similar to: counting the duplicates in an object of list

Hi, I have a file like this: 1 2 0.1 2 3 0.2 3 1 0.3 And I want to read it to create a matrix like this: [,1] [,2] [,3] [1,] 0 0.1 0 [2,] 0 0 0.2 [3,] 0.3 0 0 How can I do it efficiently? Thanks. -- Best, Zhenjiang [[alternative HTML version deleted]]

Hi R users, suppose I have two vectors, > x=c(1,2,3,4,5) > y=c('a','b','c','a','c') How can I get a data.frame like this? > xy count a 5 b 2 c 8 I know a few ways to fulfill the task. However, I have a huge number of this kind calculations, so I'd like an efficient solution. Thanks -- Best, Zhenjiang

here's my question: suppose I have a matrix: mt<-matrix(1:12,ncol=6) now I have a vector vt<-c(1,2,2,2,1,2) which means I want to get: the 1st row for column1; the 2nd row for column2; the 2nd row for column3; the 2nd row for column4; ... that what I want is this vector: 1,4,6,8,9,12 Does anyone know how to do this fast? I know I can use for-loop to travel all columns,but

Hi R users, I have a list: > x $A [1] "a" "b" "c" $B [1] "b" "c" $C [1] "c" I want to convert it to a lowercase-to-uppercase list like this: > y $a [1] "A" $b [1] "A" "B" $c [1] "A" "B" "C" In a word, I want to reverse the list names and the elements under each

Hi, For example, the data.frame like: origdata.long <- read.table(header=T, con <- textConnection(' subject sex condition measurement 1 M control 7.9 1 M first 12.3 1 M second 10.7 2 F control 6.3 2 F first 10.6 2 F second 11.1 3 F control 9.5 3

Hi, I have a for loop to make 2 types of plots and I'd like to save one type of plots to a pdf file and the other to another pdf file. How can I control which plot will be saved to which pdf? Thanks -- Best, Zhenjiang

Hi all, Suppose I have 2 data.frame , a and b, how can I add them together to get c? Thanks > a A a 1 b 2 c 3 > b A a 6 c 1 > c A a 7 b 2 c 4 -- Best, Zhenjiang [[alternative HTML version deleted]]

Hi R users, Suppose I have two lists and the names of list 'm' are a subset of those of 'n', how can I sum the two lists with corresponding elements added together to get list 'o'? > n = list("a"=1,"b"=3,"c"=5) > m = list('b'=4) > o $a [1] 1 $b [1] 7 $c [1] 5 Thanks -- Best, Zhenjiang [[alternative HTML version

Hi all, When running R interactively, I have the problem as following: > library(ggplot2) Loading required package: reshape Loading required package: plyr Attaching package: 'reshape' The following object(s) are masked from 'package:plyr': round_any Loading required package: grid Loading required package: proto > data(VADeaths) > pg <- ggplot(melt(VADeaths),

Hi R users, I was using read.table to read a file. The data.fame looked alright, but I found not all rows are read by the read.table. What's wrong with it? It didn't give me any warning or error messages. Why the data are truncated? Thanks. $ wc -l all/isoform_exp.diff 42847 all/isoform_exp.diff > a=read.table('all/isoform_exp.diff', header=T, sep='\t') > nrow(a)

It looks like the 'seq' variable to 'for' can be altered from within the loop, leading to incorrect answers. E.g., in the following I'd expect 'sum' to be 1+2=3, but R 2.10.0 (svn 48686) gives 44.5. > x = c(1,2); sum = 0; for (i in x) { x[i+1] = i + 42.5; sum = sum + i }; sum [1] 44.5 or, with a debugging cat()s, > x = c(1,2); sum = 0; for (i in x) {

If x has an S3 class then sort.int(x) returns a value without an S3 class but which has the is.object flag set, which, I think, causes identical() give a false/misleading report: > x <- structure(1:3, class="unrecognizedClass") > y <- sort.int(x) > t <- 1:3 > identical(y, t) # expect TRUE [1] FALSE > identical(as.vector(y), as.vector(t)) # expect

I think the following rather wierd expressions show a problem in how some of the .Primitive functions evaluate their arguments. I haven't yet thought of a way that a nonabusive user might run into this problem. In each case the first argument, x, is modified in the course of evaluating the second argument and then modified x gets used as the first argument: > x<-as.integer(1:5); y

Dear R users, I am trying to use the following code to make a barchar plot. The bars in the plot turn out to be a little narrow. Is there any way to modify the width of the bars? Thank you! library(lattice) scores = gl(2, 5, label=c('Sensitivity', 'PPV'), length = 100) sequences = gl(5, 1, label=c('Lemna minor', 'Dugesia japonica A', 'Gymnosporangium

Hello everyone, I have a time serie of n values, some are na's. I want to get a vector of size n whose elements represent on the time t < n the number of missing values between o and t. I know I can do it with a loop but I wanted to know if there was a function or a special syntax to do this. Thanks a lot! -- View this message in context:

One of our R users here just showed me the following problem while investigating the return value of a while loop. I added some information on a similar bug in for loops. I think he was using 2.9.0 but I see the same problem on today's development version of 2.10.0 (svn 48703). Should the semantics of while and for loops be changed slightly to avoid the memory buildup that fixing this to

Hi, I am sure there is an easy way to do it, but I can't find it. I have a data frame that has 15 columns and 7000 rows. The only values inside the data.frame are "aa", "ab", "bb" as you can see an example bellow. 1 2 3 1 aa ab ab 2 ab ab ab 3 aa aa aa 4 bb bb bb What I would like to do, is to generate a vector (or another data.frame) with 7000 rows, and 3

*Hi all, * *Assume that I have the following data set with tow variables and I want count the number of observation with identical values * ** *x1 x2* * 1 1 * * 1 0 * * 0 1* * 0 1* * 0 0* * 1 1* * 0 1 * I want the following output ** * * *n1=3 # number of identical observation between x1 and x2 variables* *n2=4 # number of different observation* How do I do it in

Hi R users, where can I find the equations used by acf function to calculate autocorrelation? I think I misunderstand acf. Doesn't acf use following equation to calculate autocorrelation? [image: R(\tau) = \frac{\operatorname{E}[(X_t - \mu)(X_{t+\tau} - \mu)]}{\sigma^2}\, ,] If it does, then the autocorrelation of a sine function should give a cosine; however, the following code gives a

R experts, Is there anyway to reorder inside each group? In the following example, the bar of year 1932 is always plotted before the bar of year 1931, may I change the order inside each groups of bars? library(lattice) barchart(yield ~ variety | site,data=barley, groups = year, layout = c(1,6),auto.key = list(points = FALSE, rectangles = TRUE, space = "right"),ylab = "Barley Yield