similar to: matrix problem

Hello, I'd like to transpose data to create an analysis-friendly dataframe. See below for an example, I was unable to use t(x) and I couldn't find a function with options like PROC TRANSPOSE in SAS. The ideal solution handles variable quantities of SITE - but beggars can't be choosers. :-) Thank you in advance, Mike ## INPUT DATA USER_ID<-c(1,1,1,2,2,2,3,3,4) SITE

Hi Listers, Is there a way that I can transpose an array... Suppose I have the following array... x<-array(c(1,2,3,4),dim=c(1,2,2)) , , 1 [,1] [,2] [1,] 1 2 , , 2 [,1] [,2] [1,] 3 4 And I would like to get the following result... , , 1 [,1] [1,] 1 [,2] 2 , , 2 [,1] [,2] [1,] 3 [,2] 4 Thanks in advance, Marcio -- View this message in context:

Hi to all, In other statistical software, such as Eviews, it is possible to regress a model with the Least Squares method, assuming that the residuals follow an AR(q) process. For example the resulting regression is something like y = 1.2154 + 0.2215 x + 0.251 AR(1) How is it possible to do the same in R? Thank you very much in advance, Constantine Tsardounis http://www.costis.name

Dear list, Im trying to do the following operation but im not able to do it This is my table: 1 2 3 1 0 7 4 2 0 2 0 3 0 1 3 4 0 3 4 what i would like to do is divide each row values with the corresponding column' sum,namely: 1 2 3 1 0 0.54 0.36 2 0 0.15 0 3 0 0.08

Hello everybody When one is working with complex matrices, "transpose" very nearly always means *Hermitian* transpose, that is, A[i,j] <- Conj(A[j,i]). One often writes A^* for the Hermitian transpose. I have only once seen a "real-life" case where transposition does not occur simultaneously with complex conjugation. And I'm not 100% sure that that wasn't a

Hi All, I want to ask if there is a transpose function for data frame like the procedure of transpose in SAS? Because I want to partially transpose a data frame which contains 5 columns (siteid, date, time, obs, mod), what I want to do is to put time as the column variables along with siteid, and date, and put obs and mod in the row names. specifically to transpose a data frame: siteid date

I am just starting to code in R and need some help as I am used to doing this in SAS. I have a dataset that looks like this: Chemical Well1 Well2 Well3 Well4 BOD 13.2 14.2 15.5 14.2 O2 7.8 2.6 3.5 2.4 TURB 10.2 14.6 18.5 17.3 and so on with more chemicals.... I would like to transpose my data so that it looks like this: Chemical WellID Value BOD Well1 13.2 BOD Well2 14.2 BOD Well3 15.5 BOD

Hi, New to R, using version 2.0.1 (2004-11-15) on debian Linux (sid), kernel 2.6.8-2-686. I have data in files with separate vectors on each row of the file, e.g., $ cat /tmp/stats freq,0,1,2,3,4,5,6,7,8,9,16,17,18,19,20,... noise,49,47,48,48,50,47,48,47,46,50,48,54,49,47,49,... signal,99,0,100,0,0,100,0,100,100,0,100,101,100,0,0,... pctrcv,5,0,5,0,0,5,0,5,11,0,5,5,5,0,0,...

Hello All, I was wondering if it's possible to reshape data from long to wide in R without using a "timevar". I've pasted some sample data below along with some code. The data are sorted by Subject and Drug. I want to transpose the Drug variable into multiple columns in alphabetical order. My data have a variable called "RowNo" that functions almost like a

I want to transpose a dataframe like level 2006 2007 2008 A .... B ..... C ........ into level year A 2006 A 2007 A 2008 B 2006 B 2007 ...... There is a procedure in SAS can do this, is there any function in R can do this? -- View this

I decided to do a direct comparison of transpose and sweep. library(microbenchmark) NN <- matrix(c(1, 2, 3, 4, 5, 6), nrow = 2, byrow = TRUE) # Example matrix lambda <- c(2, 3, 4) # Example vector colNN <- t(NN) microbenchmark( sweep = sweep(NN, 2, lambda, "/"), transpose = t(t(NN)/lambda), colNN = colNN/lambda ) Unit: nanoseconds expr min lq

Hi all, Here''s another contribution for anyone interested. In Railscast episode 28, Ryan Bates showed us in_groups_of which allows you to group array members such as >> list = [1, 2, 3, 4, 5, 6, 7] => [1, 2, 3, 4, 5, 6, 7] >> list.in_groups_of(3) => [[1, 2, 3], [4, 5, 6], [7, nil, nil]] This allows you to iterate over the groups and, for example, display a list

Suppose this is my list of transactions: set.seed(200) tran=random.transactions(100,3) inspect(tran) items transactionID 1 {item80} trans1 2 {item8, item20} trans2 3 {item28} trans3 I want to get the 'transpose' of the data, i.e. transactionID items 1 {trans2} item8 2 {trans2} item20 3 {trans3} item28 4 {trans1} item80 I

ABCD are four matrix. A * Inverse((Transpose(A)*Tranpose(B)*B*A+C)) * Transpose(A) * Transpose(B) * D how to write in R in an efficient way? --------------------------------- [[alternative HTML version deleted]]

Hi guys, I need your help!! My goal is to make a csv file from ncdf file. This is the code i've used : > hyo=open.ncdf("C:/CRUTEM3.nc") > hyo [1] "file C:/CRUTEM3.nc has 4 dimensions:" [1] "longitude Size: 72" [1] "latitude Size: 36" [1] "unspecified Size: 1" [1] "t Size: 1916" [1] "------------------------"

Hi Everyone, I have a dataset like this mean sd 0% 25% 50% 75% 100% n BODY TEMPERATURE 36.41099 0.4015699 35.1 36.22222 36.5 36.66667 37.1 89 DIASTOLIC BLOOD PRESSURE 73.60079 9.4656186 50.0 67.00000 73.0 80.00000 95.0 253 HEIGHT 171.94000 9.2011670 153.5 166.50000 173.0 176.25000 190.0

Hi I'm trying to use ouch's hansen and brown functions but I get the error: > brown(logflatnodes,archotreeouch) Error in backsolve(l, x, k = k, upper.tri = upper.tri, transpose = transpose) : NA/NaN/Inf in foreign function call (arg 1) and with hansen also: Error in optim(par = c(sqrt.alpha, sigma), fn = function(par) { : function cannot be evaluated at initial parameters

Transpose vector extracted from a matrix Hello, I am doing a recursive analysis that uses every line (vector) of a matrix in a loop. In the model, I need to transpose those vectors that are extracted from a matrix. Using simple vectors (no matrix involved) the transpose function works fine: simplevector <-matrix(1:3,3,1) tsimplevector <-t(simplevector) #transposed dim(simplevector)

I have a data set in the following format: x<-data.frame(id=c(‘a’,’b’,’c’),’2005-01-15’=c(100,225,425), ’2005-02-23’=c(1100,2325,4525)) > x id X2005.01.15 X2005.02.23 1 a 100 1100 2 b 225 2325 3 c 425 4525 I want: id a b c X2005.01.15 100 225 425 X2005.02.23 1100

I'm hoping that someone with deeper insight into S4 than I, that is to say virtually everyone reading this list, could help resolve the following problem in SparseM. We have setGeneric("backsolve", function(r, x, k = NULL, upper.tri = NULL, transpose = NULL, twice = TRUE, ...) standardGeneric("backsolve"), useAsDefault= function(r, x,