similar to: Replacing null values

I have a table that looks like this: measurement?? ?date??? door ?? color 0.93529385?? ?513?? ?open?? ?red 0.97419293?? ?420??? open ?? red 0.962053514?? ?513?? ?closed?? ?red 0.963909937?? ?1230?? ?open?? ?blue 0.97652034?? ?1230?? ?open?? ?green 0.989310795?? ?1230?? ?closed?? ?blue 0.9941022?? ?917?? ?closed?? ?yellow I would like to create a table that has: Open measurement, Closed

I have a data frame that is about 40 columns by 10000 rows. I want to get the dput of small portion of that by using dput(results[1:10,3:6]). The dput is very long and includes all the values from the original data frame. Why is that? Jeffrey

The gray (level) function returns different shades of gray, where level is a vector of numbers ranging from 0 to 1.? 0 is white and 1 is black and everything in between is a shade of gray. Is there a function that will let me choose two different colors?? For example, a 0 might be blue and 1 might be red and in between might be a mix. Jeffrey

I aggregated my data: aggresults <-aggregate(results, by=list(results$a, results$b, results$c), FUN=mean, na.rm=TRUE) results has about 8000 lines of data, and aggresults has about 80 lines. I would like to create a separate variable for each of the 80 aggregates, each containing the 100 lines that were aggregated. I would also like to create plots for each of those 80 datasets. Is

I have a matrix that looks like this: structure(c("0.0376673981759913", "0.111066500741386", "1", "1103", "18", "OPEN", "DEPR", "0.0404073656092023", "0.115186044704599", "1", "719", "18", "OPEN", "DEPR", "0.0665342096693433",

I have a table that looks like this: structure(list(speed = c(3,9,4,8,7,6), C = c(0.697, 0.011, 0.015, 0.012, 0.018, 0.019), house = c(1, 1, 1, 1, 1, 1), date = c(719, 1027, 1027, 1027, 1030, 1030), hour = c(18, 8, 8, 8, 11, 11), id = c("1000", "10000", "10001", "10002", "10003", "10004")), .Names = c("speed",

I have a scatter plot with 10000 points.? I would like to add a line that bins every 50 points and connects the average of each bin.? I'm looking for something similar to line type "m" in Stata. With this dataset of 10000 points, I would also like to bin the data and make boxplots at certain intervals, so that I have a set of boxplots to represent each bin.? I would also like the

I have the following: Tout = c(". ", ". ", + "-51.0", " -9.6", " -9.6", " -9.6", " -9.6", " -9.6", " -9.6", + " -9.6", " -9.5", " -9.5", " -9.6", " -9.5", " -9.6", " -9.6", + " -9.5", " -9.4", "

For each date, I would like to keep the line with the lowest speed and discard the rest. The result would have one line for each date. Can I use aggregate for this? My table is as follows: structure(list(speed = c(3,9,14,8,7,6), result = c(0.697, 0.011, 0.015, 0.012, 0.018, 0.019), house = c(1, 1, 1, 1, 1, 1), date = c(719, 1027, 1027, 1027, 1030, 1030), id = c("1000",

Hi, Thanks in advance for reading this post. I received some affymetrix genotyping data back recently (250K, Nsp array)…However, in order for me to do any analysis on this data set, I need to add append the annotation file to it. Basically I want to do something that looks like this: Snpfile(tab delimited): SNPID Genotype X Y 123 AA 13.4 1.2

Hi Justin Holewinski, >> As far as I know, there is not a good way to implement user prompts with the LLVM APIs. This info helps me a lot. I tried to do a thing that is not possible. Thank you very much. Sincerely Journeyer 2013/1/15 Justin Holewinski <justin.holewinski at gmail.com>: > Is this for user prompts, or just reading data from stdin? You can use >

Hi, Is there such a thing? If no: is it easily simulated? thanks, Joh

>From: Johannes Graumann <johannes_graumann at web.de> >Date: 2007/12/18 Tue PM 04:40:37 CST >To: r-help at stat.math.ethz.ch >Subject: [R] All anchored series from a vector? lapply(1:length(myvector) function(.length) { c(myvector[1}:myvector[.length]) }) but test it because i didn't. >Hi all, > >What may be a smart, efficient way to get the following result:

On Sat, Dec 29, 2012 at 9:45 PM, Journeyer J. Joh <oosaprogrammer at gmail.com> wrote: > Klang is tested with LLVM 3.1 > Header file location is often changed. I guess that's why.. I think that klang should be based on the latest SVN/git version of LLVM. -- Sean Silva

And for this kind of question I think I would better hold in. There would be more important issue worth on this list. For this reason I am sorry. Sincerely Journeyer 2013/1/15 Journeyer J. Joh <oosaprogrammer at gmail.com>: > Hi Justin Holewinski, > >>> As far as I know, there is not a good way to implement user prompts with the LLVM APIs. > > This info helps me a

Dear R users, I have a very basic query, but was unable to find a proper anwser. I have the following data.frame x y 2 0.12 3 0.25 4 0.11 6 0.16 7 0.20 and, due to further calculations, I need the data to be stored as x y 1 0 2 0.12 3 0.25 4 0.11 5 0 6 0.16 7 0.20 8 0 How do

Hello, I just applied changes of LLVM 3.2 and it is tested with LLVM 3.2 downloaded from the LLVM Download Page. I just worked for master branch only. The rest of the other branches need to be changed about this also. This will be done as soon as possible. (Before I fix this, If you look at the commits for this issue for master branch, you can easily fix it and test for others also.) Sorry for

Hi Joerg, Thank you very much! I finally found a working command string to cross-compile for ARM on x86. ./clang -v --save-temps -ccc-host-triple arm-none-linux-gnueabi --sysroot=/home/hum/Documents/Projects/arm_toolchain/arm-2010.09/arm-none-linux-gnueabi/libc -gcc-toolchain /home/hum/Documents/Projects/arm_toolchain/arm-2010.09 hello.c -o hello Above works fine! Important options are

Hi, Is there any way to get an expression into a data.frame, such that "grid.table" from "gridExtra" will plot it evaluated in the table body? The docu does it for the header, but is the body possible? Thanks, Joh

Why is class(spectrum[["Ion"]]) after this "factor"? spectrum <- cbind(spectrum,Ion=rep("", nrow(spectrum)),Deviation.AMU=rep(0.0, nrow(spectrum))) slowly going crazy ... Joh