similar to: Showing zero frequencies with xtabs

Displaying 20 results from an estimated 4000 matches similar to: "Showing zero frequencies with xtabs"

2011 Aug 28
4
How do I get a weighted frequency table?
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2002 Jun 19
4
levels() counter-intuitif? (PR#1693)
Suppose I have a factor size with levels "small", "medium" and "large". Then, when I subset this factor: >ss<-size[size!="medium"] to get at the extremes, >levels(ss) .... Levels: large medium small The same happens with >subset( size, size!="medium") I understand that the resulting factor inherits the possible levels from its
2010 Dec 20
2
tabulating 2 factors weighting by a third var
Hi, This must be an easy one but so far I haven't find a way out... I have a data frame such as: $ v1 : Factor w/ 5 levels $ v2 : Factor w/ 2 levels $ v3 : Class 'difftime' atomic [1:6666] basically v1 and v2 are factors, while v3 is a variable containing the duration of certain activities (values ranging from 11 to 45000 sec, no missing values) How can I get a table
2012 Nov 30
3
Reading .gsheet within R
Hello R-experts, I would like to know if there is a solution to read files with extension .gsheet directly into R - see http://www.fileinfo.com/extension/gsheet for more info on this file format. Thank you, Luca Mr. Luca Meyer www.lucameyer.com R 2.15.1 Mac OS X 10.8.2 [[alternative HTML version deleted]]
2011 Aug 16
1
getting names of dimnames of xtabs into xtable latex output
In R, the output of xtabs displays the names of the dimnames. In the example below, these are "change_diet" and "mydiet". Is there a way to have xtable incorporate these names directly into the latex output. Thanks for your help. table2 <- structure(c(26, 0, 40, 0, 10, 0, 188, 0, 281, 0), .Dim = c(5L, 2L), .Dimnames = structure(list(change_diet = c("Don't
2012 Feb 22
1
Multiple lines for each record: how do I handle that
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2003 May 14
2
how to include 'NA's in xtabs?
Hello! I have a dataset with NA's in some variables (factors), for example: $ P67 : Factor w/ 2 levels "-","+": NA 2 1 NA NA 2 1 1 2 NA ... I need to use 'xtabs' like xtabs(~x$P67) It works well and produces something like this: x$P67 - + 779 1318 but i want to compute NA's too, like this: x$P67 - + NA 779 1318 137 I am trying
2012 Aug 30
4
Leading plus in numeric fields
Hello R experts, I have go this data frame: 'data.frame': 1 obs. of 20 variables: $ Anno : chr "PREVISIONI VS TARGET" $ OreTot: num 41 $ GioTot: logi NA $ OrGTot: logi NA $ OreCli: num 99 $ GioCli: logi NA $ OrGCli: logi NA $ OreFor: num -27 $ GioFor: logi NA $ OrGFor: logi NA $ OreOrt: num -18 $ GioOrt: logi NA $ OrGOrt: logi NA $ OreSpo: num -6 $ GioSpo: logi
2009 Apr 24
2
argument 'exclude' in function xtabs
Dear all I was willing to use argument 'exclude' in function xtabs to remove some levels of factors (xtabs help page says '"exclude: a vector of values to be excluded when forming the set of levels of the classifying factors"). I tried: > mydata <- data.frame( treatment = c("B", "A", "C", "C", "B",
2009 Sep 04
1
Problem with xtabs(), exclude=NULL, and counting NA's
Hi all, I cannot get xtabs to count NA's like I expect. Below is a sample session, and note that the last two calls to xtabs() yield exactly the same thing. I am running R-2.5.0 -- if there was a bug in xtabs that got fixed, I would love to know about it. If there is a bug tracker somewhere, I can file it too. It isn't my fault that the server is so ridiculously outdated, but I would
2009 Dec 13
1
xtabs - missing combination
