similar to: animation error

Displaying 20 results from an estimated 400 matches similar to: "animation error"

2017 Dec 18
0
Finding center of mass in a hydrologic time series
Hi Eric, the following works for me. HTH, Eric library(EGRET) StartDate <- "1990-10-01" EndDate <- "2017-09-30" siteNumber <- "10310000" QParameterCd <- "00060" Daily <- readNWISDaily(siteNumber, QParameterCd, StartDate, EndDate) # Define 'center of mass' function com <- function(x) { match(TRUE, cumsum(x/sum(x)) > 0.5) -
2012 Sep 11
1
Animation Problem
Hi List, I am trying to build an animation and facing problem as animation is not coming "live". The goal is to build "heart beats" like diagram for the data given below. data : structure(list(date = 1971:1991, x = c(41L, 60L, 41L, 61L, 22L, 83L, 31L, 55L, 22L, 14L, 38L, 6L, 29L, 17L, 10L, 99L, 88L, 32L, 68L, 78L, 26L)), .Names = c("date", "x"), class =
2017 Jun 07
0
Determining which.max() within groups
cumsum() seems to be what you need. This can probably be done more elegantly, but ... out <- aggregate(Q ~ wyr, data = Daily, which.max) tbl <- table(Daily$wyr) out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)])) out ## yields wyr Q 1 1990 4 2 1991 6 3 1992 9 4 1993 15 5 1994 18 I leave the matter of Julian dates to you or others. Cheers, Bert Bert Gunter "The trouble
2017 Dec 18
2
Finding center of mass in a hydrologic time series
Eric B's response provided just the kind of quick & simple solution I was hoping for (appears as the function com below). However, I once again failed to take advantage of the power of R and have reverted back to using a for loop for the next step of the processing. The example below (which requires the library EGRET for pulling an example dataset) works, but probably can be replaced
2017 Dec 16
0
Finding center of mass in a hydrologic time series
Hi Eric, How about match( TRUE, cumsum(hyd/sum(hyd)) > .5 ) - 1 HTH, Eric On Sat, Dec 16, 2017 at 3:18 PM, Morway, Eric <emorway at usgs.gov> wrote: > The small bit of script below is an example of what I'm attempting to do - > find the day on which the 'center of mass' occurs. In case that is the > wrong term, I'd like to know the day that essentially cuts
2017 Sep 13
0
compounding precipitation based on whether falls within a day
Thanks for the reprex. Wouldn't have bothered without it. The following is I believe **almost** what you want. It seems a bit clumsy to me, so others may provide you something neater. But anyway... ## Convert POSIXct vector to dates ## There are 22 different days, not 21 date <- as.Date(prec_idx) ## Sum results by date at each i,j of the last 2 array dimensions z <-
2013 Jan 26
2
a function more appropriate than 'sapply'?
I'm wondering if I need to use a function other than sapply as the following line of code runs indefinitely (or > 30 min so far) and uses up all 16Gb of memory on my machine for what seems like a very small dataset (data attached in a txt file wells.txt <http://r.789695.n4.nabble.com/file/n4656723/wells.txt> ). The R code is:
2010 Jun 25
4
Average 2 Columns when possible, or return available value
Forum, Using the following data: DF<-read.table(textConnection("A B 22.60 NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA 102.00 NA 19.20 NA 19.20 NA NA NA NA NA NA NA 11.80 NA 7.62 NA NA NA NA NA NA NA NA NA NA NA 75.00 NA NA NA 18.30 18.2 NA NA NA NA 8.44 NA 18.00 NA NA NA 12.90 NA"),header=T) closeAllConnections() The second column is a duplicate
2013 Jan 23
2
setting off-diagonals to zero
The following 1460 x 1460 matrix can be throught of as 16 distinct 365 x 365 matrices. I'm trying to set off-diaganol terms in the 16 sub-matrices with indices more than +/- 5 (days) from each other to zero using some for loops. This works well for some, but not all, of the for loops. The R code I"m using follows. For some reason the third loop below zero's-out everything in the
2012 Feb 11
2
obtaining a true/false vector with combination of strsplit, length, unlist,
Hi, A pared down version of the dataset I'm working with: edm<-read.table(textConnection("WELLID X_GRID Y_GRID LAYER ROW COLUMN SPECIES CALCULATED OBSERVED w301_3 4428. 1389 2 6 18 1 3558 6490. w304_12 4836. 6627 2 27 20 1 3509 3228. 02_10_12080 3.6125E+04 13875 1 56 145 1
2010 Mar 20
2
