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Dear all, I have a large vector (lets call it myVector) and I want to plot its value with the logic below yaxis<-myVector[1] yaxis<-c(xaxis,mean(myvector[2:3]) yaxis<-c(xaxis,mean(myvector[4:8]) yaxis<c(xaxis,mean(myvector[9:16]) yaxis<c(xaxis,mean(myvector[17:32]) this has to stop when the new ..... yaxis<c(xaxis,mean(myvector[1024:2048]) will not find the correspondent number

Hello everyone. I would like to find the sample covariance matrix using R. So far I read on the wikipedia what a sample_covariance is http://en.wikipedia.org/wiki/Sample_covariance according to wikipedia one vector is enough to calculate the sample covariance matrix. In R I tried cov(myvector) and I get the reply that I need to pass either two argument or one matrix with x,y values . How can I

Dear all, I would like to print an empirical cdf on a vector I have while the plot(ecdf(myVector)) works great when I try to specify the line type to be a line (I get points) with plot(ecdf(myVector),type="lines") Error in plot.default(NA, NA, type = "n", xlim = xlim, ylim = ylim, xlab = xlab,  :   formal argument "type" matched by multiple actual arguments I get

Hello, i would like to ask you another question. Is exist anymethod to vectors that tells me the last element?That is to say,I have a vector, I want to return the position of last element. I hope having explained. A greeting, Ignacio. -- View this message in context: http://old.nabble.com/Method-tp26493442p26493442.html Sent from the R help mailing list archive at Nabble.com.

Dear all, I would like to create the following sequence of numbers 1 2 2 3 3 3 3 4 4 4 4 4 4 4 4 and so on (actually I double the number of same elements).... the reason is that I want then to feed the sequence above to  tapply(myVector, weirSeq, FUN = mean) and then average over those... Could you please provide some guidance how I can create such a sequence in R? Regards Alex

> is.na(strptime("5/2/1992", format="%m/%d/%Y")) [1] FALSE > is.na(strptime("5/3/1992", format="%m/%d/%Y")) [1] TRUE Any idea what's going on with this? Running strptime against all dates from around 1946, only 5/3/1992 was converted as "NA". Even stranger, it still seems to have a value associated with it (even though is.na thinks

Dear all, Could you please explain me why > OverloadsTesT [1] 1 0 1 0 0 0 0 0 0 0 > a<-matrix(data=seq(1,10),nrow=10) > a [,1] [1,] 1 [2,] 2 [3,] 3 [4,] 4 [5,] 5 [6,] 6 [7,] 7 [8,] 8 [9,] 9 [10,] 10 > a[-OverloadsTesT] [1] 2 3 4 5 6 7 8 9 10 the last line does not remove the first and third element and only does the first element.? What I

Dear Users! I encountered with some problem in data reading while I challenged R (and me too) in a validation point of view. In this issue, I tried to utilize some reference datasets ( http://www.itl.nist.gov/div898/strd/index.html). And the result departed a bit from my expectations. This dataset dedicated to challenge cancellation and accumulation errors (case SmLs07), that's why this

> grep("f[0-9]+=", "f1=5,f22=3,", value = T) [1] "f1=5,f22=3," How do I make the line output c("f1", "f22") instead? (Actually, c(1,22) would be even better). Thank you. -- View this message in context: http://r.789695.n4.nabble.com/Quick-GREP-challenge-tp2339486p2339486.html Sent from the R help mailing list archive at Nabble.com.

Hi, set.seed(29) myVector<- rnorm(100) ?seq(1,100,by=2) # [1]? 1? 3? 5? 7? 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 #[26] 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 myVector[seq(1,100,by=2)] rev(myVector) ?sum(myVector>0) #[1] 46 #or ?table(myVector>0) # #FALSE? TRUE ?#? 54??? 46 A.K. Hey guys, this is my first week

Dear colleagues, Is there a way to order list items by date? I have a series of surveys in a list where the name of each list item is the date the survey was taken but the list items are out of order. Each data frame has a variable in it with the survey date as well, if that helps. Yours, Simon Kiss #Sample Data mylist<-list('1991-01-01'=data.frame(a=rep(5,5),

I am working on a simulation where I need to count the number of matches for an arbitrary pattern in a large sequence of binomial factors. My current code is for(indx in 1:(length(bin.05)-3)) if ((bin.05[indx] == test.pattern[1]) && (bin.05[indx+1] == test.pattern[2]) && (bin.05[indx+2] == test.pattern[3])) return.values$count.match.pattern[1] =

Hi! I'm running R version 2.13.0 (2011-04-13) Platform: i386-pc-mingw32/i386 (32-bit) When i type in the command: sum(c(-0.2, 0.8, 0.8, -3.2, 1.8)) R returns the value: -5.551115e-17 Why doesn't R return zero in this case? There shouldn't be any rounding error in a simple sum. Thanks, Mark

>From: Johannes Graumann <johannes_graumann at web.de> >Date: 2007/12/18 Tue PM 04:40:37 CST >To: r-help at stat.math.ethz.ch >Subject: [R] All anchored series from a vector? lapply(1:length(myvector) function(.length) { c(myvector[1}:myvector[.length]) }) but test it because i didn't. >Hi all, > >What may be a smart, efficient way to get the following result:

Dear all, While I am executing my code I receive the error below Error in sort.int(x, na.last = na.last, decreasing = decreasing, ...) :   'x' must be atomic the weird thing that I am not calling anywhere sort function nor do I rely on anyh sorting. How I can discover where this comes from (inside which function?). I would like to thank you in advance for your help B.R Alex

The example here puzzles me. It seems like the < operator doesn't work as expected. > l <- 0.6 > u <- seq(0.4, 0.7, 0.1) > u [1] 0.4 0.5 0.6 0.7 > mygrid <- expand.grid("l" = l, "u" = u) > mygrid l u 1 0.6 0.4 2 0.6 0.5 3 0.6 0.6 4 0.6 0.7 > mygridcollapsed <- mygrid[mygrid$l < mygrid$u, ] > mygridcollapsed l u 3 0.6 0.6 4

Hi, I am trying to find a function to match two data frames of different lengths for one field only. So, for example, df1 is: Name Position location francesca A 75 cristina B 36 And df2 is: location Country 75 UK 56 Austria And I would like to match on "Location" and the output to be something like: Name Position Location Match francesca A 75 1 cristina B 36 0 I have tried with

Hello everyone, I've come up with a problem with using paste() inside apply() that I can't seem to solve. Briefly, if I'm using paste to collapse the rows of a data frame, AND the data frame contains strings with spaces, AND there are NA values in subsequent columns, then paste() introduces spaces. This only happens with that particular combination of data values and commands. I have

Dear all, let say I have following list: Dat <- vector("list", length = 26) names(Dat) <- LETTERS My_Function <- function(x) return(rnorm(5)) Dat1 <- lapply(Dat, My_Function) However I want to apply my function 'My_Function' for all elements of 'Dat' except the elements having 'names(Dat) == "P"'. Here I have specified the name

Hello, I'm using range do define boundaries for a linear model, so the line I graph is only graphed for the range of data. There are NAs in the data, but I dont remember this being a problem before. I typed na.action=na.omit anyway, which has usually solved any NA issues in the past. Any idea why R cant do vector functions for these data? Solution? Thanks, Colin Wahl M.S. Biology candidate