similar to: Replacing NAs in one variable with values of another variable

Displaying 20 results from an estimated 10000 matches similar to: "Replacing NAs in one variable with values of another variable"

2011 Jun 24
4
What does class "call" mean? How do I make class "formula" into a "call"?
I have a list called "tabs" that I would like to have the same structure as my list "eqSystem." The two look like they have the same format but they are different because when I look at their attributes, class(eqSystem[[1]]) is "call" but class(tabs[[1]]) is "formula". I want to have class(tabs[[1]]) as a call too. So what does "call" mean? And how
2011 Sep 21
2
Weighted Average on More than One Variable in Data Frame
Dear R Users, I have looked for a solution to the following problem and I have not been able to find it on the archive, through Google or in the R documentation. I have a data frame, say df, which has 4 variables, one of which I would like to use as a grouping variable (g), another one that I would like to use for my weights (w) The other two variables are variables (x1 and x2) for which I would
2011 Mar 18
2
How do I delete multiple blank variables from a data frame?
Dear List Members,I have 55 data frames, each of which with 272 variables and 267 observations. Some of these variables are blanks but the blanks are not the same for every data frame. I would like to write a procedure in which I import a data frame, see which variables are blank, and delete those variables. My data frames have variables named P1 to P136 and Q1 to Q136. I have a couple of
2011 Feb 09
3
Loop in variable names
Hello! I would like to do some tables for several variables and I would like to write a loop that does the table for each variable. I should also point out that my data set has several missing observations and sometimes the observations that are missing are not the same for all my variables. What I would like to do: table(StoreData$CompanyID, !is.na(StoreData$P2))
2011 Apr 15
2
Function for deleting variables with >=50% missing obs from a data frame
Hello R users! I have several data frames where some of the variables have many missing observations. For example, Q1 in one of my data frames has over 66% of its observations missing. I have tried imputation with mice but it does not work for all the data frames and I get the following message or a similar message to this: iter imp variable 1 1 Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11
2011 Apr 07
1
df with max function applied to 6 lags of a variable?!?
Hello everyone! I have a data frame of 136 variables with 270 observations. I would like to create a new data frame such that each element of that data frame contains the maximum value of the 6 prior lags of the initial data frame. So for example, if my original data frame, A, were A1=c(7.72, 7.94, 7.56, 7.54, 0.93, 0.59, 7.21, 8.00, 7.19, 7.57)A2=c(4.27, 3.70, 3.80, 3.67, 3.83, 3.95, 4.02, 2.06,
2011 Jun 28
2
How do I output all the R-squares of an SUR? summary(fitSUR$eq[[1:4]])$r.squared does not work
Greetings R Users, I have a system of equations for which I would like to output all the R-squares. Assume there are four equations in my system, the only way I found to output all the R-squares is by calling them out one by one as this: summary(fitSUR$eq[[1]])$r.squared summary(fitSUR$eq[[2]])$r.squared summary(fitSUR$eq[[3]])$r.squared summary(fitSUR$eq[[4]])$r.squared But isn't there a
2011 Apr 19
1
Subsetting a data frame by dropping correlated variables
Hello R Users! I have a data frame that has many variables, some with missing observations, and some that are correlated with each other. I would like to subset the data by dropping one of the variables that is correlated with another variable that I will keep int he data frame. Alternatively, I could also drop both the variables that are correlated with each other. Worry not! I am not deleting
2011 Apr 08
1
Package mice: Error in if (meth[j] != "") { : argument is of length zero
Dear R users, I am using package mice and I am getting the error " Error in if (meth[j] != "") { : argument is of length zero." I have tried using several different versions of R (even the one that will be coming out this month) to no avail. I am using RStudio as my interface with R. Also note that I had run this a couple of days ago and it was working fine; I can't,
