similar to: issue with strptime

Dear all, I created a n*2 matrix and I want to replace the ith row with a vector. Can anyone suggest me what is the simple way to do it? Sorry for bothering you with such simple question. I appreciate any hints or advice. Thanks in advance. Cassie [[alternative HTML version deleted]]

Dear all, I am trying to simulate from truncated Pareto distribution. I know there is a package called PtProcess for Pareto distribution...but it is not for truncated one. Can anyone please help me with this? Thanks in advance. Cassie [[alternative HTML version deleted]]

Dear all, I am trying to simulate from discrete uniform distribution. But I could not find any in-built code in R. Could anyone help me please? Thanks in advance for the time and help. Cassie [[alternative HTML version deleted]]

> is.na(strptime("5/2/1992", format="%m/%d/%Y")) [1] FALSE > is.na(strptime("5/3/1992", format="%m/%d/%Y")) [1] TRUE Any idea what's going on with this? Running strptime against all dates from around 1946, only 5/3/1992 was converted as "NA". Even stranger, it still seems to have a value associated with it (even though is.na thinks

Hello everyone, I am wondering if there is any routine in R which can convert time given in 'seconds' unit to the 12 hour time format. For example, suppose the data set looks like x=c(36885,84000,20) #x in seconds I want to get the output as [1] " 11:14:45 AM" [2] " 11:20:00 PM" [3] "12:20:00 AM" Does anyone have any idea? Thanks in advance. Cassie

On Tue, Jan 10, 2017 at 08:13:21PM -0600, Dirk Eddelbuettel wrote: > > On 10 January 2017 at 17:48, frederik at ofb.net wrote: > | Hi R Devel, > | > | I just ran into a corner case with 'strptime'. Recall that the "%OS" > | conversion accepts fractional seconds: > | > | > strptime("17_35_14.01234.mp3","%H_%M_%OS.mp3")$sec > |

Hi R Devel, I just ran into a corner case with 'strptime'. Recall that the "%OS" conversion accepts fractional seconds: > strptime("17_35_14.01234.mp3","%H_%M_%OS.mp3")$sec [1] 14.01234 Unfortunately for my application it seems to be "greedy", in that it tries to parse a decimal point which might belong to the rest of the format: >

Hi This code should explain what I'm trying to do > strptime("30-Jan-08", "%d-%b-%y") [1] "2008-01-30" > > format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") [1] "Jan-08" > > strptime(format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") , "%b-%y") [1] NA I have a

Hi All In trying to correlate some tide gauge data I need to deal with varying timezones. From the documentation on strptime, it seemed that the tz variable might have some effect on the conversion, but I'm not seeing an effect. > strptime("20061201 1:02 PST",format="%Y%m%d %H:%M",tz="PST")+0 [1] "2006-12-01 01:02:00 EST" >

I'm trying to proess date/time fields from files that were given to me to analyze. Any clues what I'm doing wrong with strptime? This seems to fail the same way under Linux or Windows. For ?strptime would it make sense to explain %OS3 somewhere besides the Examples? > # Why does %OS3 work here? > format(Sys.time(), "%H:%M:%S") [1] "16:45:19" >

Hi, I am having a trouble parsing dates using strptime() that I get in the format of year and week number. The data looks like this "201127" which means year 2011 and week 27. I would like to graph this using ggplot but then I get a gap between 201054 and 201101 so I thought I would just easily convert it. I tried to use strptime and as.Date and the format string of %Y%W but it seems

Hi Frederik, On Mon, 2017-01-16 at 18:20 -0800, frederik at ofb.net wrote: > Hi R Devel, > > I wrote some code which depends on 'strptime' being able to parse an > incomplete date, like this: > > > > > base::strptime("2016","%Y") > [1] "2016-01-14 PST" > > The above works - although it's odd that it gives the month

Hi everybody When I try example of strptime x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") z <- strptime(x, "%d%b%Y") The result is; > z [1] NA NA NA NA I have got the same result with complete form of month but not with numeric form. Any idea? [[alternative HTML version deleted]]

Full_Name: Bill Hutchison Version: 2.2.1 OS: Windows XP Submission from: (NULL) (69.158.121.13) example(strptime) produces the following error: Error in strptime(x, "%d%b%Y") : 2 arguments passed to 'strptime' which requires 3 This error occurs wherever strptime is used. It does not occur in 2.2.0

Converting date strings that range between Mar-14-2010 2:00 and Mar-14-2010 2:59 (inclusive) to date objects (POSIX) returns a NA entity: > strptime("3/14/2010 2:00",format="%m/%d/%Y %H:%M") [1] "2010-03-14 02:00:00" This looks fine, however other functions such as plot see a NA object instead: > is.na(strptime("3/14/2010

I think the following examples illustrate the crux of the matter (version and OS info are below). The problem has to do with the transition from standard time to daylight savings time. My timezone, US/Pacific, has two parts: standard time (PST) 8 hours behind GMT and daylight savings time (PDT) 7 hours behind GMT. The transition takes place this year on 7 April at 02:00, when 02:00 is

Is there a way to make as.Date() and strptime() process strings with negative years? It appears that Date objects can contain negative years and you can convert them to strings, but you can't convert them back to Date objects. x <- as.Date(c("0001-01-24", "0500-01-24")) as.character(x) # "0001-01-24" "0500-02-02" as.Date(as.character(x)) #

I'm sure this is just the result of a basic misunderstanding of the syntax of R, but I am stumped. A <- read.table(file="sumByThirtyMinute.csv",sep=",",col.names=c("date","pandl")) A now consists of thousands of rows, but A$date is a string... ... 3183 2006-02-28 12:00:00 548.470 3184 2006-02-28 12:30:00 515.240 3185 2006-02-28 13:00:00

Hello, I cannot reproduce this behavior and, as documented, the posted code doesn't issue warnings due to a wrong timezone but I'm running sessionInfo() R version 4.0.3 (2020-10-10) Platform: x86_64-pc-linux-gnu (64-bit) Running under: Ubuntu 20.04.1 LTS Matrix products: default BLAS: /usr/lib/x86_64-linux-gnu/blas/libblas.so.3.9.0 LAPACK:

Dear R-people! I am using R 1.8.0, under Windows XP. What I want to do is a date conversion of a character column of a data frame and assign the result as a new column. Simple example: > x <- data.frame(a=c("yesterday","today","tomorrow"), b=I(c("20031111", "20031112", "20031113"))) # convert x$b from character to date: >