similar to: Help: RH9 upgrade (mbox)

Displaying 20 results from an estimated 20000 matches similar to: "Help: RH9 upgrade (mbox)"

2007 Mar 02
2
MBOX to MAILDIR conversion
Thinking about going from mbox to maildir. Started with mbox way back when but thinking about making the conversion. The main reason is that I use rsync for backups and when these huge mailboxes are touched I have to copy the whole thing. With maildir I only copy the files that change. So - my questions is - what's the easiest way to make this happan. I assume there are conversion
2007 May 17
1
Wiki relating to subscriptions
On this wiki page http://wiki.dovecot.org/Migration/UW appears this information: "It's possible to keep using the .mailboxlist}} filename (as long as it's in the same directory) by modifying {{{SUBSCRIPTION_FILE_NAME define in src/lib-storage/index/mbox/mbox-storage.h" However, if a user wanted to continue using .mailboxlist wouldn't they also have to change the
2005 Apr 14
5
dovecot rpms, .subscriptions file, mbox to maildir
Hi, I am running dovecot 0.99-14 on a Fedora Core 2 machine. I had a few questions: 1) I wanted to upgrade to the dovecot-1.0 release. However, I am not sure if that's really required. dovecot-0.99-14 has been running very well for me for quite some time. Is there a real advantage to switching to the latest release. The reason I'm asking this is because: i) I don't have too
2007 Feb 20
1
Dovecot losing .mailboxlist files
Hello! I am running a site that has two servers, 10 000 users in both, Solaris 9 and home directories with mbox mailboxes shared with NFS. Indexes are kept separately in both server, on local disks, both servers are serving imap (from NFS mboxes). We are trying to convert from uw-imap to dovecot. Servers are currently running on their limits and now i have mysterious problems with
2012 Mar 14
4
.mailboxlist -> .subscriptions
I've mostly finished a conversion from an old Centos 3 UW-Imap server to a new Centos 6 dovecot server. I did not copy the old ~/.mailboxlist file to ~/mail/.subscriptions file, but notice some users have the latter file now. These are all mbox folders on the old and new server. I'm getting ready to do the same to another old/new pair of servers and I'm wondering if there is an
2010 Jan 28
2
Data frame of different sized lists in a function call
I'm hoping to get some "best practice" feedback for constructing a function call which takes an undefined set of DIFFERENT length vectors -- e.g. say we have two lists: list1=c(1:10) list2=c(2:4) lists = data.frame(list1,list2) coerces those two to be the same length (recycling list2 to fill in the missing rows) -- what is a quick way of having each of those lists retain their
2006 Oct 17
2
Subscription file
Background: We are a UW-IMAP shop, using mbox format. (!) We are in the process of upgrading to Dovecot, hopefully to 1.0 proper. :) One of the modifications we have been using in test versions of Dovecot involve the move of the user subscription file from: IMAP-root/.subscriptions to: $HOME/.mailboxlist Rather than having to make changes to Dovecot source code each time a new release
2003 Feb 27
2
IMAP Folder paths
Hello, we like to use dovecot, but our old imapd used to store the paths of the folder in the file ~/.mailboxlist. This file contains something like this: mail/read mail/dovecot .netscape/imap/mailbox .Mail/foo Each line with a path to one mbox folder. And please pay attention that there is no path to the inbox, because this is stored on the server... Is there a way to use this
2007 May 16
2
substitute "x" for "pattern" in a list, while preservign list "structure". lapply, gsub, list...?
