similar to: searching and replacing in a data frame.

Dear Olivier, Many thanks for your reply. Very cool. You know what I thought ? I thought you had modified the A4 sheet size to compute the paperheight and paperwidth ? I wonder if that's another way of proceeding. Best, Ashim On Sat, Nov 18, 2023 at 12:51?PM Olivier Crouzet <olivier.crouzet at univ-nantes.fr> wrote: > > Dear Ashim, > > these are documented in the LaTeX

Dear All, we need to do : library(car) for the spreadLevelPlot function I forgot to say that. Apologies, Ashim On Sun, Jan 7, 2018 at 10:37 AM, Ashim Kapoor <ashimkapoor at gmail.com> wrote: > Dear All, > > I want a transformation which will make the spread of the response at all > combinations > of 2 factors the same. > > See for example : > >

And indeed again (I did not understand your previous question exactly at first), the 'hard-coded' definition of a landscape a4 sheet would therefore be: paperwidth=29.7cm, paperheight=21cm Olivier. On Sat, 18 Nov 2023 13:20:49 +0530 Ashim Kapoor <ashimkapoor at gmail.com> wrote: > Dear Olivier, > > Many thanks for your reply. > > Very cool. > > You know

Dear All, I want a transformation which will make the spread of the response at all combinations of 2 factors the same. See for example : boxplot(breaks ~ tension * wool, warpbreaks) The closest I can do is : spreadLevelPlot(breaks ~tension , warpbreaks) spreadLevelPlot(breaks ~ wool , warpbreaks) I want to do : spreadLevelPlot(breaks ~tension * wool, warpbreaks) But I get : >

Dear Ashim, I?ll address your questions briefly but they?re really not appropriate for this list, which is for questions about using R, not general statistical questions. (1) The relevant distribution is within cells of the wool x tension cross-classification because it?s the deviations from the cell means that are supposed to be normally distributed with equal variance. In the warpbreaks data

On Thu, 08 Jun 2023, Ashim Kapoor writes: > Dear All, > > I had done an automatic upgrade of my Debian 10 system which had also > upgraded R. > > I reinstalled the stargazer package and the error went away. > > Query : Do I need to reinstall all packages with each upgrade of R ? > > Best, > Ashim Your session info says "stargazer 5.2.2". What version

Dear Ashim, these are documented in the LaTeX 'geometry' package (see for example on CTAN: https://ctan.org/pkg/geometry). As I added in my response on Stackoverflow, several parts in the RMarkdown header actually concern information that are processed by LaTeX to actually generate the PDF, among which the 'geometry' line. For someone who is used to working with LaTeX, it is

Dear All, Here is a reprex: > x<- 1:100 > x[-which(x>100)] integer(0) In words, I am finding out which indices correspond to values in x which are greater than 100 ( there are no such items ) . Then I remove those indices. I should get back the x that I started with since there are no items in x which are bigger than 100 . Instead, it is returning an empty vector. Why is this ?

Dear All, I had done an automatic upgrade of my Debian 10 system which had also upgraded R. I reinstalled the stargazer package and the error went away. Query : Do I need to reinstall all packages with each upgrade of R ? Best, Ashim On Thu, Jun 8, 2023 at 11:11?AM Ashim Kapoor <ashimkapoor at gmail.com> wrote: > > Dear All, > > Here is my reproducible example: > >

Dear Olivier, Many thanks for your reply. This works well for me. How did you come up with the pagewidth / pageheight numbers? I do understand that their ratio = 16:9, but how did you choose these numbers? Best Regards, Ashim On Fri, Nov 17, 2023 at 9:25?PM Olivier Crouzet <olivier.crouzet at univ-nantes.fr> wrote: > > Dear Ashim, > > I don't think the aspectratio is

Dear R-helpers, Please have a look at the following. f1 is the same as f2 except that it has some values replaced by NA. But it's corresponding file is slightly bigger than the file containing f2. Could someone please tell me if this is an anomaly ? > load("file1") > ls() [1] "f1" > load("file2") > ls() [1] "f1" "f2" > >

Dear Ashim, Try spreadLevelPlot(breaks ~ interaction(tension, wool), data=warpbreaks) . I hope this helps, John ----------------------------- John Fox, Professor Emeritus McMaster University Hamilton, Ontario, Canada Web: socialsciences.mcmaster.ca/jfox/ > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Ashim > Kapoor > Sent:

Dear Sir, Many thanks for your reply. I have a query. I have a whole set of distributions which should be made normal / homoscedastic. Take for instance the warpbreaks data set. We have the following boxplots for the warpbreaks dataset: a. boxplot(breaks ~ wool) b. boxplot(breaks ~ tension) c. boxplot(breaks ~ interaction(wool,tension)) d. boxplot(breaks ~ wool @ each level of tension) e.

Look at which(x>100) This is a zero-length vector. The negative of nothing is nothing, not a list of all possible index values. Do you want x[ !( x > 100 ) ] ? On April 18, 2018 6:13:30 AM CDT, Ashim Kapoor <ashimkapoor at gmail.com> wrote: >Dear All, > >Here is a reprex: > >> x<- 1:100 >> x[-which(x>100)] >integer(0) > >In words, I am

Dear all, I have posted a query which has received a response but that is not working on my computer. Here is the query: https://stackoverflow.com/questions/77387434/pdf-from-rmarkdown-landscape-and-aspectratio-169 Can someone please help me ? Best Regards, Ashim

Dear Ashim, I don't think the aspectratio is appropriate in this context because it would imply that the beamer (LaTeX) class is used but you're actually using the article (LaTeX) class. You may use specifications of the geometry package rather than specifying options to the class: e.g. replace your current header: --- title: "Testing landscape and aspect ratio" output:

Dear All, I am trying to use the function ses from the forecast package. >From its help I have : Usage: ses(y, h = 10, level = c(80, 95), fan = FALSE, initial = c("optimal", "simple"), alpha = NULL, lambda = NULL, biasadj = FALSE, x = y, ...) My query is that if I do not mention the initial value will its default value be "optimal". A MWE would be

The first one, i.e. "optimal"; check help for match.arg() for the idiom. -pd > On 2 Oct 2017, at 11:48 , Ashim Kapoor <ashimkapoor at gmail.com> wrote: > > Dear All, > > I am trying to use the function ses from the forecast package. > > From its help I have : > > Usage: > > ses(y, h = 10, level = c(80, 95), fan = FALSE, initial =

Dear R-helpers, It seems to me that a character zoo cannot be coerced to a numeric zoo. Below is a minimal example. Can someone tell me what I have done wrong? > z<-zoo(1:4,order.by=1:4) > coredata(z)<-as.character(coredata(z)) > str(z) ‘zoo’ series from 1 to 4 Data: chr [1:4] "1" "2" "3" "4" Index: int [1:4] 1 2 3 4 >

Zitat von Ashim Kapoor <ashimkapoor at gmail.com>: > Dear All, > > My query is: > > Do we always need to use perl = TRUE option when doing ignore.case=TRUE? > > A small example : > > my_text = > "RECOVERY OFFICER-II\nDEBTS RECOVERY TRIBUNAL-III\n RC No. 162/2015\nSBI > VS RAMESH GUPTA.\n Dated: 01.03.2016 Item no.01\n > Present: