Displaying 20 results from an estimated 6000 matches similar to: "inset one map on top of another map"
2011 Aug 19
2
display only the top-right half of a correlation matrix?
Dear all
Is there an easy way to display only one half (top-right or
bottom-left) of a correlation matrix?
> require(Hmisc)
> rcorr(as.matrix(mtcars[ , 1:4]))
mpg cyl disp hp
mpg 1.00 -0.85 -0.85 -0.78
cyl -0.85 1.00 0.90 0.83
disp -0.85 0.90 1.00 0.79
hp -0.78 0.83 0.79 1.00
n= 32
P
mpg cyl disp hp
mpg 0 0 0
cyl 0 0 0
disp 0 0
2012 Oct 11
2
struggling with R2wd or SWord? Try rtf!
I have been looking for a way to write R-generated reports to Microsoft
Word documents. In the past, I used the package R2wd, but for some reason
I haven't been able to get it to work on my current set up.
R version 2.15.0 (64-bit)
Windows 7 Enterprise - Service Pack 1
Microsoft Office Professional Plus 2010 - Word version
14.0.6123.5001 (32-bit)
I gave the package
2009 Jul 28
3
selecting vector elements using matrices and combining the results
I've been scratching my head over this one for too long. I'm hoping
someone out there can solve this riddle.
I have two vectors of characters, v1 and v2, both of length L, and two
matrices of logicals, m1 and m2, both of dimension N*L. The first matrix
of logicals corresponds to the first vector of characters, and the second
to the second.
The matrices are telling me which of the
2011 Aug 10
1
column names issue with read.csv
Dear List,
I wonder why when using read.csv(), if the column name contains a
numeric i.e. a stock symbols-"0001.HK", it will automatically insert
an "X" character to the column names - "X0001.HK".
Now I have to manually do a loop and use substring() to remove the "X"
character. Any advice? Thanks
Anthony
2011 Aug 19
1
how to merge distance data based on location
Hi all,
I have two data frames, two columns each, 1000s of rows. Each row
represents a segment of the genome where a deletion has occurred.
First column is start position of the deletion in genomic distance,
second is end position.
So, e.g., first 3 rows of data frame A is:
1003 1023
5932 6120
12348 12689
first 3 rows of data frame B is:
852 5305
1010 1015
8500 9500
10000 13000
I want to merge
2011 Aug 05
1
Displaying a summary in graphics
I'm writing a script which puts together a bunch of graphs and outputs them to a graphics device. One of the things I want to add is ANOVA summaries but I'm having trouble with formatting them for graphics.
I do this:
anova_summary <- summary(aov(concentration~inhibition*genotype, data =drug_data))
print(anova_summary)
The printout to the R console is in the format I want but if I
2011 Jun 15
2
Count occurances in integers (or strings)
Hi,
I have a dataframe column from which I want to calculate the number of
1's in each entry. Some column values could, for example, be
"0001001000" and "11110000111".
To get the number of occurrences from a string I use this:
sum(unlist(strsplit(mydata[,"my_column"], "")) == "1")
However, as my data is not in string form.. How do I convert
2011 Aug 03
2
syntax with do.call and `[`
Dear List,
i would like to mimic the behaviour or the following indexing with a do.call construct to be able to supply the arguments to `[` as a list:
test = matrix[1:4,2]
result = test[2,]
My try, however, did not work:
result = do.call(`[`,list(test,2,NULL))
result = do.call(`[`,list(test,2,))
result = do.call(`[`,list(test,2,''))
How can I use the do.call in that way with
2011 Aug 10
2
function runif in for loop
Hello,
I'd like to perform a regression using MCMCregress (MCMCpack).
One variable therefore should be a function rather than a variable:
I want to use X as an input and X should be defined as a random number between to values. Therefore I want to use the function runif like:
X <-(1, Xa, Xb) but it seems that runif doesn't allow to use vectors.
So I think I've to calculate the new
2011 Jul 27
2
plotting the ending point in a for loop
Hello,
I would appreciate if someone could help me with this query. I would like to
plot a line chart of all of the points in a "for" loop. I would also like
to plot the final point with a symbol (to show where the random walk ends).
Here is the code I am using:
Brownian.fn <- function(mu, sigma, T, N){
dt <- T/N
t <- c(rep(NA, N))
B1 <- c(rep(NA, N))
B2 <- c(rep(NA,
2011 Aug 10
2
round() a data frame containing 'character' variables?
