similar to: two sample histogram

Given a data frame with a continuous variable and a factor. I would like to generate a histogram of the continuous variable, where each bar is filled with different colors according to the percentage of factor values falling into this region of the continuous variable. I looked into packages like 'lattice' and 'ggplot2'. Searching R-help revealed that 'histogram' is

Dear Contributors: I have two vectors x and z, and I want to display the histograms of both vectors in the same graph, x in red bars, z in blue bars. If you have any clue on how to do that, I will be very glad to hear it!!!!!! Thanks in advance again, Juan Pablo Fededa [[alternative HTML version deleted]]

I am learning ggplot2 commands and I have figured out how to create histograms and density curves but I am not sure how to add a density curve on top of a histogram. Here are the two graphs that I created. ## Histogram t<-rnorm(500) w<-qplot(t, main="Normal Random Sample", fill=I("blue"), colour=I("black"), geom="histogram") w ##Density Curve

Hi, First let me say I am a big fan of R and appreciate all your time and effort. The update() function does not seem to work in a for loop. Consider the following: mdat <- matrix(c(1,2,3, 11,23,13, 12,4,8), nrow = 3, ncol=3, byrow=TRUE) reg <- lm(mdat[7:9]~1) for(i in 1:2) { reg <- update(reg,.~.+mdat[((i-1)*3 + 1):(i*3)]) #update reg twice } reg # reg should have two independent

Dear R-help team, I am getting addicted to using R but keep on getting many challenges on the way especially on data management (data cleaning). I have been wanting to drop all the rows if there values are `NA' or have specific values like 1 or 2 or 3. mdat <- matrix(1:21, nrow = 7, ncol=3, byrow=TRUE, dimnames = list(c("row1",

Dear all, For two sets of random variables, say, x <- rnorm(1000, 10, 10) and y <- rnorm(1000. 3, 20). Is there any way to overlay the histograms (and density curves) of x and y on the plot of y vs. x? The histogram of x is on the x axis and that of y is on the y axis. The density curve here is to approximate the shape of the distribution and does not have to have area 1. Thank you

Hi all R-users, If I have a matrix with numeric elements as follows, the values are rounded when I try to refer to a specifici element using [], the value is rounded. The same thing happens if the matrix is read from a file, the values are stored to the correct precision but then when I try to refer to a specific element (such as using [], it is rounded. How do I avoid this rounding?

Hi all, So let's say I have a matrix, mdat and I only know the index number. How do I retrieve the column and row names? For example, > mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("C.1", "C.2", "C.3"))) > mdat[4] [1] 12 >

Dear R help, Apologies for the less than informative subject line. I will do my best to describe my problem. Consider the following matrix: mdat <- matrix(c(1,0,1,1,1,0), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("T1", "T2"), c("sp.1", "sp.2", "sp.3"))) mdat In my actual data I have time

Hello there, I have a question regarding bar plots. I am trying to plot the data from the following matrix as a barplot - # input data mdat <- matrix(c(0.1,0.9,0.9,0.1,0.5,0.5,0.45,1-0.45,0.6,0.4,0.8,0.2), nrow = 6, ncol=2, byrow=TRUE, + dimnames = list(c("Mon", "Mon", "Tues", "Tues", "Thurs", "Friday"), +

Hi, I was trying to make another legend for the rug plot. Sample code: library(ggplo2) ids <- paste('id_',1:3,sep='') before <- sample(9) after <- sample(1:10,9) dat <- as.matrix(cbind(before,after)) rownames(dat) <- rep(ids,3) position <- c(rep(10,3),rep(13,3),rep(19,3)) mdat <- cbind(melt(dat),position) ggplot(mdat, aes(position, value)) +

Currently, I am doing it this way. x <- mtcars$mpg h<-hist(x, breaks=10, col="red", xlab="Miles Per Gallon", main="Histogram with Normal Curve") xfit<-seq(min(x),max(x),length=40) yfit<-dnorm(xfit,mean=mean(x),sd=sd(x)) yfit <- yfit*diff(h$mids[1:2])*length(x) lines(xfit, yfit, col="blue", lwd=2) But since, ggplot2 has more appealing

Hi everyone. Long time listener, first-time caller here. I have a data set that's been melted with the excellent reshape package, but I can't seem to cast it the way I need to. Here's the melted data's structure: > str(mdat) 'data.frame': 6978 obs. of 4 variables: $ VehType : Factor w/ 2 levels "Car","Truck": 1 1 2 1 1 2 1 1 1 1 ... $ Year :

Problem: I am trying to get the histogram and box plot x axis to match. I?ve tried using the expand_limits function to make the axis match but that didn?t make the axis match. The histogram?s axis are still consistently larger than the ones for the box plot (though the function did help). Does anyone have a suggestion as to what I should do instead? Background: I am building a Shiny app that

I'm learning ggplot and am a little confused. Sometimes discrete scales work like I'd expect, and sometimes they don't. For example... This works exactly like one would expect: df<-data.frame(names=c("Bob","Mary","Joe","Bob","Bob")) ggplot(df,aes(names))+geom_histogram() But this yields an error:

Dear R users, I would like to draw some histograms as seen in the page whose address I wrote below. I searched through the web a lot and I found a page which describes how I can do it for older versions of R. For newer versions they recommend to install the package R.basics in R.clusters but this does not exist. The address of the web page is http://www1.maths.lth.se/help/R/plot.histogram/

Hi, Can you please help me with this please? What I am trying to do is call a vector from R function and used in the new function So I create 4 functions with these arguments M11 <- function(TrainData,TestData,mdat,nsam) { ls <- list() I have few statments one of them is vectx <- c(,1,2,3,4,5,6,6) vectz <- c(12,34,5,6,78,9,90) and then................ ls(vectx=vtecx,vectz=vectz)

Alright, so I am trying to write my own function to calculate column sums in a matrix. I want the result as a single list with the values. So far I have: csum<-function(m) { a = data.frame(m) s = lapply(a,sum) return(s) } What is the easiest way to have it return in a format such as [1] 6 15 24 ? Thanks. -- View this message in context:

Hi I got a barplot that has values between 0-150 and the y-axis shows the steps 0 50 100 and 150 but I would like to change it to 0 10 20 30... ...130 140 150 Dont really know the word in english so sry about it beeing abit confusing :) Thx for your help Joel -- View this message in context: http://r.789695.n4.nabble.com/change-y-axis-distance-tp2548363p2548363.html Sent from the R help

Hi all, I try to represent a multiple curve graphic where the x-axis is the temperature and the different y-axes are the different X (X22,X43,X44...) some X corresponds to the same molecule (22 and 44 are for CO2 for instance) so I use the same colour for them. I wanna mix the linetype with the colour to be able to visually see the difference between X43 and X45 The best I have done up to now