similar to: Basic question about re-writing for loop as a function

On Sunday 19 January 2003 03:35, Michael Smith shaped the electrons to shout: > There's a bad interaction here between the predata and this faststart. > Suppose we have two logical streams (A and B), and the stream has just > recently got to logical stream B. Now, this means the fast start queue > contains the end of stream A, then the stream B headers, then the start > of

Dear All I have a program that breaks at the following lines of code: bigfunction = { ... object1 = myfunction(x) object2 = strsplit(object1, ",")[[1]] ... } where myfunction is defined elsewhere outside of bigfunction. The error I get is "error in strsplit() -- object1 not found". However, when I insert browser() into my code so that the above reads, bigfunction = {

Dear Friends, I have a matrix of size 5000 X 20. The first two columns are indicator variables taking the value of either 0 or 1. Let us call the first two columns Y1 and Y2. I need to randomly sample 1000 rows with all the associated columns, in other words my new matrix should be of size 1000 X 20. I realize that using this command newmat <- mainmat[sample(1000,replace=F),] achieves

Hello- A basic question which has nonetheless floored me entirely. I have a dataset which looks like this: Type ID Date Value A 1 16/09/2020 8 A 1 23/09/2010 9 B 3 18/8/2010 7 B 1 13/5/2010 6 There are two Types, which correspond to different individuals in different conditions, and loads of ID labels (1:50)

Hi, find enclosed a patch to implement faststart (or prebuffering). Basically, it stores a number of "refbuf"s, configurable by seconds. When a new client connects, it adds the prebuffers to que clients' queue so they are delivered as fast as permitted by the connection. As result, the players prebuffers are filled up faster giving a better "response". I tried

This small example will make icecast unusable after few seconds. The problem resides on EPIPE received when trying to send the first (58) bytes of the vorbis predata. Change the URL for your own, and try it in a LAN. I have no idea on the reasons of these errors, altough I suspect it's related to the fact that the headers are sent in blocking state and then we change to non-blocking. I

Hello, I have a matrix mat1 of dim [1,8] and mat2 of dim[30,8], I want to replace the first row of mat2 with mat1, this is what I do: mat2[1,]<-mat1 but it transforms mat2 in a list I don't understand, I want it to stay a matrix... ----- Anna Lippel -- View this message in context: http://n4.nabble.com/Simple-question-on-replace-a-matrix-row-tp1427857p1427857.html Sent from the R help

Hello- Such a strange problem, can't figure it out at all. Using binomial glm models, and the step() function, so the call looks like this: sectionmodel = glm(formula = Target3 ~ S1Q12_NUM.1 + S1Q9_NUM.1 + S1Q5_NUM.1 + S1Q7_NUM.1 + S1Q8_NUM.1 + S1Q6_NUM.1 + S1Q10_NUM.1 + S1Q12_BURG.1 + S1Q12_CD.1 + S1Q4.1 + S1Q12_OTHVIOL.1 + S1Q8.1 + S1Q12_GBH.1 + S1Q11.1 + S1Q7.1 + S1Q12_THEFT.1

Hi there, I have a problem about lapply, strsplit, and accessing list elements, which I don't understand or cannot solve: I have e.g. a character vector with three elements: x = c("349/077,349/074,349/100,349/117", "340/384.2,340/513,367/139,455/128,D13/168", "600/437,128/903,128/904") The task I want to perform, is to generate a list,

Hello- I have some code that looks like this: with(mydatalocal, sum(table(Service[Time==5:8]))) This is designed to add up the numbers of responses between the Time codes 5 to 8 (which are integers and refer to quarters). Service is just one of the variables, I'm just trying to count the number of responses so I picked any of the variables. However, there is something wrong, it returns far

Hello- Sorry, this is a bit of a noob question, but I can't seem to progress it any further. I have two dataframes which contain a series of strings which exactly match. The problem is one has more rows than the other (more cases have been added) and they have been sorted so that they are not in the same order. The smaller dataframe, though, contains in another column which has codes

I am using the following command to replace all the missing values and assorted typos in a dataframe with NA: mydata[mydata>80]=NA The problem is that the first column contains values which should be more than 80, so really I want to do it just for mydata[,2:length(mydata)] I can't seem to re-write the code to fit: mydata[,2:length(mydata)>80]=NA # no error message, but doesn't

Hi, I'm looking for some way to pick up the numbers which are contained and buried in a long character. For example, outtree.new="(((B:1204.25,E:1204.25):7581.11,F:8785.36):8353.85,C:17139.21);" num.char =

Hi all If I have a string, say "ABCDA", and I want to convert this to the sum of the letter values, e.g. A -> 1 B -> 2 etc, so "ABCDA" = 1+2+3+4+1 = 11 Is there an elegant way to do this? Trying something like which(LETTERS %in% unlist(strsplit("ABCDA", ""))) is not quite correct, as it does not count repeated characters. I guess what I need is

Thanks. Yes. Your approach can identify: Glaxy ace S 5830 and S 5830 Glaxy ace But you can not identify using same program: Iphone 4S 16 G Iphone 4S 16G How should I solve both in same time. Kind regards,Tammy [[alternative HTML version deleted]]

Dear Mao Jianfeng, "r-help-owner" is not the place for help, but: r-help at r-project.org (CC-ed here) In any case, strsplit() does the job, i.e.: > unlist(strsplit("BCPy01-01", "-")) [1] "BCPy01" "01" You can work with the whole variable, like: splitpop <- strsplit(df1$popcode, "-") then access the first part with >

On Sunday 19 January 2003 08:09, Ricardo Galli wrote: > Hi, > find enclosed a patch to implement faststart (or prebuffering). > > Basically, it stores a number of "refbuf"s, configurable by seconds. When > a new client connects, it adds the prebuffers to que clients' queue so > they are delivered as fast as permitted by the connection. As result, the > players

Hi, A pared down version of the dataset I'm working with: edm<-read.table(textConnection("WELLID X_GRID Y_GRID LAYER ROW COLUMN SPECIES CALCULATED OBSERVED w301_3 4428. 1389 2 6 18 1 3558 6490. w304_12 4836. 6627 2 27 20 1 3509 3228. 02_10_12080 3.6125E+04 13875 1 56 145 1

Hello, I am attempting to manipulate strings in which there are differing amounts of whitespace before and after each element taht I want to keep (any word, letter, or number). However, after strsplit and unlist, I know how to select specific elements with "[ ]", but I want to select instead all elements that are not missing. That is, do not select any elements that are simply

If I have this object: x <- c("abc\ndef", "", "ghi") and I write it to a file using `writeLines(x, "test.txt")`, my text editor sees a 5 line file: 1: abc 2: def 3: 4: ghi 5: which is what I'd expect: the last line in the editor is empty. If I use `readLines("test.txt")` on that file, I get the vector