am intending to use Sweave. I have read the Sweave documentation and section 1.4 of the extensions manual and apart from (a) do not use split = TRUE (b) and include all the source components, there does not seem to be anything CRAN specific. 1 - Am I missing some other documentation? 2 - If I use a package from CTAN would that be considered within the

Hi, the R code: a <- matrix(c(1,5,4,3,7,10,34,4,3,8,6,5,12,17,45,3,2,45,46,47,3,4,22,12,21), nrow=5) rownames(a) <- c("a","b","c","d","e") a a[which(a[,3] < 8), ] a[which(a[,3] < 6), ] produces the following output: > a [,1] [,2] [,3] [,4] [,5] a 1 10 6 3 3 b 5 34 5 2 4 c 4 4 12 45 22 d

Hello! with the R system command I would like to call a perl script which needs an input directory and an output directory in form of a path. When I put in the path directly it works. The script line looks as follows: system("perl '../path1' '../path2' '../path3'") If I store the path in a variable/object and call the perl script again it does not run and I

Hello, with Sys.time() you get the following string: "2011-11-15 16:25:55 GMT" How can I extract the following substrings: year <- 2011 month <- 11 day_time <- 15_16_25_55 Cheers, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/Extract-pattern-from-string-tp4073432p4073432.html Sent from the R help mailing list archive at Nabble.com.

Hi, imagine the following matrix/data.frame Letter Number a 1 a 1 b 1 b 0 c 0 c 1 d 0 d 0 If the numbers for two identical letters are also identical then I want to remove either the first or the second row of that letter. If for a letter the numbers are 1 and 0 I want to remove the row with the 0. That means if the code works I would and up with the following matrix/data.frame Letter

Hello, consider the following data.frame df and vector v df <- data.frame(group = c("A","B","C","D"), value = c(1,2,3,4)) v <- c(2,3) How can I return a sub data.frame which has only the rows left where value matches v df: group value B 2 C 3 Cheers -- View this message in context:

Dear all, I need to do the same procedure on several files. But I don't know how to refer to the file name. Here is an example of what I am trying to do. List of files: file1(A,B,C, D1...Dn), file2(A,B,C,E1,...,En), file3(A,B,C,F1,...,Fn) Procedure I want to apply on each file: dft <- melt(df,id=c('A','B','C')) dft$X <- substr(dft$variable,1,3) dft$Y <-

Hello, can anybody tell me how to produce a plot like the one in http://cran.r-project.org/web/packages/lme4/vignettes/Implementation.pdf on page 13, Figure 6? The data is stored in: library(nlme) data(Oats) Cheers -- View this message in context: http://r.789695.n4.nabble.com/Help-needed-in-reproducing-a-plot-tp4119603p4119603.html Sent from the R help mailing list archive at