similar to: Weighted Average on More than One Variable in Data Frame

Dear R-users, I am trying to translate a matlab code for calculating the Local Whittle estimator in time series with long memory originally written by Shimotsu and available free in his webpage ( http://www.econ.queensu.ca/pub/faculty/shimotsu/ ) The Matlab code is ======================================================================================= function[r] = whittle(d,x,m) % WHITTLE.M

Hi R experts, I need know how calculate a weighted mean by group in a data frame. I have tried with aggragate() function: data.frame(x=c(15,12,3,10,10),g=c(1,1,1,2,2,3,3),w=c(2,3,1,5,5,2,5)) -> d aggregate(d$x,by=list(d$g),weighted.mean,w=d$w) Generating the following error: Error en FUN(X[[1L]], ...) : 'x' and 'w' must have the same length Thanks in advance [[alternative

Hi everyone, I'm a newbie to centos and having trouble upgrading java's jdk1.4 to jdk1.5. I assume I have to get the jdk from jpackage, but I'm having trouble locating it, let alone finding any instructions on how to upgrade. Much appreciated if anyone can help. Thanks!

I am attempting to build from a src.rpm (knowing very little about rpm at all) and the spec file notes that the architecture should be set on the command line: > # platform defines - set one below or define the build_xxx on the command line Now. My question is this, how does one do this using rpmbuild? The syntax rpmbuild --target centos4 package.src.rpm seemingly has no effect.

Hi This is a very small patch that seems to solve that "Exit the app and get a segfault in return" problem. Another thing: bigdemo.rb:395 does item = event.get_item() if item.is_ok but get_item typemaps TreeItemId into a plain integer, so it doesn''t have is_ok method anymore, is there any wxruby2''yish solution to this kind of problem ? A.K. In case

Hello everyone, I have tried several ways of doing this and searched the documentation and help lists and I have been unable to find an answer or even whether it is possible to do it. I am pasting together a formula and I need to insert double quotes around the strings. Here's an example: location <- c("AL", "AK", "MA", "PA") v=2 test <-

Hi, I'm having trouble getting my Palm to sync with jpilot on my Centos system via USB. When I sync, I get this error in jpilot: pi_accept Illegal seek Exiting with status SYNC_ERROR_PI_ACCEPT Finished I have jpilot syncing fine with this Palm over the network, BTW. For USB, I set things up for udev as described on various websites. Here are the relevant ports & symlink (created

Hi Attached is a patch that adds aliases to the API for methods that look like attribute accessors. So a_frame.set_title(''The title'') # currently a_frame.title = ''The title'' # now an alternative textctrl.get_value # currently textctrl.value # now an alternative Also, C++ methods named ''IsXXX'' are now exposed in ruby with

Hello everyone, I am trying to figure out a way of replacing missing observations in one of the variables of a data frame by values of another variable. For example, assume my data is X X <-as.data.frame(matrix(c(9, 6, 1, 3, 9, "NA", "NA","NA","NA","NA", 6, 4, 3,"NA", "NA", "NA", 5, 4, 1, 3),

Greetings R Users, I have a system of equations for which I would like to output all the R-squares. Assume there are four equations in my system, the only way I found to output all the R-squares is by calling them out one by one as this: summary(fitSUR$eq[[1]])$r.squared summary(fitSUR$eq[[2]])$r.squared summary(fitSUR$eq[[3]])$r.squared summary(fitSUR$eq[[4]])$r.squared But isn't there a

Hi, I was asking about php 5.2 because I would like to use this program with these requirements: http://www.magentocommerce.com/system-requirements This ecommerce store is built with the zend framework and requires php 5.2. Mcrypt is not in the centos mirrors either. I did manage to get this beta ecommerce store installed on php 5.1.6-12 by removing the mycript line in the install xml file and

Dear all, I would like to know how can I create a binned column in a data.frame. The output that I would like is something like this: Start Binned_Start 1 0-5 2 0-5 6 5-10 8 5-10 13 10-15 ... Best regards João Fadista Ph.d. student UNIVERSITY OF AARHUS Faculty of Agricultural Sciences Dept. of Genetics and Biotechnology Blichers

I have a list called "tabs" that I would like to have the same structure as my list "eqSystem." The two look like they have the same format but they are different because when I look at their attributes, class(eqSystem[[1]]) is "call" but class(tabs[[1]]) is "formula". I want to have class(tabs[[1]]) as a call too. So what does "call" mean? And how

fitz_ra wrote > I know this is posted a lot, I've been through about 40 messages reading > how to do this so let me apologize in advance because I can't get this > operation to work unlike the many examples shown. > > I have a 2 row matrix >> temp > [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] > [,9] [,10] > [1,] 17.000

Dear all, Sorry for bringing up an old issue: >pexp(50, 0.5) [1] 1 In some cases, pexp() gives CDF=1. I read some discussion in 2002 saying it has been patched. However it's not working in "R2.4.1Patched". Could anyone help me out? Thanks a lot, Jeann _________________________________________________________________ Fine Dining & Fancy Food. Check Out This

The summary stats for the xin and yin variables below are correct. However, if I use plot(xin,yin), an exception is thrown saying that "object xin is not found." Also, it is apparent that I can't successfully replace the x and y vectors with values from xin and yin. The four plots on one panel are showing but the range of x and y is only [0,1], and therefore, it seems like an

Hi, I have a matrix with column names starting with a character in [0-9]. After some matrix operations (e.g. copy to another matrix), R seems to add a character 'X' in front of the column name. Is this a normal default behaviour of R? Why has it got this behaviour? Can it be changed? What would be the side effect? Thank you. Regards, Gilbert [[alternative HTML version deleted]]

Hi, is there a way I can calculate a summary statistics for a columns matrix let say we have this matrix x <- matrix(sample(1:8000),nrow=100) colnames(x)<- paste("Col",1:ncol(x),sep="") if I used summary summary(x) i get the output for each column but I need the output to be in matrix with rownames and all the columns beside it this how I want it

Hi R-users: [R 2.2 on OSX 10.4.3] I have a (sparse) vegetation data frame with 500 rows (sampling units) and 177 columns (plant species) where the data represent % cover. I need to summarize the cover data by returning the names of the most dominant and the second most dominant species per plot. I reduced the data frame to omit cover below 5%; this is what it looks like stacked. I have

Dear R users, I have a function (simplified here) that accepts two arguments and performs various calculations: foo <- function(y, x) { a <- y*sqrt(x) b <- a+2 c <- a*b return(c) } If I call the function as follows I get the result I desire: > foo(.1, 1:12) [1] 0.2100000 0.3028427 0.3764102 0.4400000 0.4972136 0.5498979 0.5991503 0.6456854 0.6900000 0.7324555 0.7733250