similar to: Find a particular point on a curve

Dear all- I have a dataset (see a sample below - but the whole dataset is June 2005 - June 2008). The "LST" format is "YYMMDDHHmm" and I would like to get the hourly average of the "mph" for the summer months (spanning all years). I have been trying to use "aggregate" but am not having much success at all! any thoughts would be greatly appreciated.

I'm trying to read a comma delimited dataset that uses '.' for NA. I found that if the last field on a line was a missing '.' it was not read as NA, but just a '.', and the life variable was made a factor. The data looks like this, income,imr,region,oilexprt,imr80,gnp80,life Afghanistan,75,400.0,4,0,185.0,.,37.5 Algeria,400,86.3,2,1,20.5,1920,50.7

Dear Community, I have been using two types of survival programs to analyse a data set. The first one is an R function called aftreg. The second one an STATA function called streg. Both of them include the same analyisis with a weibull distribution. Yet, results are very different. Shouldn't the results be the same? Kind regards, J -- View this message in context:

We would like to load data from Statistics Canada (http://www.statcan.gc.ca/) using R, for example, Employment and unemployment rates. It seems to me that the tables are displayed in HTML. I was wondering if you know how to load these tables. Thanks, -james

Hi, I need help writing a function I capture seal pups mutliple times during the lactation season in order to monitor their growth rate. When I release them, the recovery (mother-pup) time is not the same for all individuals. I want to know if individuals that recover their mother the fastest are the ones with the highest growth rates. So, I noted at every release if the pup

Hi Everyone, I have a dataset like this mean sd 0% 25% 50% 75% 100% n BODY TEMPERATURE 36.41099 0.4015699 35.1 36.22222 36.5 36.66667 37.1 89 DIASTOLIC BLOOD PRESSURE 73.60079 9.4656186 50.0 67.00000 73.0 80.00000 95.0 253 HEIGHT 171.94000 9.2011670 153.5 166.50000 173.0 176.25000 190.0

I am working on high load daemon development, which listens on UDP and processes packets. Last few months I noticed some strange issue when it takes 500-700 ms to answer packet, while usually it takes 20 ms. I've run strace on all daemon processes and found this thing: 13:35:36.979887 stat("/etc/localtime", {st_mode=S_IFREG|0644, st_size=2309, ...}) = 0 13:35:36.979944 write(3,

Dear Listserv, Here is my latest in a series of simple-seeming questions that dog me. Consider the following data: x <- read.table(textConnection("temperature probability 0.11 9.4 0 2.3 0.38 8.7 0.43 9.2 0.6 15.6 0.47 8.7 0.09 12.8 0.11 9.4 0.01 7.7 0.83 8 0.65 9.3 0.05 7.4 0.34 10.1 0.02 4.8 0.07 9.1 0.6 15.6 0.01 8.4 0.9 9.6 0.83 8 0.12 8.4 0.01 8 0 5 0.11 9.7 0.41 7.4 0.05 9.4 0.09

Hi Team Can someone advice me on how i can lower the load average on my asterisk server? dahdi-linux-2.1.0.4 dahdi-tools-2.1.0.2 libpri-1.4.10.1 asterisk-1.4.25.1 2 X TE412P Digium cards on ISDN PRI Im using the system as an IVR without any transcoding or bridging ************************************** top - 10:27:57 up 199 days, 5:18, 2 users, load average: 67.75, 62.55, 55.75 Tasks: 149

Hi friends. Package: nut Version: 2.4.1-1 Depends: libusb, openssl, neon, libgd, net-snmp Status: install user installed Section: admin Architecture: mipsel maintainer: NSLU2 Linux <nslu2-linux at yahoogroups.com> MD5Sum: c8c55a6021fea2b5f194ce4623eb2dfe Size: 1246363 Filename: nut_2.4.1-1_mipsel.ipk Source: http://eu1.networkupstools.org/source/2.4/nut-2.4.1.tar.gz Description: Network UPS

Dear R listers, When using smooth.spline to interpolate data, results are generally good. However, some cases produce totally unreasonable results. The data are values of pressure, temperature, and salinity from a probe that is lowered into the ocean, and the objective is to interpolate temperature and salinity to specified pressures. While smooth.spline provides excellent values at the

