Displaying 20 results from an estimated 9000 matches similar to: "Error in plotmath"
2007 Jul 10
3
ECDF, distribution of Pareto, distribution of Normal
Hello all,
I would like to plot the emperical CDF, normal CDF and pareto CDF in the
same graph and I amusing the following codes. "z" is a vector and I just
need the part when z between 1.6 and 3.
plot(ecdf(z), do.points=FALSE, verticals=TRUE,
xlim=c(1.6,3),ylim=c(1-sum(z>1.6)/length(z), 1))
x <- seq(1.6, 3, 0.1)
lines(x,pgpd(x, 1.544,0.4373,-0.2398), col="red")
y
2009 Sep 29
1
Probability of data values form empirical distribution
Hello,
Could someone help me please and to tell how to get the probability from empirical distribution (not parametric) for each data value (R function).
For example, for normal distribution there is such a function like:
“pnorm(q, mean = 0, sd = 1, lower.tail = TRUE, log.p = FALSE)”
I need the same function only for the empirical distribution (which does not correspond to any typical
2009 Sep 29
1
Probability of data values form empirical distribution
Hello,
Could someone help me please and to tell how to get the probability from empirical distribution (not parametric) for each data value (R function).
For example, for normal distribution there is such a function like:
“pnorm(q, mean = 0, sd = 1, lower.tail = TRUE, log.p = FALSE)”
I need the same function only for the empirical distribution (which does not correspond to any typical
2005 Nov 17
3
ECDF values
Dear UseRs,
maybe is a silly question: how can I get Empirical CDF
values from an object created with ecdf()?? Using
print I obtain:
Empirical CDF
Call: ecdf(t)
x[1:57] = 4.1, 4.4, 4.5, ..., 491.3,
671.27
Thanks in advance.
Regards,
Vito
Diventare costruttori di soluzioni
Became solutions' constructors
"The business of the statistician is to catalyze
the scientific
2003 May 08
2
approximation of CDF
Hi all,
is there any package in R capable of smooth approximation of CDF
basing on given sample?
(Thus, I am not speaking about ecdf)
In particular, I expect very much that the approximation should
subject to the property:
f(x0)<=f(x1) for x0<x1, where x0 and x1 belong to range of
the sample given.
Polynomial approximation could be OK for me as well.
P.S.
2012 Jun 14
2
plot cdf
Good Afternoon,
I'm trying to create a cdf plot, with the following code. It works well,
but I have little doubt, if you can help solve. When I create the plot,
like the graph line would still not appear with point
#cdf
x<-table(Dataset$Apcode)
View(s)
hist(s)
*plot(ecdf(x))*
x<-1 37607
2 26625
3 5856
4 25992
5 30585
6 16064
7 9850
..
...
..
186 52
--
View this message in
2009 Mar 25
1
Confusion about ecdf
Hi,
I'm bit confused about ecdf (read the help files but still not sure about
this). I have an analytical expression for the pdf, but want to get the
empirical cdf. How do I use this analytical expression with ecdf?
If this helps make it concrete, the pdf is:
f(u) = \sum_{t = 1}^T 1/n_t \sum_{i = 1}^{n_t} 1/w K((u - u_{it})/w)
where K = kernel density estimator, w = weights, and u_{it} =
2004 Feb 18
2
Area between CDFs
Dear List:
I am trying to find the area between two ECDFs. I am examining the gap in performance between two groups, males and females on a student achievement test in math, which is a continuous metric.
I start by creating a subset of the dataframe
male<-subset(datafile, female="Male")
female<-subset(datafile, female="Female")
I then plot the two CDFs via
2008 Jul 15
1
Supressing printing from a function: ecdf
Dear R Users,
I am trying to suppress the information printed by the ecdf function
during an assignment. Various alternatives have failed me so far:
> a=summary(ecdf(rnorm(100)))["1st Qu."]
Empirical CDF: 100 unique values with summary
> invisible(a=summary(ecdf(rnorm(100)))["1st Qu."])
Empirical CDF: 100 unique values with summary
> (function()
2003 Jun 24
4
cumulative frequency distribution plot
Does R do cumulative frequency distribution plots?
--
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High Performance Computing & Scientific Visualization
SAIC, Supporting the EPA
Research Triangle Park, NC
919-541-1500 EMail: cathey.tommy at epa.gov
My e-mail does not reflect the opinion of SAIC or the EPA.