Dear list, I am trying to make a contingency table with xtabs but I am getting a 0 where I expect a 'NA'. Here is a simple example: options(stringsAsFactors = FALSE) rn <- LETTERS[1:4] df1 <- data.frame(r07 = rep(rn, each=4), r08 = rep(rn, 4), value = 1:16) xtabs(value ~ r07 + r08, df1) # Delete the combination [A, C] df1 <- df1[-3,] # Set 'value'
2015 Feb 09
3
xtabs and NA
Hi I haven't found a way to produce a tabulation from factor data with NA values using xtabs. Please find a minimal example below, it's also on R-pubs [1]. Tested with R 3.1.2 and R-devel r67720. It doesn't seem to be documented explicitly that it's not supported. From reading the code [2] it looks like the relevant call to table() doesn't set the "useNA"
2003 Aug 16
2
xtabs to dataframe fails (PR#3754)
Full_Name: Daniel Frey Version: 1.7.1 OS: Windows 2000 Submission from: (NULL) (80.254.164.242) Generating a data frame out of a xtabs result acts unusual. Take the following sample to reproduce it: > a.a <- c("a","a","a","b","b") > a.b <- c("c","c","d","e","f") >
2017 Jan 19
2
xtabs(), factors and NAs
Hi all, I know this issue has been discussed a few times in the past already, but Martin Maechler suggested in a bug report [1] that I raise it here. Basically, there is no (easy) way of printing NAs for all variables when calling xtabs() on factors. Passing 'exclude=NULL, na.action=na.pass' works for character vectors, but not for factors. > test <-
2010 Apr 18
3
xtabs() of proportions, and naming a dimension (not a row)
Hi, xtabs() creates a table of counts. I want a table of proportions -- that is, I want to divide every vector (along a particular dimension) by its sum. The tiny example below does that. The call to xtabs() creates a matrix "A" with dimensions ("x1","x2","y"). I transform "A" using aperm() and aaply() to get the matrix "B". The
2001 Aug 05
2
xtabs, drop.unused.levels (PR#1041)
Full_Name: Martin Lenze Version: 1.3.0 22.06.2001 OS: win32,x86 Submission from: (NULL) (194.221.251.1) As a newbie I'm not sure, whether this is a bug, but I don't know how to get around this behaviour: > x <- list("A"=rep(c(1:5),30), + "B"=c(rep(letters[1:3],30),rep(letters[2:4],20))) > y <- as.data.frame(x) > xtabs(~A+B,y) B A a b c d 1 6 10
2001 Apr 03
2
Parse error in xtabs
Greetings- Using R 1.2.2 under linux, I get the following: > l.agg<-xtabs(cbind(r.logic.interests, r.logic.morality, + r.logic.enlightened, r.logic.capacity, r.logic.mediate) + ~ grouptype, + data=gt) Error in parse(file, n, text, prompt) : parse error I know the data are structured fine, as I can use all the elements in individual xtabs()
2008 Mar 12
1
ftable and xtabs
Hoping someone can help me with xtabs and ftable. I'm trying to get a pair of ftables (possibly more) next to each other. For example: > dunhill_lights_xtab<-ftable(xtabs(grossedupobs ~ gender+age_group + dunhill_lights, data = ciggs)) > dunhill_lights_xtab dunhill_lights No Yes gender age_group Female
2007 Oct 05
1
creating objects of class "xtabs" "table" in R
I have an application that would generate a cross-tabulation in array format in R. In particular, my application would give me a result similar to that of : array(5,c(2,2,2,2,2)) The above could be seen as a cross-tabulation of 5 variables with 2 levels each (could be 0 and 1). In this case, the data were such that each cell has exactly 5 observations. I Now, I want the output to look like the
2009 Jul 02
1
From xtabs to matrix
Hi list, is it possible convert the xtabs result xtabs(breaks~tension+wool,data=warpbreaks) wool tension A B L 401 254 M 216 259 H 221 169 to a simple matrix or data frame? A B L 401 254 M 216 259 H 221 169 Thanks a lot! Gianandrea -- View this message in context: http://www.nabble.com/From-xtabs-to-matrix-tp24304588p24304588.html