similar to: How to convert 3-digits hours

Hi, I have some problems with as.Date function. After I applied as.Date for my data, "2010" changed to "2020" as below Where am I wrong? Thanks Wonjae > x=c("11/16/2010","11/17/2010","11/18/2010","11/19/2010") > x=as.Date(x,"%m/%d/%y") > x [1] "2020-11-16" "2020-11-17" "2020-11-18"

Forum, I've got hourly data for roughly 5 months of time that I want to subset into successive weeks. The first two elements of the dataset are well.80.2$date[1] >[1] 6/12/2000 2:00 >9256 Levels: 10/1/2001... well.80.2$date[2] >[1] 6/12/2000 3:00 >9256 Levels: 10/1/2001.... and so on until mid-october. I've been able to add 1 week the first element with the following:

Hi all, I need to compare time series data files of different time formats. I had no problems with text format using strptime. But how can I convert datetime numbers from Excel (days since 30.12.1899 00:00:00) into POSIXt objects? For example 29770.375 should be converted to "03.07.1981 09:00:00" I tried the following code and encountered strange results: t1-t0 gives 29770.33

Hello, I have a data frame somewhat like that: myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00"), Hunger=c(1,1,1,2,2,1) ) myframestime <- as.POSIXct (strptime(as.character(myframe$Timestamp),

I've got an array of times in H:MM:SS PM/AM format, e.g. "5:27:15 PM" (no leading zero), and I would like to convert them over to 24 HR syntax, e.g. HH:MM:SS. If it matters, the times are from the Central Time zone. Is there a command to convert the time to a 24HR format? I tried the following: ptime("5:27:15 PM", "%H:%M:%S") [1] "2009-11-04

Dear R helpers. I am new to plotting time data using R. wonder how to convert character time info into date in R. I searched over the web but did not find answer. the input character string is something like 03_1993 or 03-1993, so the precision is at month level. I tried the following but failed. #R code below. strptime(c("03_1993"),"%m_%Y")

Hy all, I wish to use the date function to draw againt the lifetime of a motor. This lifetime is given to me in Hours (it can go over 5000 hours) I'm unable to find how to convert this lifetime value to something like %H:%M:%S because when R see 24H it says 1 day, i don't want that, i just want %H:%M:%S with a value of %H higher than 24... for example: i've got this value in hours:

A data set I obtained has the hours running from 01 through 24 rather than the conventional 00 through 23. My favorite, strptime, balks at hour 24. I thought it would be easy to correct but it must be too late on Friday for my brain and caffeine isn't helping. TIA for a hint, Clint -- Clint Bowman INTERNET: clint at ecy.wa.gov Air Quality Modeler INTERNET: clint at math.utah.edu

Hi everybody. I have a dataframe that contains a factor with the date information in the format like in the example below: "2009/05/12 11:22:31 AM" I have been able to convert it to POSIXt using strptime Now I want to print only the date as one vector and the time in another vector but they must be real date and time classes so that i can use them in calculations to reconstruct my

Dear list-members, I would like to calculate the difference between two points in time. To convert a 'time (GMT)'-character with the format "1/1/1999 01:01:01" into an object of class "POSIXct"', I first use the strptime() as suggested in the details help(as.POSIXct). e.g. starttime<-strptime("1/1/1999 01:01:01",format="%d/%m/%Y %H:%M:%S")

I think the following examples illustrate the crux of the matter (version and OS info are below). The problem has to do with the transition from standard time to daylight savings time. My timezone, US/Pacific, has two parts: standard time (PST) 8 hours behind GMT and daylight savings time (PDT) 7 hours behind GMT. The transition takes place this year on 7 April at 02:00, when 02:00 is

Hi This code should explain what I'm trying to do > strptime("30-Jan-08", "%d-%b-%y") [1] "2008-01-30" > > format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") [1] "Jan-08" > > strptime(format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") , "%b-%y") [1] NA I have a

Hi All In trying to correlate some tide gauge data I need to deal with varying timezones. From the documentation on strptime, it seemed that the tz variable might have some effect on the conversion, but I'm not seeing an effect. > strptime("20061201 1:02 PST",format="%Y%m%d %H:%M",tz="PST")+0 [1] "2006-12-01 01:02:00 EST" >

I'm trying to proess date/time fields from files that were given to me to analyze. Any clues what I'm doing wrong with strptime? This seems to fail the same way under Linux or Windows. For ?strptime would it make sense to explain %OS3 somewhere besides the Examples? > # Why does %OS3 work here? > format(Sys.time(), "%H:%M:%S") [1] "16:45:19" >

Dear list members, I have come about a peculiar behavior in R (4.0.2) which I would describe as a bug. On macOS, where `strptime()` raises a warning for invalid timezone identifiers, the following code will continue to raise the original warning with every subsequent call to `strptime()`: ``` # attach a handler for warnings for this call only: tryCatch(strptime('2020-10-31 18:30', format

Hello, I cannot reproduce this behavior and, as documented, the posted code doesn't issue warnings due to a wrong timezone but I'm running sessionInfo() R version 4.0.3 (2020-10-10) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Ubuntu 20.04.1 LTS Matrix products: default BLAS: /usr/lib/x86_64-linux-gnu/blas/libblas.so.3.9.0 LAPACK:

Hi, I am having a trouble parsing dates using strptime() that I get in the format of year and week number. The data looks like this "201127" which means year 2011 and week 27. I would like to graph this using ggplot but then I get a gap between 201054 and 201101 so I thought I would just easily convert it. I tried to use strptime and as.Date and the format string of %Y%W but it seems

Hi Frederik, On Mon, 2017-01-16 at 18:20 -0800, frederik at ofb.net wrote: > Hi R Devel, > > I wrote some code which depends on 'strptime' being able to parse an > incomplete date, like this: > > > > > base::strptime("2016","%Y") > [1] "2016-01-14 PST" > > The above works - although it's odd that it gives the month

Hello, Please excuse me if this question has been asked before. I'm new to R, and have been trying to google the answers without any success. I would like to convert a set of date and time into R date-time class. Right now, the dates and times are in integer format, so I first need to convert them into string, and then to R date-time using strptime. However, I have a problem converting them

There is incompatibility between R strptime and musl libc. I posted about it on their mailing list, but they need more information I can't provide, so I'm forwarding the message here in hope R developers can help. Thanks. ---------- Forwarded message ---------- From: Rich Felker <dalias at libc.org> Date: Thu, Feb 4, 2016 at 2:07 PM Subject: Re: [musl] strptime() question To: Alba