Federal Contact - John B. Smith
919-541-1087 - smith.johnb at epa.gov
2011 Jun 02
4
[Plea to the R Gods] Theoretical and Empirical CDFs
http://r.789695.n4.nabble.com/file/n3567636/ecdfs.jpg ecdfs.jpg
http://r.789695.n4.nabble.com/file/n3567636/ecdf_curve.gif ecdf_curve.gif
Hello,
I have generated a plot of two empirical CDFs (attachment 1). As a result,
they are stepwise when plotted. The following code was used:
> plot(ecdf(mut), do.points=FALSE, verticals=TRUE, xlim=range(mut, non),
> col="red")
>
2011 May 14
1
odfWeave 0.7.17 stutters on Debian testing 64-bit amd64 systems.
Dear list,
This is a copy of a mail sent to Max Kuhn, original author and
maintainer of the odfWeave package, which seems not to have received it.
It reports a problem that seems to be very implementation specific
(reproductible on three Debian testing amd64 machine, does *not* happen
on two i686 Debian testing systems, does *not* happen on an Ubuntu 11.06
amd64 machine) and therefore not
2010 Nov 25
1
overlap cdf plots and add colors and etc
Hi r-users,
I would like to overlap 2 ecdf plots.
I tried this below and it gives me two plots of ecdf but just both just in
black.
par(mar=c(4,4,2,1.2),oma=c(0,0,0,0),xaxs="i", yaxs="i")
plot(ecdf(datobs))
lines(ecdf(gam_sum_gen))
Then I try to add colors etc and also the legend but fail.
par(mar=c(4,4,2,1.2),oma=c(0,0,0,0),xaxs="i", yaxs="i")
2011 Jan 26
2
2 functions with same name - what to do to get the one I want
There seems to be 2 functions call ecdf...
http://lib.stat.cmu.edu/S/Harrell/help/Hmisc/html/ecdf.html
http://127.0.0.1:11885/library/stats/html/ecdf.html
How do I get the one ecdf {Hmisc} to run instead of the ecdf {stats}
A pointer in the right direction would be greatly appreciated.
Tried to instal Hmisc but got this message, so I assume I have it
> utils:::menuInstallPkgs()
Warning:
2007 Nov 18
2
Obtaining x-values from ECDF
Dear Group,
I am using the ecdf function as follows:
cawa.cdp <- ecdf(cawaocc$LEFF80)
summary(cawa.cdp)
Empirical CDF: 223 unique values with summary
Min. 1st Qu. Median Mean 3rd Qu. Max.
0.07918 1.35700 1.68600 1.61000 1.91200 2.70000
I can see by the summary that the y-value for the 3rd quartile is 1.912.
How can I obtain the x-value for a specified y-value (e.g., 0.8)?
2009 Aug 03
1
Help with Ecdf function
Dear R users,
I'm using Ecdf (Hmisc library) to plot four cdf in a same graphic. In this
graphic I also plot the 0.99 quantile for these cdf. I successfully plot
cdfs using different types of line to distinguish them, but I can't
determine the type of lines showing 0.99 quantile.
Is there a way to assign different line types for quantile lines in Ecdf
plot?
Best regards,
--
Mateus da
2006 Jun 30
1
Empirical CDF
Good day everyone,
I want to assess the error when fitting a Gram-Charlier
CDF to some data 'ws', that is, I want to calculate:
Err = |ecdf(ws) - GCh_ser(ws)|
The problem is, I cannot get the F(x) values from the
ecdf.
'Summary(ecdf())' returns some of the x-axis values,
but how do you get the F(x) values?
Thank you for any help you can provide.
Regards,
Augusto
2010 Feb 19
1
color graph in multiple plots
Hi,
I would like to distinguish my plots using colors but I got error message. How do I correct that?
plot(ecdf(z), main ="CDF for observed and simulated weighted sum",type="l",lwd=2,col="blue",
xlab="Weighted sum (mm)", ylab="Cumulative Percent", xlim=c(0,15), xaxs ='i', yaxs ='i',ylim=c(0,1))
par(new=TRUE)
2011 Aug 22
2
CDFs
Hello all,
I have two columns of numbers. I would like to do the following:
(1) Plot both cdfs, F1 and F2 on the same graph.
(2) Find smoothed approximations of F1 and F2 lets call them F1hat and F2hat
(3) Find values for F1hat when we substitue a value of x in it.
(4) Find the corresponding densities of the cdfs.
Any ideas?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
2011 May 17
2
pdf (probability distribution function) and cdf
Dear all,
I would like for a given vector to calculate the pdf and the cdf and then plot these two graphs.
Is there in R any toolkit that can help me do that fast?
Regards
Alex