similar to: R PLS package data format

Hi list, I am looking at the data yarn in package, I don't understand what is dimension of this data set. I did the following: > library(pls) > data(yarn) > dim(yarn) [1] 28 3 > head(yarn) NIR.1 NIR.2 NIR.3 NIR.4 NIR.5 NIR.6 NIR.7 NIR.8 NIR.9 NIR.10 NIR.11 1 3.06630 3.08610 3.10790 3.09720 2.99790 2.82730 2.62330 2.40390 2.19310 2.00580 1.83790 2

All, I am working with NIR spectral data and it was great to find that the example in ?plsr also used spectral data. Unfortunately, I am having difficulty figuring out how the "yarn" dataset is structured to allow for the plsr model to read: library(pls) data(yard) yarn.oscorespls <- mvr(density ~ NIR, 6, data = yarn, validation = "CV", method = "oscorespls")

Hi~ helpers. I was surprised by R data type. I use to data type like table. I don't know R allow several data type such as list, number, matrix in the same matrix. I want to use plsr in pls package to anlaysis data. So, I read R help and example of plsr. that example show me that data as yarn has three colname as NIR, density and train. the NIR was 268(No. of col) X 71(No. of row)

Hi. I was used to draw 2D plot to show distribution of my samples. It was very powerful in small samples. Recently , I handle a lot of type of samples as more 15. so, I want to use more dimention. I was used that I conduct plsda function and draw biplot, such as, p1=plsda(mw, sp) biplot(p1) How can I draw 3D graph with my data?? I don't know exactly numerical value each spot. please,

Hi, Currently I have a dataset of 2400*408. And I would like to apply PCR method to study the any correlation between the tests. My current data is in data.frame and I have formed horizontal(1-407) to be the exact data, and (408) to be my results data(Yes and No) I have also binarized these Yes and No to 1 and -1s. However, when I refer to PCR manual on R, the example of yarn.pcr <-

Version 2.0-0 of the pls package is now available on CRAN. The pls package implements partial least squares regression (PLSR) and principal component regression (PCR). Features of the package include - Several plsr algorithms: orthogonal scores, kernel pls and simpls - Flexible cross-validation - A formula interface, with traditional methods like predict, coef, plot and summary - Functions

Version 2.0-0 of the pls package is now available on CRAN. The pls package implements partial least squares regression (PLSR) and principal component regression (PCR). Features of the package include - Several plsr algorithms: orthogonal scores, kernel pls and simpls - Flexible cross-validation - A formula interface, with traditional methods like predict, coef, plot and summary - Functions

Hi, I have the following question about creating data frames. I want to create a data frame with 2 components: a vector and a matrix. Let me use a simple example: y <- rnorm(10) x <- matrix(rnorm(150), nrow=10) Now if I do dd <- data.frame(x=x, y=y) I get a data frame with 16 colums, but if, according to the documentation, I do dd <- data.frame(x=I(x), y=y) then str(dd)

Here are some data frames: df3.2 <- data.frame(1:3, 7:9) df4.2 <- data.frame(1:4, 7:10) df3.3 <- data.frame(1:3, 7:9, 10:12) df4.3 <- data.frame(1:4, 7:10, 10:13) df3.4 <- data.frame(1:3, 7:9, 10:12, 15:17) df4.4 <- data.frame(1:4, 7:10, 10:13, 15:18) Now here are some commands and their answers: > median(df3.2) [1] 2 8 > median(df4.2) [1] 2.5 8.5 > median(df3.3)

First I have a matrix called stocks1: > class(stocks1) [1] "matrix" Here are the first 5 rows of the last 4 columns: > stocks1[1:5,2:5] [,1] [,2] [,3] [,4] [1,] 80.73 31.95 25.4 25.69 [2,] 83.66 31.95 27.12 25.2 [3,] 83.27 32.93 28.74 26.29 [4,] 83.9 34.07 29.77 26.6 [5,] 82.74 35.18 30.24 27.41 Now, why can't I convert this into a dataframe?

Hi - I am using pls package for some pcr computations. There is a data set called gasoline. Would someone be able to tell me what command(s) could be used to produce this graph in R? I am not sure where the log(1/R) - Y-axis - are coming from Thanks much Ravi

Hi R Users, I have been trying to work out how to rename column names using grep, basically I have generated these column names using tapply: [1] "NAME" "X1.1" "X2.1" "X3.1" "X4.1" "X5.1" "X6.1" "X7.1" "X8.1" [10] "X1.2" "X2.2" "X3.2" "X4.2"

Dear developeRs, I maintain a package 'pls', which has a main fit function mvr(), and functions plsr() and pcr() which are meant to take the same arguments as mvr() and do exactly the same, but have different default values for the 'method' argument. The three functions are all exported from the name space. In the 'pre namespace' era, I took inspiration from lm() and

Dear list! I have run into a problem that seems very simple but I can't find any solution to it (have searched the internet, help-files and "An introduction to R" etc without any luck). The problem is the following: I would like to create a data.frame with two components (columns), the first component being a matrix and the second component a vector. Whatever I have tried so far, I

Hi, I want to calculate PLS package in R. Now I want to calculate R, MSEP, RMSEP and R2 of PLSR and PCR using this. I also add this in library of R. How I can calculate R, MSEP, RMSEP and R2 of PLSR and PCR in R. I s any other method then please also suggest me. Simply I want to calculate these value. Thanking you. -- Nitish Kumar Mishra Junior Research Fellow BIC, IMTECH, Chandigarh, India

Dear all, I am using the pls package of R to perform partial least square on a set of multivariate data. Instead of fitting a linear model, I want to fit my data with a quadratic function with interaction terms. But I am not sure how. I will use an example to illustrate my problem: Following the example in the PLS manual: ## Read data data(gasoline) gasTrain <- gasoline[1:50,] ## Perform

> On Jul 13, 2017, at 10:43 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > > poly(NIR, degree = 2) will work if NIR is a matrix, not a data.frame. > The degree argument apparently *must* be explicitly named if NIR is > not a numeric vector. AFAICS, this is unclear or unstated in ?poly. I still get the same error with: library(pld) data(gasoline) gasTrain <-

> On Jul 12, 2017, at 6:58 PM, Ng, Kelvin Sai-cheong <kscng at connect.hku.hk> wrote: > > Dear all, > > I am using the pls package of R to perform partial least square on a set of > multivariate data. Instead of fitting a linear model, I want to fit my > data with a quadratic function with interaction terms. But I am not sure > how. I will use an example to

I have two ideas about it. 1- i) Entering variables in quadratic form is done with the command I (variable ^ 2) - plsr (octane ~ NIR + I (nir ^ 2), ncomp = 10, data = gasTrain, validation = "LOO" You could also use a new variable NIR_sq <- (NIR) ^ 2 ii) To insert a square variable, use syntax I (x ^ 2) - it is very important to insert I before the parentheses. iii) If you want to

Below. -- Bert Bert Gunter On Thu, Jul 13, 2017 at 3:07 AM, Luigi Biagini <luigi.biagini at gmail.com> wrote: > I have two ideas about it. > > 1- > i) Entering variables in quadratic form is done with the command I > (variable ^ 2) - > plsr (octane ~ NIR + I (nir ^ 2), ncomp = 10, data = gasTrain, validation = > "LOO" > You could also use a new variable