similar to: Subsetting a zooreg object using window / subset

Hello R-Users I am struggling with this line plot, it might be simple but I am missing something here. First of all I want to make multiple line plots across seasons (DJF,MAM,JJA,SON) for 12 variables (here, called nodes) and fill them with the node. So that season=x-axis, node=line col and freq=y-axis. My plot currently links all DJFs, MAMs, JJAs and SONs, however I will like them to be

Mathew Brown Institute of Bioclimatology University of G?ttingen B?sgenweg 2 37077 G?ttingen, Germany t: +49 551 39 9359 mathew.brown at forst.uni-goettingen.de On 9/24/2011 6:00 PM, r-help-request at r-project.org wrote: > Send R-help mailing list submissions to > r-help at r-project.org > > To subscribe or unsubscribe via the World Wide Web, visit >

Hi there I'm working with ncdf data. I have different dataset for 4 runs, 4 seasons and 3 timeslices (48 datasets in total). The datasets have the following dimensions: 96 longitudes, 48 latitudes and 30 time steps. To read all of them in, I wrote the following loop: runs <- c("03","04","05","06") years <- c(1851,1961,2061) seasons <-

Dear R users, I have a quick question regarding creating an index for a zoo object. I am using R 2.12 on winxp. I have read through the R archives searching for information on dates and time series analysis and nothing seems to cover my question. I am extracting data from a time series of remote sensing data. The frequency of the data is 16 days which means I cant use ts (ts likes months single

Hi all and thanks for your time in advance, I can't figure out why summary.lmrob complains when lmrob is used on a zooreg object. If the zooreg object is converted to vector before calling lmrob, no problems appear. Let me clarify this with an example: >library(robustbase) >library(zoo) >dad<-c(801.4625,527.2062,545.2250,608.2313,633.8875,575.9500,797.0500,706.4188,

Hello, Can anyone explain the following behaviour? To me it seems a bug, but maybe it is intentional. It seems that a diff on a zooreg class that is not _strictly_ regular only considers those entries that are 'deltat' apart. In the following, diff on the zooreg class only returns values where the index was one second apart. The example replicates by dev code, but I've also tested

I create a zooreg object that runs from Jan-1-2002 0:00 to Jun-1-2005 0:00... regts.start = ISOdatetime(2002, 1, 1, hour=0, min=0, sec=0, tz="") regts.end = ISOdatetime(2005, 6, 1, hour=0, min=0, sec=0, tz="") regts.zoo <- zooreg( NA, regts.start, regts.end, deltat=3600 ) Upon inspection: > regts.zoo[1:3] 2002-01-01 00:00:00 2002-01-01 01:00:00 2002-01-01 02:00:00

I am trying to extract only the winters (defined to be 01-Dec through 28-Feb) of daily data from 1948-2002. There are 90 days in each winter season. I wrote the following code to gather the winter dates into a single vector: DJF <- NULL for(year in 1949:1999) { temp.begin <- strptime(paste("01/12", year-1, sep="/"), "%d/%m/%Y") temp.end <-

Dear all Im new in R I have a necdf data set that I want to plot : this is my data set [1] "file Tmax.DJF.daily.1981_1999.echama2.nc has 4 dimensions:" [1] "longitude Size: 127" [1] "latitude Size: 110" [1] "ht Size: 1" [1] "t Size: 1680" [1] "------------------------" [1] "file Tmax.DJF.daily.1981_1999.echama2.nc has 1

Dear R users, I am a remote sensing researcher currently studying the use of LiDAR data for quantifying tree height, in particular I would like to determine the sample size needed to capture and quantify canopy height variability. To do this I have employed the use of automap(), which automatically calculates variograms including reporting the range of the variogram. The program is easy to use

Dear all, I would like to know how can I concatenate 2 data.frames into a single one. Both data frames have the same number of columns and the same class type in each correspondent column. So what I want is to have a new data.frame where I have first the values from one data.frame and then the values from a second data.frame would came after in this new data.frame. Thanks in advance. Med

I have a zooreg object and I want to be able to generate a value for seasons and 11-day composites paste it onto my zoo data frame, along with year, month and days. Right now I have the following to work from: eg. dat.zoo.mdy <- with(month.day.year(time(dat.zoo)), cbind(dat.zoo, year, month, day, quarter = (month - 1) %/% 3 + 1, dow = as.numeric(format(time(dat.zoo), "%w")))) For

I have *** attached *** an RData file containing an R object that is acting strangely. Try this in a fresh workspace. Do not load zoo or any other package. We load the object, zz2, from the attached RData file. It is just the number 1 with the class c("zooreg", "zoo"). Now create an S3 print routine that simply prints an X when given an object of class "zoo". If

Dear R users I am currently investigating time series analysis using an irregular time series. Our study is looking at vegetation change in areas of alien vegetation growth after clearing events. The irregular time series is sourced from Landsat ETM+ data, over a six year period I have 38 scenes. For certain periods I have monthly data while for others, images are up to three months apart. So far

Dear all, please consider my following workbook: library(zoo) lis1 <- vector('list', length = 2) lis2 <- vector('list', length = 2) lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1) lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency = 12) lis2[[1]] <- matrix(1:40, 20) lis2[[2]] <-

Hi all, I've got a list of files from 1914 to 2000. For each file, I can call the read.table function as follows. > file <- read.table("1914.txt") But I want to make a script so that at the end of the loop, the script selects the file 1915.txt, 1916.txt and so on. I've used seq() to create the increment seq <- paste(seq(1914, 2006, by=1), "*.txt.h",

No he podido crear una matriz con dos columnas una de fechas y la otra columna con números de casos de una enfermedad x library(zoo) zooreg(1:300, start = as.Date("2012-03-01")) cbind(zooreg(1:300, start = as.Date("2012-03-01")) , c(1:300)) #?como incluir un vector o una ts? -- Este mensaje le ha llegado mediante el servicio de correo electronico que

Dear R community, I have the following two zoo objects: MONTHLY CPI > plot(z) > par("usr") [1] 1977.76333 2011.15333 70.39856 227.03744 > z=zooreg(cpius$Value,as.yearmon("1979-11"),frequency=12) > str(z) ?zooreg? series from Nov 1979 to Oct 2010 Data: num [1:372] 76.2 77 77.8 78.5 79.5 80.3 81.1 82 82 82.6 ... Index: Class 'yearmon' num [1:372]

Hi, I'm trying to plot the forecasts I generated using the Plot.Fore function of the BootPR package. But I got an error from zoo: My data: Time Series: Start = 1 End = 18 Frequency = 1 [1] 38731 38628 39117 92809 71984 31226 58613 72360 107956 92066 [11] 95208 99098 95848 120383 110717 105680 98469 101916 Script: y1<-ts(y1);

R-listers, I am using xts with a yearmon index, but am getting some inconsistent results with the date index when i drop observations (for example by using na.omit). The issue is illustrated in the example below. If I start with a monthly zooreg series starting in 2009, yearmon converts this to "Dec-2008". Not such a worry for my example, but strange. Having converted to xts, i drop