I am experimenting with some of the common r functions. I had a question re:using "gsub" (or some similar functions) on the contents of a list. I want to design a function that looks at "everything" contained din a list, and anytime it finds the text string "pattern" replace it with "x". I also wish to preserve the "structure" of the original
2010 Feb 26
3
Preserving lists in a function
Dear R users, A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults. However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R: myfunction=function( list1=list
2007 Nov 26
2
upgrade from version 1.0.3 to version 1.0.7
Im working on upgrading to dovecot-1.0.7 from version 1.0.3 which I installed using yum. I backed up my init.d stuff so everything still works. However, when I shutdown my old dovecot version and start the new, I get an empty mailbox when logging into mail. My current config for dovecot.conf on version 1.0.3 has this for my mailbox location:mail_location = mbox:~/:INBOX=/var/mail/%u
2009 Oct 30
2
Names of list members in a plot using sapply
Hi R users: I got this code to generate a graphic for each member of a lists. list1<-list(A=data.frame(x=c(1,2),y=c(5,6)),B=data.frame(x=c(8,9),y=c(12,6))) names1<-names(list1) sapply(1:length(list1),function(i) with(list1[[i]],plot(x,y,type="l",main=paste("Graphic of",names1[i])))) Is there a more elegant solution for not to use two separate lists? I would like to
2010 Mar 15
1
rbind, data.frame, classes
Hi, This has bugged me for a bit. First question is how to keep classes with rbind, and second question is how to properly return vecotrs instead of lists after turning an rbind of lists into a data.frame list1=list(a=2, b=as.Date("20090102", format="%Y%m%d")) list2=list(a=2, b=as.Date("20090102", format="%Y%m%d")) rbind(list1, list2) #this loses the
2013 Jan 10
1
merging command
HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-colSums(x, na.rm=FALSE) z<-matrix(y,ncol=10) ?z<-as.dist(z) ?z ?# ?? 1?? 2?? 3?? 4?? 5??
2007 Oct 15
1
The "condition has length > 1" issue for lists
I have the following code: list1 <- list() for (i in list.files(pattern="filename1")){ x <- read.table(i) list1[[i]] <- x } list2 <- list() for (i in list.files(pattern="filename2*")){ x <- read.table(i) list2[[i]] <- x } anslist <- vector('list', length(list1)) for(i in 1:length(list1)) if (list1[[i]] & list2[[i]] >1)
2011 Jan 20
1
syntax for a list of components from a list
I'm attempting to generalise a function that reads individual list components, in this case they are matrices, and converts them into 3 dimensional array. I can input each matrix individually, but want to do it for about 1,000 of them ... This works array2 <- abind(list1[[1]],list1[[2]],list1[[3]],along=3) This doesn't array2 <- abind(list1[[1:3]],along=3) This doesn't either
2011 Nov 21
1
Creating a list from all combinations of two lists
R-helpers: Say I have two lists of arbitrary elements, e.g.: list1=list(c(1:3),"R is fun!",c(3:6)) list2=list(c(10:5),c(5:3),c(13,5),"I am so confused") I would like to produce a single new list that is composed of all combinations of the "top level" of list1 and list2, e.g.: listcombo=list(list(list1[[1]],list2[[1]]),list(list1[[1]],list2[[2]]
2011 Feb 06
1
Applying 'cbind/rbind' among different list object
Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent** list objects. For example please consider following: > list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2) <- c("a", "b") > list1[[1]] <- matrix(1:25, 5) > list1[[2]] <- matrix(2:26, 5) > list2[[1]] <- 10:14 > list2[[2]] <-
2012 Apr 19
1
question about lists
I am new to R, and I have been running into the following situation when I mistype a variable name in some code: > list1 <- list( a=1, b=2 ) > list2 <- list( a=1 ) > list2$b <- list1$c > list2 $a [1] 1 I would think at the point where I am trying to reference a field called "c" -- that does not exist -- in list1, there would be an error flagged. Instead, list1$c
2011 Feb 08
2
Extrcat selected rows from a list
Hi, I have two lists 1) List1- 30,000 rows and 104 columns 2) List2- a list of 14000 selected rownames  from List 1 Now, I want to extract all the 104 columns of List1  matching with the 14000 selected rownames from List2.  Psedocode will be something like this: match rownames(List2) with rownames(List1) extract selected matched 104 coloumns from (List1) strore in-> List3 So the