Dear all
It is difficult to use round(..., digits=2) on a data frame since one
has to first take care to remove non-numeric variables such as
'character' or 'factor':
> head(round(iris, 2))
Error in Math.data.frame(list(Sepal.Length = c(5.1, 4.9, 4.7, 4.6, 5, :
non-numeric variable in data frame: Species
> head(round(iris[1:4], 2))
Sepal.Length Sepal.Width Petal.Length
2011 Aug 05
2
R compare cells in one matrix
Good morning!
Please, could you help me with the problem?
I have a matrix *144x73.*
An example of a matrix:
[,1] [,2] [,3] [,4] [,5]
[1,] 277.4 276.24 275.62 276.55 278.05
[2,] 277.4 276.24 275.55 276.42 277.72
[3,] 277.4 276.24 275.50 276.22 277.39
[4,] 277.4 276.24 275.42 276.02 277.02
[5,] 277.4 276.22 275.37 275.82 276.64
And I want to *compare*its cells
2011 Jul 28
3
Data frame to list
I'm hoping this is an easy problem that I'm missing something obvious. Given:
x=c(1,1,1,2,2,3,3,3)
y=c(1:length(x))
dataframe=data.frame(x,y)
I would like to convert this to a list for use with certain functions,
where each entry of the list is a subsetted dataframe based on
dataframe$x
I can do this "brute force" by a for-next loop:
unique_x=unique(dataframe$x)
2011 Aug 01
3
possible reason for merge not working
Hi Guys,
working on a "merge" for 2 data frames.
Using the command:
x <- merge(annotatedData, UCSCgenes, by.x="names",
by.y="Ensembl.Gene.ID", all.x=TRUE)
names and Ensembl.Gene.ID are columns with similar elements from the x
and y data frames.
annotatedData has 8909 entries, so has x(as expected). x has columns
for UCSCgenes, but there is no data in them, all
2011 Aug 02
2
Data frame to matrix - revisited
Hi,
I've tried to look through all the previous related Threads/posts but can't find a solution to what's probably a simple question.
?
I have a data frame comprised of three columns e.g.:
?
ID1?ID2?Value
a?b?1
b?d?1
c?a?2
c?e?1
d?a?1
e?d?2
?
I'd like to convert the data to a matrix i.e.:
?
?a b c d e
a n/a 1 2 1 n/a
b 1 n/a n/a 1 n/a?
c 2 n/a n/a n/a 1
d 1 1 n/a n/a 2
e n/a n/a 1
2011 Aug 04
3
R loop problem
I have run into a speed issue, and given the size of the problem it feels
like there should be an easy solution. Here is the problem statement with
some arbitrary numbers added.
#p,q: vector with length(q)==length(p)==10000 and length(levels(p))==3000
#y,z: vectors with length(levels(y))=length(y)==length(z)==5000
for (i in levels(p)){
q[i==p]<-z[i==y]}
At first i used two for loops which
2010 Aug 05
2
colour of label points on a boxplot
Hi all,
I have 6 datasets(dataframes Assem_ContigsLen7 through all_ContigsLen12)
containing 3 columns (contig_id, contig_length, read_count).
Each dataset is composed of 3 types of contigs (assemblies of genomic
fragments), 1- all Bacterial fragments, 2 - all Viral fragments, 3 -
mixed fragments.
I identified the type of contig through a merge with another table with
just contig_id and
2011 Aug 01
4
fill Matrix quicker
dear all,
i have a quite simple question, i want to fill up a Matrix like done in the
following function,
but the performance is very bad for large dimensions
is there a way to do this like with apply or something similar?
makeMatrix <- function(a, b,dim) {
X=matrix(0,ncol=dim,nrow=dim)
for (i in c(1:dim)){
for (j in c(1:dim)) {
if (i==j) {X[i,j]<-a}
else { X[i,j]<- exp((
2011 Jul 29
2
change pch in 3dplot, export graph
Hello I was wondering if anyone has been able to change the pch value for
points in 3dplot()? I am able to change point colors just not symbol types.
I have included a portion of my code below. I realize this won't work
outside of my script, but thought, maybe there is something obvious that I
am doing wrong. Also is it possible to utilize the interactive feature of
3dplot in a
2011 Aug 10
2
Histograms in R
HI everyone,
I'm plotting a histogram in R and within that histogram i need to
demonstrate the percentage of another variable (Percentage of MutStatus)
within the bins plotted inthe histogram....I don't know how to do that!
Data:Validation_Status Mutation_Status TvarRatio
Wildtype None 0.08
Wildtype None 0.08
Wildtype None 0.08
Wildtype None 0.08
Wildtype None 0.080139373
Wildtype None