similar to: group means: split and unsplit

I have a list that has about 50 elements, each repeated many times (a list of states by observation). I want to create a vector with the same length with the same value repeated over and over again within states. The value I want is the number of observations that are in the same state as each observation. In stata, this is simply egen statesum = count(state), by(state). What is the r

I want to do the following: glm(y ~ x1 + x2 +...) within a panel. Hence y, x1, and x2 all vary at the individual level. However, there is likely correlation of these variables within an individual, so standard errors need adjustment. I do not want to estimate fixed effects, but do want to cluster standard errors at the individual level. Is there an automated way to do this? Nothing in

I get the following when I try to run R from the terminal (I think ok from the gui, but not what I want to do): dyld: Symbol not found: __cg_jpeg_resync_to_restart Referenced from: /System/Library/Frameworks/ ApplicationServices.framework/Versions/A/Frameworks/ImageIO.framework/ Versions/A/ImageIO Expected in: /sw/lib/libJPEG.dylib Trace/BPT trap Any suggestions? I have installed the

It would be nice to have something like stata's outreg that lets regression output go into a form like Specification (1) Specification (2) Var 1 coef(1,1) coef(1,2) se(1,1) se(1,2) Var 2 coef(2,1) coef(2,2) se(2,1) se(2,2) I don't think this can be done in xtable? Thomas Davidoff Assistant Professor Haas School of Business UC Berkeley Berkeley, CA 94618 Phone: (510)

Sorry, couldn't resist... From: Gabor Grothendieck > > ov$vn1 is not a variable. It is the result of applying the $ > function to the ov and vn1 arguments. ... which would suggest: get("$")(get("ov"), "vn1"). 8-) Andy > For example, using BOD which is a data frame that comes with > R, rather than get("BOD$Time") use

Hello everyone, I use the split function splitting with the f function on a 3 columns and more than 100 000 rows data frame. Once it's split I have a list of data frames still with 3 columns and n rows. I manipulate those list elements and get a list of data frames still with 3 columns but less rows. So when I unsplit it, I get an error as I use the same factor function I used to split ( f in

Hedderik van Rijn <hedderik@cmu.edu> writes: > If the second argument to unsplit is not a simple vector (but a "list > containing multiple lists"), the function seems to have some problems. > > Given a slight modification of the examples in help(split): > > > xg <- split(x,list(g1=g,g2=g)) > > unsplit(xg,list(g1=g,g2=g)) > [1] -0.7877109

R-devel, Below is a simple example calling split and unsplit on a numeric vector of length 2 where 'f' is c(1,NA). > unsplit(split(c(1,2), c(1,NA)), c(1,NA)) [1] 1 0 I noticed that the call to vector in unsplit gives us 0 as the 2nd element of the result. Is this the intended result, as opposed to NA? Thanks for your help, Jeff -- Jeff Enos Kane Capital Management jeff at

What are the R equivalents to the Stata command egen tag and egen count? egen station_week_tag = tag(station week) Thank you

In data OME in MASS I would like to extract the first 5 observations per subject (=ID). So I do library(MASS) OMEsub <- split(OME, OME$ID) OMEsub <- lapply(OMEsub,function(x)x[1:5,]) unsplit(OMEsub, OME$ID) - which results in [[1]] [1] 1 1 1 1 1 [[2]] [1] 30 30 30 30 30 [[3]] [1] low low low low low Levels: N/A high low [[4]] [1] 35 35 40 40 45 [[5]] [1] coherent incoherent coherent

Perhaps this is the intended behavior, but I discovered that unsplit throws an error when it tries to set rownames of a variable that has no dimension. This occurs when unsplit is passed a list of data.frames that have only a single column. An example: df <- data.frame(letters[seq(25)]) fac <- rep(seq(5), 5) unsplit(split(df, fac), fac) For reference, I'm using R version 2.9.0

Hello, using the `unsplit()` function with tibbles currently leads to the following error: > mtcars_tb <- as_tibble(mtcars, rownames = NULL) > s <- split(mtcars_tb, mtcars_tb$gear) > unsplit(s, mtcars_tb$gear) Error: Must subset rows with a valid subscript vector. ? Logical subscripts must match the size of the indexed input. x Input has size 15 but subscript `rep(NA, len)` has

I get the sentiment, but this is really just bad coding (on my own part, I suspect), so we might as well just fix it... -pd > On 21 Nov 2020, at 17:42 , Marc Schwartz via R-devel <r-devel at r-project.org> wrote: > > >> On Nov 21, 2020, at 10:55 AM, Mario Annau <mario.annau at gmail.com> wrote: >> >> Hello, >> >> using the `unsplit()`

Hi everyone, I have already used split() and unsplit() in data frames without problems, but now I’m applying these functions to other data and when using unsplit() I have received the following message: Error in `row.names<-.data.frame`(`*tmp*`, value = c("1", "2", "3", "4", : duplicate ''row.names'' are not allowed In

Dear R-bug-people I have encountered a problem with "unsplit", which I believe may be caused by a bug in the function. However, unexpericend with bug-reports I apologise if this is barely a user problem rather than a problem within R. The problem occurs if an object is split by several grouping factors with levels not occuring in the data, and using drop = TRUE. This may appear as

> On Nov 21, 2020, at 10:55 AM, Mario Annau <mario.annau at gmail.com> wrote: > > Hello, > > using the `unsplit()` function with tibbles currently leads to the > following error: > >> mtcars_tb <- as_tibble(mtcars, rownames = NULL) >> s <- split(mtcars_tb, mtcars_tb$gear) >> unsplit(s, mtcars_tb$gear) > Error: Must subset rows with a valid

(only of interest -- maybe! -- to those who followed this thread of a couple of weeks ago) Just for the heckuva it, I compared the timing of Deepayan's unsplit(x,f) solution to my as.vector(do.call(rbind, x)) approach to the query for a list of 3 vectors each of length 1000 (the original toy example was for a list of 3 vectors of length 5). Unsurprisingly, I think, because the unsplit()

Cool - thank you Peter! @Marc: This is really not a tidyverse vs base-R debate and I personally think that they should both work together for most parts. The common environment is still R. But just to give you the full picture I also filed a bug for tibbles (https://github.com/tidyverse/tibble/issues/829). With these two fixes I think that split/unsplit would work for tibbles and users (like me)

Hedderik van Rijn <hedderik@cmu.edu> writes: > > Thanks for pointing this out. I think your code should work, although > > I'm slightly uneasy about actually modifying f, so how about > > Just curious, why are you uneasy about that? Does it have side effects? It is largely due superstition, but if you change f before calling split<-() you have split() and

Dear R listers, I am trying to create a new variable that uniquely identifies groups of observations in a dataset. So far I couldn't figure out how to do this in R. In Stata I would simply type: egen newvar = group(dim1, dim2, dim3) Please, find below a quick example to show what I am dealing with: I have a dataset with 4 variables: var <- runif(50) ## a variable that I want to group