similar to: Display/show the evaluation result of R commands automatically

Dear list, I wonder if there a better way to have rbind/cbind/append to create the first element (if it is empty) instead of doing the following in a loop? for (i in 1:10) { if (i == 1) { aRow = SomeExpression(i) } else { aRow = rbind(aRow,SomeExpression(i)) } } Thanks Anthony

Dear R-help, I wonder if you could give me some suggestions in how to do a union join of two data frames as follow: -> union join the common column, and insert a 0 if one is missing. I made a function to perform the following, and I know it may not that quite welly written, but it works. Any suggestions are welcome, many thanks. Anthony > q1 =

Dear List, I wonder why when using read.csv(), if the column name contains a numeric i.e. a stock symbols-"0001.HK", it will automatically insert an "X" character to the column names - "X0001.HK". Now I have to manually do a loop and use substring() to remove the "X" character. Any advice? Thanks Anthony

Note: I am almost certain that this has been asked and answered here before, so my apologies for the redundant query. I also know that there are several packages that will do this, but I wish to do it using base R functions only (see below). The query: Suppose I have a character vector of names like this: somenames <- c("Heigh", "Ho", "Silver", "Away")

Hello I am new to R and I need to convert some dates (numeric format by matlab) to actual dates in R. For instance, Matlab -> 730456 -> >> datestr(730456) ans = 02-Dec-1999 R - > library(zoo) > as.Date(730456) [1] "3969-12-03" I don't not mind the output format but it needs to be right. Many thanks Ed

Another solution. reformulate + substitute + as.formula: substitute(~ (.)^2, list(. = reformulate(somenames)[[2]])) |> as.formula() On Sat, Mar 29, 2025 at 5:31?PM Bert Gunter <bgunter.4567 at gmail.com> wrote: > > Note: I am almost certain that this has been asked and answered here > before, so my apologies for the redundant query. > > I also know that there are several

Gabor, Duncan, et. al. 1. Thank you for your great comments and solutions. This is what I was hoping for! 2. Duncan: I completely agree with your criticisms. In fact, I realized the for() loop only needed the <- assignment, but your comment is important to note. However, I didn't like the for() loop either; I *much* preferred your Reduce() solution which is exactly the sort of elegant

Dear Sir, Thanks for your mail and help. I got this error while trying to run your code. sbux1.z <- read.csv.zoo(u, FUN = as.yearmon, format = fmt) Error in read.table(file = file, header = header, sep = sep, quote = quote, : 'file' must be a character string or connection Thanks and Regards, Upananda Pani On Tue, Sep 19, 2017 at 4:31 PM, Upananda Pani <upananda.pani at

Thanks for the response. Yes, I did study the vignette but did not understand it fully. Anyway, I have tried once again now. I am happy to say that I have got what I wanted. library(Ryacas) x <- Sym("x");U <- Sym("U");x0 <- Sym("x0");C <- Sym("C") my_func <- function(x,U,x0,C) { return (U/(1+exp(-(x-x0)/C)))} FirstDeriv <-

Thanks in advance. I'm having a trouble with data saving. I want to run the same data which is in Ecdat library at different statistic programs(excel, stata and matlab) The data I want to use is library(Ecdat) data(Housing) and I want to extract this data our of R as *.dta *.xls formats. So, my first try was to open the data in R window and drag and paste to excel or notepad. BUT, it

Hello, I'm attempting to access a specific number of sub diagonals in a MATRIX and have been accustomed to using spdiags in MATLAB or Octave. I've got a solution pieced together using for loops and it works though isn't vectorized and liable to run very slow for large matrices. As an example: A = 1 2 3 4 5 9 8 7 6 5 4 5 6 7 8 5 4 3 2 1 8 7 6 0 1 The subdiagonals are: 9,5,3,0 4,4,6

Hi Gabor's code works as expeceted without error. What is "u" in your case? Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Upananda > Pani > Sent: Wednesday, September 20, 2017 11:06 AM > To: Gabor Grothendieck <ggrothendieck at gmail.com> > Cc: r-help <r-help at r-project.org> >

Hi all, I would like to do some QSAR analysis (quantitative structure activity relationship). I need to use some Partial Least Squares (PLS) regression, but I have not seen this option on the R-project. Is it possible to do this kind of regression on R? thank you in advance best regards, olivier [[alternate HTML version deleted]]

Dear All, Thanks a lot for your help. Would you please let me know if i want to read a csv file as zoo object from my local file rather than directly from the website, how to do that? library(zoo) u <- "https://faculty.washington.edu/ezivot/econ424/sbuxPrices.csv" fmt <- "%m/%d/%Y" With sincere regards, Upananda Pani On Wed, Sep 20, 2017 at 3:22 PM, PIKAL Petr

I am interested in testing two similar nls models to determine if the lines are statistically different when fitted with two different data sets; one corn, another soybean. I know I can do this in linear models by testing for interactions. See Introductory Statistics with R by Dallgaard p212-218 for an example. I have two different data sets I am comparing to lai. ci.re should have very

I am porting a program in matlab to R, The problem is that Matlab has a feature where symbols that aren't arguments are evaluated immediately. That is: Y=3 F=@(x) x*Y Will yield a function such that F(2)=6. If later say. Y=4 then F(2) will still equal 6. R on the other hand has lazy evaluation. F<-function(x){x*Y} Will do the following Y=3 F(2)=6 Y=4 F(2)=8. Does anyone know of away to

Hi, I'm having a problem converting a Matlab program into R. The R code works almost all the time, but about 4% of the time R's optim function gets stuck on a local minimum whereas matlab's fminsearch function does not (or at least fminsearch finds a better minimum than optim). My understanding is that both functions default to Nelder-Mead optimization, but what's different about

Hello All, I have searched but haven't been able to find an answer to this question. I'm writing a function that needs to be able evaluate the right-hand side of a general non-linear formula for different parameter values, similar to what nls() does. I looked through the nls() code but it isn't clear what is going on. Could someone point me to a reference or a way I might do this?

Dear R Core, working on my dynamic factor modelling package, which requires several subroutines to create and update several system matrices, I come back to the issue of being annoyed by R not supporting multiple assignment out of the box like Matlab, Python and julia. e.g. something like A, C, Q, R = init_matrices(X, Y, Z) would be a great addition to the language. I know there are several

Dear R-help, Would it be possible to have the "prompt" option accept a function, such as date()? This way, I can easily deduce the elapse time of top level R expressions. This would be similar to how Unix shells handle their prompt variables. Cheers, Andy ------------------------------------------------------------------------------ Notice: This e-mail message, together with any