Dear list, I want to make a plot based on the following information, using the command plot. variable A for x axis : temperature (range: -20 degrees to 40 degree) variable B for y axis : altitude (range: 50 m to 2500 m ) The data below 0 degree of X variable wants to be erased tentatively. Please kindly advise the command to extract the data ranging from 0 degree to 40 degrees. Thank

I've got a list of 5 matrices that are each 5 x 6. I'd like to end up with a 5 x 6 matrix that contains the mean value of the 5 original matrices. I can do this by brute force, but there must be a better way than making each matrix into a vector and then remaking a matrix thanks very much for any help david freedman ll=list(structure(c(9.7, 17.6, 20.8, 24.1, 33.8, 14.5, 25.7, 29.8,

Dear useRs, i want to split a matrix having 1116rows and 12 columns. i want to split that matrix into 36 small matrices each having 12 columns and 31 rows. The big matrix should be splitted row wise. which means that the first small matrix should copy values which are in first 31 rows and 12 columns of the big matrix. similarly 2nd small matrix should contain values from 32nd to 63rd row of the

Dear all, I am quite new to R; facing certain problems: Say, I have a text file( named as "try"): Year C1 C2 C3 C4 C5 C6 Y1 3.5 13.8 9.5 6.8 0.4 24.2 Y2 3.8 13.9 9.9 7.6 0.7 12.8 Y3 4.5 14.5 14.2 9.2 0.6 14.5 Y4 5.9 16.2 24.6 12.7 0.2 24.3 Y5 7.2 20.4 40.6 18.2 0.8 28.2 Y6 5.9 18.6 37.4 14.5 0.3 36.9 Y7 8.0 16.1 88.6 24.1 0.1 34.6 Y8 13.6 21.1 56.3 19.0 0.7 33.3 I wish to import the

I have timstamped data like this: > sd[1:10,] Tstamp Density Mesh50 Mesh70 Mesh100 Mesh150 Mesh200 2 2009/02/27 07:00 30.5 0.7 10.7 21.4 32.8 41.6 3 2009/02/27 08:00 32.2 1.6 12.4 23.3 34.5 43.0 4 2009/02/27 09:00 32.7 4.8 13.0 24.0 35.1 43.5 5 2009/02/27 10:00 26.7 0.3 6.5 17.6 28.1 36.9 6 2009/02/27 11:00

I know that R is very advanced when it comes to DateTime handling. I am not quite as advanced as R however. I just downloaded a stupendously ugly dataset of hourly air temperature from 1985 to 2003. It has a great many NAs. I want to extract mean, median, max, and min monthly values. So far I have read it in as object. Date and Time are factors and Temp is an int. > summary(temp.dat)

Hi, Suppose I have the following vector (data points): > x [1] 36.0 57.3 73.3 92.0 300.4 80.9 19.8 31.4 85.8 44.9 24.6 48.0 [13] 28.0 38.3 85.2 103.6 154.4 128.5 38.3 72.4 122.7 123.1 41.8 21.7 [25] 143.6 120.2 46.6 29.2 44.8 25.0 57.3 96.4 29.4 62.9 66.4 30.0 [37] 24.1 14.8 56.6 102.4 117.5 90.4 37.2 79.6 27.8 17.1 26.6 16.3 [49] 41.4 48.9 24.1

Is this what you want? temp<-c(rep("Low",2),rep("Medium",2),rep("High",2)) light<-rep(c("Dark","light"),3) avg<-dat.avg2[,3] # se<-dat.avg2[,4] dat.avg.temp<-data.frame(cbind(avg,se)) dat.avg.temp<-data.frame(cbind(temp,light,dat.avg.temp)) dat.plot<-qplot(light,avg, fill=factor(temp),data=dat.avg.temp, geom="bar",

Hi, I have a data frame of about 700 000 rows which look something like this: Date Temperature Category 2007102 16 A 2007102 17 B 2007102 18 C but need it to be: Date TemperatureA TemperatureB TemperatureC 2007102 16 17 18 Any suggestions? /Angelica -- View this message