similar to: change rownames

Dear list, I'm trying to create a matrix by combining the sites that species occur in a new matrix with species as rows and sites as columns. The main matrix is "mat": mat <- as.data.frame(cbind(sp1=c(rep(0, 5), rep(1, 5)),sp2=sample(c(rep(0, 6),rep(1, 4))), fac=c(rep("a", 3), rep("b", 3),rep("c", 4)))) The first two columns are species and the

Dear All, I am not familiar with R yet I want to use it to perform some task, hence my posting here. I hope someone can help. I have a set of data, genes (rows) and samples (columns). I want to do a Pearson correlation on all the possible pairwise combinations of all the genes (2000). Does anyone have an idea of how to execute this in R? Thanks in advance. -- View this message in context:

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Hello, I'm hoping someone with a wide experience with R may be able to see what the program is trying to tell me. I've got an array: y1=rnorm(41,0.2) y2=rnorm(41,0.2) y3=rbind(y1,y2) data11<-array(0,c(41,2,2)) data11[,1,]=y3 data11[,2,]=y3 rownames(data11)<-rownames(data11, do.NULL = FALSE, prefix = "Obs.") colnames=c("V","R")

Hello, I am trying to help a colleague with an R problem (see below) to whit I can only generate a very inelegant solution. Any advice would be welcome. Thanks, Brian If you have two matrices, say a species by trait matrix (Matrix 1 below) and a plot by species matrix (Matrix 2 below), is there a straightforward way to prune one matrix so that the species list matches those in a

We were looking at conducting a pilot program with Dell to virtualize our lab environments. We are specifically looking at Dell/Citrix provisioning servers. The OS in this setup is streamed from the server on every boot. I was curious if the R Project had any licensing stipulations in this type of setup. This is in the beginning phases and we wanted to answer some questions about licensing.

Hi all, I think this might be an easy one but I cannot think of a way to do this other than what I am currently attempting. I simply want to sort my data frame's rownames by a defined vector so that the plots I generate from that vector are in the desired order Consider the test data below: #Create test data DataToPlot.. <- data.frame("Location1" =

I am getting an error message, which I do not know the source to. I have a matrix SAMPLES that has preexisting rownames that I would like to change. GENE_NAMES contains these rownames. > rownames(SAMPLES) = GENE_NAMES Error in "dimnames<-.data.frame"(`*tmp*`, value = list(list(V1 = c(3843, : invalid 'dimnames' given for data frame > dim(SAMPLES) [1] 12626

I noticed something surprising (in R 2.2.1 on WinXP) According to the documentation, rownames and colnames are character vectors. Assigning a vector of class POSIXct or POSIXlt as rownames or colnames therefore is not strictly according to the rules. In some cases, R performs a reasonable typecast, but in some other cases where the same typecast also would be possible, it does not. Assigning a

I noticed something surprising (in R 2.2.1 on WinXP) According to the documentation, rownames and colnames are character vectors. Assigning a vector of class POSIXct or POSIXlt as rownames or colnames therefore is not strictly according to the rules. In some cases, R performs a reasonable typecast, but in some other cases where the same typecast also would be possible, it does not. Assigning a

As I was working through elementary examples, I was using dataset "plasma" of package "HSAUR". In performing a logistic regression of the data, and making the diagnostic plots (R-2.5.0) data(plasma,package='HSAUR') plasma_1<- glm(ESR ~ fibrinogen * globulin, data=plasma, family=binomial()) layout(matrix(1:4,nrow=2)) plot(plasma_1) I find that data points

I find one row in my large dataset. But when I use the "rownames" for the data on the 100,000 row, the result show nothing. I try it by the following example, it still likes that. > tst[rownames(tst)==100000,] [1] x y <0 rows> (or 0-length row.names) ############## > tst=data.frame(x=1:200000,y=200000:1) > tst[rownames(tst)==1,] x y 1 1 200000 >

Hi guys, I am using the blp() function from RBloomberg package which returns a matrix of prices with the columns corresponding to the security name and the columns to the date. When I have a look at the matrix I can see the rownames (dates) on the left of the prices but when I call the rownames() function it returns me a NULL value. It worked perfectly until I had to reinstall the RBloomberg

Hi I want to extract rows of a matrix, and preserve rownames even if only one row is selected. Toy example: R> a <- matrix(1:9,3,3) R> rownames(a) <- letters[1:3] R> colnames(a) <- LETTERS[1:3] R> a A B C a 1 4 7 b 2 5 8 c 3 6 9 Extract the first two rows: R> wanted <- 1:2 R> a[wanted,] A B C a 1 4 7 b 2 5 8 rownames come through fine. Now extract just

Saludos, tengo un problema que no puedo resolver dentro del R Estoy creando una funcion que a partir de un objeto compuesto por diferentes matrices como el que esta a continuacion: [[1]] M1 M2 M3 M4 sp1 2 0 1 8 sp2 4 5 2 4 sp3 0 0 4 0 sp4 5 7 5 0 sp5 0 4 0 0 [[2]] M3 M2 M4 M1 sp1 1 0 8 2 sp2 2 5 4 4 sp3 4 0 0 0 sp4 5 7 0 5 sp5 0 4 0 0 [[3]]

Hello! Data.frames have new rownames funcionality, however in use of colnames<- in R-devel "changes" this. Here is the example: > df1 <- data.frame(letters[1:5]) > attributes(df1) $names [1] "letters.1.5." $row.names [1] 1 2 3 4 5 $class [1] "data.frame" > colnames(df1) <- "bla" > attributes(df1) $names [1] "bla"

Hi, I am working on some microarray data, and have some problems with writing iterations. In essence, the problem is that objects with three dimensions don't have rownames and colnames. These colnames and rownames would otherwise still be there in 2 dimensional objects. I need to generate multiple iterations of a 2 means-clustering algorithm, and these objects thus probably need 3

Hello, Here's my problem. I have a large data frame and a vector with some of its row names. I'd like to have a new data frame only with those rows that match this vector of row names. I tried this: data<-cbind(c(1,2,3,4,5,6),c(2,3,4,5,6,7)) rownames(data)<-c("a", "b", "c","d","e","f") names.to.keep<-c("a",

Hi, I'm quite new to R, so excuse me if this problem has a simple solution. I'm working with an array, lets say i <- array(c(1:3,3:1), dim=c(3,2)) Then I want to give the rows and the columns names: rownames(i)<-c("a","b","c") colnames(i)<-c("d","e") The result is given below: d e a 1 3 b 2 2 c 3 1 Here comes my problem.

Hi, On R 2.10.1 for Windows, when I do the following to duplicate the structure of a large numeric matrix called matrix1: matrix2 <- matrix(0,nrow=nrow(matrix1),ncol=ncol(matrix1)) and then rownames(matrix2) <- rownames(matrix1) I get a "cannot allocate vector of size xxMb" error but if I instead do: rnames <- list() rnames <- rownames(matrix1) matrix2 <-