similar to: Summing values by weekday and weekend - based on daily dates

(Sorry for reposting. Please delete previous msgs. Thanks!) Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604

Sorry for reposting. The previous message not showing up. Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3

Dear everybody, I have the following challenge. I have a data set with 2 subgroups, dates (days), and corresponding values (see example code below). Within each subgroup: I need to aggregate (sum) the values by week - for weeks that start on a Monday (for example, 2008-12-29 was a Monday). I find it difficult because I have missing dates in my data - so that sometimes I don't even have the

Hi all, I am generating histograms with the following R script : #!/usr/bin/Rscript out_file = "histo.png" png(out_file) scan("values.csv") -> myvalues hist(myvalues, breaks = 50) dev.off() print(paste("Plot was saved in:", getwd())) I want the histogram to have a larger number of breaks, but a smaller break width, the idea is to make it appear smoother

Dear R-Helpers, I've looked high and low for a function that provides frequencies, proportions and cumulative proportions side-by-side. Below is the table I need. Is there a function that already does it? Thanks, Bob > # Generate some test scores > myValues <- c(70:95) > Score <- ( sample( myValues, size=1000, replace=TRUE) ) > head(Score) [1] 77 71 81 88 83 93 > >

Hi, I have the following data: > Myvalues Gene ES MEF Embryo ESHyp 1 GeneA -0.38509507 0.00 1.6250 1.7039921 2 GeneB 0.06262914 0.00 1.6250 -0.272033 and so on... I want to plot the expression values of GeneA and GeneB in the different cell/embryo/conditions (columns 2:5 above). Now, if I do: >library(ggplot2) > qplot(x=Gene, Embryo, geom =

I noticed something surprising (in R 2.2.1 on WinXP) According to the documentation, rownames and colnames are character vectors. Assigning a vector of class POSIXct or POSIXlt as rownames or colnames therefore is not strictly according to the rules. In some cases, R performs a reasonable typecast, but in some other cases where the same typecast also would be possible, it does not. Assigning a

I noticed something surprising (in R 2.2.1 on WinXP) According to the documentation, rownames and colnames are character vectors. Assigning a vector of class POSIXct or POSIXlt as rownames or colnames therefore is not strictly according to the rules. In some cases, R performs a reasonable typecast, but in some other cases where the same typecast also would be possible, it does not. Assigning a

Hi all I was wondering whether there has ever been an update on the rownames and colnames behaviour as described by Eric below? I still get the same behaviour, exactly as described by Eric, on my WinXP installation of R-2.3.0. I also posted a message to r-help on Friday but looking through the online archives it seems to have not made it to the list. I would agree with Eric that a consistent

Hello I have a string which contains microseconds, can anyone help on constructing this in to a time object, with the microseconds, that I can take to a ZOO file? Thanks Sean > UK[1,3] [1] "17:09:53.824" > UK[1,1] [1] "2007-12-11 00:00:00" > mydates <- paste( substr(UK[,1], 1, 10), UK[,3]) > mydates[1] [1] "2007-12-11 17:09:53.824" >

I am completely misunderstanding how to handle dates. I want to plot a couple of data series against some dates. Simple example 1 below works fine. Unfortunately I have multiple observations per day (no time breakdowns) and observations across years. (example 2 very simplistic version ) Can anyone suggest a quick fix or point me to something to read? I thought that zoo might do it but I seem

Question from an [R] novice... Hi, I have a vector of date/times like the one shown below (a truncated sample of a much longer list...) > dates[1:4] [1] "2006-03-16 08:41:00" "2006-03-16 10:28:00" "2006-03-16 11:03:00" [4] "2006-03-16 11:04:00" I would like to generate a weekday histogram showing the frequency of dates falling on each weekday. I know

ISOweek is a small package which contains functions to substitute the %V and %u formats which are not implemented on Windows. In addition, the package offers functions to convert from standard calender format yyyy-mm-dd to ISO 8601 week format yyyy-Www-d and vice versa. Uwe Block [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

ISOweek is a small package which contains functions to substitute the %V and %u formats which are not implemented on Windows. In addition, the package offers functions to convert from standard calender format yyyy-mm-dd to ISO 8601 week format yyyy-Www-d and vice versa. Uwe Block [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head><meta http-equiv="content-type" content="text/html; charset=utf-8" /><style type="text/css"><!-- #msg dl { border: 1px #006 solid; background: #369; padding:

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:

Hello! I have a regular data frame (DATA) with 10 people and 1 column ('variable'). Its cases are people with names ('a', 'b', 'c', 'd', 'e', 'f', etc.). I would like to write a function that would sum up the values on 'variable' of all possible combinations of people, i.e. 1. I would like to write a loop - in such a way that it

I''m doing another 0.3.7 release this weekend which will roll in changes from Luis for the win32 service, and some enhancements to the mongrel_rails Unix runner which makes it behave better with switchtower. There''s also a new document on setting up a proxy with lighttpd to do simple clustering on the site: http://mongrel.rubyforge.org/docs/lighttpd.html I''ll be

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On Saturday, I will be rebuilding my server. I expect the project to take most of the day. I will begin around 7AM PST (-0800). The server hosts the following sites: www1.shorewall.net (a.k.a. shorewall.net) ftp1.shorewall.net lists.shorewall.net rsync.shorewall.net Sorry for the inconvenience. - -Tom - -- Tom Eastep \ Nothing is foolproof