similar to: help with "by" command

Hello all, I am using the clustering functions in R in order to work with large masses of binary time series data, however the clustering functions do not seem able to fit this size of practical problem. Library 'hclust' is good (though it may be sub par for this size of problem, thus doubly poor for this application) in that I do not want to make assumptions about the number of

Hello everyone, What is the simplest, most RELIABLE way to import data from MS EXCEL (.xls) format to R? In the past I have used the read.xls() function from the xlsReadWrite package, however, I have been wrestling with it all afternoon long with no success. I continue to receive the following error message: > {widge<-read.xls("F:\\Classes\\Z1.Data\\stat.3010\\WidgeOne.xls", +

Hello, I was using version 2.13.2 and I have just downloaded the latest version 2.14.1. However, I''m trying to install the packages I was using and when I look for them in the packages list, I can´t find many in the CRAN binaries (e.g. "vegan"). I do find them in the CRAN sources but the installation fails. I tried downloading the version 2.14.0 and I had the same problem. I

Hi. I searched the list and didn't found nothing similar to this. I simplified my example like below: #I need calculate correlation (for example) between 2 columns classified by a third one at a data.frame, like below: #number of rows nr = 10 #the third column is to enforce that I need correlation on two variables only dataf =

hello when I entered following command, I got NA values for some catagories. > tapply(slp_jeo2$slp,slp_jeo2$jeo,mean ) 999 Ca Cka DCy Jh JKi Kk 14.06665 NA 14.60445 NA NA NA NA NA KTa KTac Ku Kua Kus Ky Kyk ODe NA NA NA NA NA NA

Hello, I am a new R user, using version 1.5.1. I am attempting to run R programs from a dos command line (in win2000) and am having problems. My goal is to be able to use R from batch scripts in both windows and also in Linux eventually later. When I first ran "rcmd BATCH --help" it said that perl was not found. after installing perl and running again, I received the following error:

Hello all, I created a set of Docker images running Asterisk and exposing AMI / ARI ports that i found to be quite useful for ARI / AMI development and regression. As they are based on Docker with whaleware, adding new configuration files to roll your own dialplan / queues / voicemail etc is pretty easy. And you can run quite a lot on the same box to simulate clusters. There is no SIP / RTP

Hi all, I'm feeling a little guilty to ask this question, since I've written a solution using a rather clunky for loop that gets the job done. But I'm convinced there must be a faster (and probably more elegant) way to accomplish what I'm looking to do (perhaps using the "merge" function?). I figured somebody out there might've already figured this out: I have

hi, i have another question on tapply: i have a dataset z like this: 5540 389100307391 2600 5541 389100307391 2600 5542 389100307391 2600 5543 389100307391 2600 5544 389100307391 2600 5546 381300302513 NA 5547 387000307470 NA 5548 387000307470 NA 5549 387000307470 NA 5550 387000307470 NA 5551 387000307470 NA 5552 387000307470

Dear R-help forum members, Suppose I have a data-frame having two variables and single data for each of them, as described below. variable_1           variable_2         10                          20 I have written a function, say, 'fun' which uses input 10 and 20 and gives me desired result. fun = function(X, Y)          {          X + Y              #( I am just giving an example of

Dear R users, I have a newbie-question that I couldn't resolve after reading through several pieces of documentation and searching the archive. I have a data.frame containing experimental data from a group experiment in psychology. Each line represents a single participant, but participants were assigned to groups of three or four persons. One variable indicates each participants'

Hi everybody, using bwplot for producing panel boxplot with 3 dimensions i want to add a mark on each boxplot representing one individual (on all its dimensions) till now, i didn't succeed getting the desired solution I want as well to keep the median symbols as a line Many thanks for your help christophe here is the tested code: ######################## library(lattice) ex <-

Dear R experts, I am trying to solve this problem, related to the possibility of changing the shape of a data frame using a "pivoting-like" function. I have a dataframe df of observations as follows: ID VALIDITY YEAR PROPERTY PROPERTY VALUE A1 2007 P1 V1 A1 2007 P2 V2 A1 2007 P3 V3 A1 2008 P1 V10 A1 2008 P2 V20 A2 2007 P5 V50 A2 2008 P6 V20 A3 2007

Hi, I'm very new to R and absolutely love it. Does anyone know how to use something in R that functions like a BY command in SAS? For example, let's say you have a variable x, and you want to see the mean. Easy... > mean(x) But what if you want to see the mean of x conditional on another discrete variable? My best attempts so far are something like... > mean(x, y_cat=1)

Dear R Users, I have the following data frame: v1 <- c(rep(10,3),rep(11,2)) v2 <- sample(5:10, 5, replace = T) v3 <- c(0,1,2,0,2) df <- data.frame(v1,v2,v3) > df v1 v2 v3 1 10 9 0 2 10 5 1 3 10 6 2 4 11 7 0 5 11 5 2 I want to add a new column v4 such that its values are equal to the value of v2 conditional on v3=0 for each subgroup of v1. In the above example, the

Hello, I am trying to randomly select rows with unique values in columns 1 and 2. I want to generate multiple subsets to estimate a statistic for each data set. Below is a simplified example. L1 L2 L3 L4 L5 1 a b 1 2 3 2 a c 4 5 6 3 a d 7 8 9 4 a e 10 11 12 5 a f 13 14 15 6 b c 16 17 18 7 b d 19 20 21 8 b e 22 23 24 9 b f 25 26 27 10 c d 28 29 30 11 c e

I'm hoping there is a simple answer to this - it seems that there should be, but I can't figure it out. I have a matrix/data frame with three variables of interest - V1, V2, V3. One, V1, is a factor with x levels (x may be a large number); I want to calculate the correlation between the other two (i.e. cor(V2,V3)) for each level, and store it as a vector of length x. I should think this

Dear R-community, Using bwplot, how can I put the whiskers at percentile 5 and percentile 95, in place of the default position coef=1.5?? Using panel=panel.bwstrip, whiskerpos=0.05, from the package agsemisc gives satisfaction, but changes the appearance of my boxplot and works with an old version of R, what I don’t want, and I didn’t find the option in box.umbrella parameters Many thanks

Hi Asterisk users, I'm one of Asterisk ARI users, and trying to designing the new ARI for application execution in Stasis(). This will be made possible for executing the applications in the Stasis() application. But, before going further, I would like to know which application needs to be considered. Because this feature will introduce new Stasis behavior, I would like to test the

Hello, I have openSUSE 11.1 Trying to install randomForest as SU after invoking R install.packages("randomForest") and I get this * Installing *source* package ‘randomForest’ ... ** libs gcc -std=gnu99 -I/usr/lib/R/include -I/usr/local/include -fpic -O2 -c classTree.c -o classTree.o gcc -std=gnu99 -I/usr/lib/R/include -I/usr/local/include -fpic -O2 -c regTree.c -o