different forms of nls recommendations
Hello, Using this data: http://n4.nabble.com/file/n1676330/US_Final_Values.txt US_Final_Values.txt and the following code i got the image at the end of this message: US.final.values<-read.table("c:/tmp/US_Final_Values.txt",header=T,sep=" ") US.nls.1<-nls(US.final.values$ECe~a*US.final.values$WTD^b+c,data=US.final.values,start=list(a=2.75,b=-0.95,c=0.731),trace=TRUE)
2011 Dec 01
2
legend, "lheight", and alignment
Hello, A bit of fairly simple code, yet I don't seem to be able to manipulate it quite as much as I would like: 1) It would be nice if the objects appearing in the legend were aligned, and by aligned I mean the boxes are centered over the lines. Do I need to adjust the use of "NA" in the code below to accomplish this? Here's how it appears on my machine:
2013 Jan 25
2
resizing data
Undoubtedly this question has been asked before, I just can't seem to find the combination of search terms to produce it. I'm trying to resize a dataset that is pulled into R using read.table. However, I think the same problem can be produced using matrix: x<-matrix(1:64,8) x # [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] #[1,] 1 9 17 25 33 41 49 57 #[2,] 2 10
2010 Jun 02
3
#Rscript error on Windows 7 operating system
Forum, I've been running some parameter estimation software (UCODE which is maintained by the USGS) that has the capability of running models in parallel on a local network. Each additional processor I can incorporate into the parent-child network helps cut the overall runtime, which is currently on the order of days. When a signal is sent to a child (or slave) processor a series of
2010 Feb 08
2
object 'xxx' not found
The following line of code seems fairly straight forward, yet it is kicking back an error message: for (i in 1:length(mean.natveg.frac)){month.observed[i]=as.numeric(names(mean.natveg.frac[i]))%%12} Error message: Error in month.observed[i] = as numeric(names(mean.natveg.frac[i]))%%12 : object 'month.observed' not found Seems like its not found because I'm trying to define it. Also
2011 Jan 04
0
Package animation update (v2.0-0)
Hi, The animation package 2.0-0 is on CRAN now. This version is a milestone of the animation package. It includes a new function saveHTML() which uses a much more elegant interface and is consistent in syntax with other save*() functions such as saveMovie(), saveSWF() and saveLatex(). Lots of demos have been added to demonstrate the flexibility of this package, e.g. now we can get the snapshots
2011 Jan 04
0
Package animation update (v2.0-0)
Hi, The animation package 2.0-0 is on CRAN now. This version is a milestone of the animation package. It includes a new function saveHTML() which uses a much more elegant interface and is consistent in syntax with other save*() functions such as saveMovie(), saveSWF() and saveLatex(). Lots of demos have been added to demonstrate the flexibility of this package, e.g. now we can get the snapshots
2011 Mar 18
1
points() rendering points outside of input
As a followup to pi-day, I attempted to make a .gif of a simulation based estimation of pi by plotting points inside a single quadrant of a circle (a la?http://www.drewconway.com/zia/?p=2667 ). ?When rendering the individual x,y pairs with points() I intermittently see points crop up around (2,0.5) but the input values for x and y are bounded between 0 and 1. square<-structure(c(0, 0, 1, 1, 0,
2012 Jun 06
3
extracting values from txt file that follow user-supplied quote
useRs- I'm attempting to scan a more than 1Gb text file and read and store the values that follow a specific key-phrase that is repeated multiple time throughout the file. A snippet of the text file I'm trying to read is attached. The text file is a dumping ground for various aspects of the performance of the model that generates it. Thus, the location of information I'm wanting
2017 Jun 07
4
Determining which.max() within groups
Using the dataset below, I got close to what I'm after, but not quite all the way there. Any suggestions appreciated: Daily <- read.table(textConnection(" Date wyr Q 1911-04-01 1990 4.530695 1911-04-02 1990 4.700596 1911-04-03 1990 4.898814 1911-04-04 1990 5.097032 1911-04-05 1991 5.295250 1911-04-06 1991 6.569508 1911-04-07 1991 5.861587 1911-04-08 1991 5.153666