2012 Apr 20
1
pasting a formula string with double quotes in it
Hello everyone, I have tried several ways of doing this and searched the documentation and help lists and I have been unable to find an answer or even whether it is possible to do it. I am pasting together a formula and I need to insert double quotes around the strings. Here's an example: location <- c("AL", "AK", "MA", "PA") v=2 test <-
2011 Apr 13
1
Overcoming warning in package zoo
Dear R users,I have a long program that I am trying to run--I am using RStudio as my interface with R. The pieces of the program run well individually but when I try to run everything in sequence it bogs down because of a warning after using rollmax from package zoo. Here is the warning: "In rollmax.zoo(zoo(Pmat), 7, na.pad = FALSE, align = "right") : na.pad is deprecated. Use
2009 Nov 20
2
Finding & replacing non-ASCII characters
Hi guys, Are there any feasible methods in searching & finding non-ASCII characters in R? For example, from the following object, x <- mia. SzaÌmitaÌó The desired output is, x.out <- mia. SzaImitaIA Your help in resolving this would be greatly appreciated. [[alternative HTML version deleted]]
2011 Jun 21
1
Setting up list of many equations for systemfit
Dear List Members,I am trying to set up a large system of equations and I am trying to find a simple way to set up the list command under the package system fit. Here is the example from system fit and what I am trying to do: EQ1 <- Y1 ~ X1 + X2 + X4EQ2 <- Y2 ~ X2 + X3EQ3 <- Y3 ~ X2 + X3 + X4EQ4 <- Y4 ~ X1 + X3 + X4eqSystem <-list(form1 = EQ1, form2 = EQ2, form3 = EQ3, form4 = EQ4)
2006 Jun 01
4
FW: How to create a new package?
Hi, I'm a group of functions and I would like to create a package for load in R. I have created a directory named INE and a directory below that named R, for the files of R functions. A have created the files DESCRIPTION and INDEX in the INE directory. The installation from local zip files, in the R 2.3.0, results but to load the package I get an error like: 'INE' is not a
2011 Feb 04
4
aggregate function - na.action
Can someone please tell me what is up with na.action in aggregate? My (somewhat) reproducible example: (I say somewhat because some lines wouldn't run in a separate session, more below) set.seed(100) dat=data.frame( x1=sample(c(NA,'m','f'), 100, replace=TRUE), x2=sample(c(NA, 1:10), 100, replace=TRUE), x3=sample(c(NA,letters[1:5]), 100, replace=TRUE),
2011 Feb 25
1
combining two columns into one column despite NAs
I am trying to combine two columns in a data frame into one column. Some values in either column are missing, but not in the same row for the two different columns. Additionally, when both columns in a row contain data, the data are identical. I want a new column with the identical data or the data from the column with observed data. For example: I have >data id x y
2010 Mar 04
4
Analogue to SPSS regression commands ENTER and REMOVE in R?
I am not sure if this question has been asked before - but is there a procedure in R (in lm or glm?) that is equivalent to ENTER and REMOVE regression commands in SPSS? Thanks a lot! -- Dimitri Liakhovitski Ninah.com Dimitri.Liakhovitski at ninah.com
2007 Feb 21
2
file path
Hello, It is possible to return the path of the current working R-file (in execution)? Thanks, Rita Sousa. [[alternative HTML version deleted]]
2011 Mar 20
4
predicting values from multiple regression
Hey List, I did a multiple regression and my final model looks as follows: model9<-lm(calP ~ nsP + I(st^2) + distPr + I(distPr^2)) Now I tried to predict the values for calP from this model using the following function: xv<-seq(0,89,by=1) yv<-predict(model9,list(distPr=xv,st=xv,nsP=xv)) The predicted values are however strange. Now I do not know weather just the model does not fit
2011 Jan 28
6
User error in calling predict/model.frame
I want to predict values from an existing lm (linear model, e.g. lm.obj) result in R using a new set of predictor variables (e.g. newdata). However, it seems that because my linear models was made by calling scale() on the target predictor that predict exits with an error, "Error in scale(xxA, center = 9.7846094491829, scale = 0.959413568556403) : object 'xxA' not found". By