Displaying 20 results from an estimated 3000 matches similar to: "Question on Manova"
2011 Jun 21
1
Stepwise Manova
Hello all,
I have a question on manova in R:
I'm using the function "manova()" from the stats package.
Is there anything like a stepwise (backward or forward) manova in R (like there is for regression and anova).
When I enter:
step(Model1, data=Mydata)
R returns the message:
Error in drop1.mlm(fit, scope$drop, scale = scale, trace = trace, k = k, :
no 'drop1'
2011 Mar 20
3
manova question
Dear friends,
Sorry for this somewhat generically titled posting but I had a question
with using contrasts in a manova context. So here is my question:
Suppose I am interested in doing inference on \beta in the case of the
model given by:
Y = X %*% \beta + e
where Y is a n x p matrix of observations, X is a n x m design matrix,
\beta is m x p matrix of parameters, and e is a
2010 Oct 29
1
Repeated Measures MANOVA
Hello all,
Is there an r function that exists that will perform repeated measures MANOVAs? For example, let's say I have 3 DVs, one between-subjects IV, and one within-subjects IV. Based on the documentation for the manova command, a function like that below is not appropriate because it cannot take Error arguments.
manova(cbind(DV1,DV2,DV3) ~ BetweenSubjectsIV * WithinSubjectsIV +
2011 Oct 18
1
contrasts in MANOVA
Dear r-helpers,
I have a query regarding use of contrasts in MANOVA.
summary(manova(model))
gives me only result of test for overall difference.
Would you be so kind and give me a hint how to get the same test statistics
(e.g.Pillai's) and P values for the predefined contrasts?
Best regards
Ondrej Mikula
--
Institute of Animal Physiology and Genetics
Academy of Sciences of the Czech
2011 Apr 27
1
centroid representation and MANOVA
hi all.
I have a matrix of data with 5 different groups and 20 individual
response per group, and about 12 variables collected for each. I want to
represent the result in a 2D plot. PCA is not so good because the
difference between the groups is not obvious. I have seen, in a recent
paper, people doing a MANOVA and representing it in a centroid plot
(they used Matlab to do it).
I would like
2010 Mar 15
2
R example code of Split-plot Manova
Hi,
Urgent help- I have not been using R and statistics in my research for a
long time, but still remember some concept. I would like to have a sample
code for Manova analysis of Split-plot experiment. Could someone please post
a sample code and a short input sample as well?
Thank you so much!
[[alternative HTML version deleted]]
2010 Apr 08
2
general linear hypothesis testing for manova model
Hello,
I have a MANOVA model and I want to test the following hypothesis: LBM =
0 where B is the parameter estimates.
Is there any function to do this in R?
Cheers,
Philippe
--
Philippe Hup?
Institut Curie, CNRS UMR 144, INSERM U900
26 rue d'Ulm
75005 Paris - France
Email : Philippe.Hupe at curie.fr
T?l : +33 (0)1 56 24 69 91
Fax: +33 (0)1 56 24 69 11
website :
2012 Feb 08
2
dropterm in MANOVA for MLM objects
Dear R fans,
I have got a difficult sounding problem.
For fitting a linear model using continuous response and then for re-fitting the model after excluding every single variable, the following functions can be used.
library(MASS)
model = lm(perf ~ syct + mmin + mmax + cach + chmin + chmax, data = cpus)
dropterm(model, test = "F")
But I am not sure whether any similar functions is
2012 Mar 19
1
car/MANOVA question
Dear colleagues,
I had a question wrt the car package. How do I evaluate whether a
simpler multivariate regression model is adequate?
For instance, I do the following:
ami <- read.table(file =
"http://www.public.iastate.edu/~maitra/stat501/datasets/amitriptyline.dat",
col.names=c("TCAD", "drug", "gender", "antidepressant","PR",
2004 May 24
2
Manova and specifying the model
Hi,
I would like to conduct a MANOVA. I know that there 's the manova() funciton and the summary.manova() function to get the appropriate summary of test statistics.
I just don't manage to specify my model in the manova() call. How to specify a model with multiple responses and one explanatory factor?
If I type:
2007 Feb 22
1
MANOVA usage
Hello,
I had a couple questions about manova modeling in R.
I have calculated a manova model, and generated a summary.manova output
using both the Wilks test and Pillai test.
The output is essentially the same, except that the Wilks lambda = 1 -
Pillai. Is this normal? (The output from both is appended below.)
My other question is about the use of MANOVA. If I have one variable which
has a
2012 Mar 13
4
MANOVA and Extra Sums-of-Squares Tests
I would like to conduct an extra sum-of -squares test that compares a full
MANOVA model (with all 1st order interactions) to a reduced model (no
interactions) to determine if I can drop all interactions at the same time.
This is analagous to an extra sum-of-squares F-test in ANOVA, but instead
using MANOVA. Is there a command in R that does this? If not, is there a
command that calculates
2007 Apr 05
1
MANOVA with repeated measurements
Hello,
I have a question regarding performing manova. I have an experiment where I want to measure 10 output variables for 3 different measurement methods. Since each of the methods requires some user interaction, I would also like to include repeated measures for each of the output variables to include intraobserver variability in the design.
How can I perform such a repeated-measures
2004 Feb 15
1
manova() with a data frame
I'm trying to learn to use manova(), and don't understand why none of
the following work:
> data(iris)
> fit <- manova(~ Species, data=iris)
Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) :
incompatible dimensions
> fit <- manova(iris[,1:4] ~ Species, data=iris)
Error in model.frame(formula, rownames, variables, varnames, extras,
2006 Nov 09
2
Repeated Measures MANOVA in R
Can R do a repeated measures MANOVA and tell what dimensionality the statistical variance occupies?
I have been using MATLAB and SPSS to do my statistics. MATLAB can do ANOVAs and MANOVAs. When it performs a MANOVA, it returns a
parameter d that estimates the dimensionality in which the means lie. It also returns a vector of p-values, where each p_n tests
the null hypothesis that the mean
2006 Feb 16
2
MANOVA: how do I read off within and between Sum-of-Squares info from the manova result?
Hi all,
I am experimenting the function "manova" in R.
I tried it on a few data sets, but I did not understand the result:
I used "summary(manova_result)"
and "summary(manova_result, test='Wilks')"
and they gave a bunch of numbers...
But I need the Sum-of-Squares of BETWEEN and WITHIN matrices...
How do I read off from the R's manova results?
Any
2003 Nov 22
3
summary.manova and rank deficiency
Hi all,
I have received the following error from summary.manova:
Error in summary.manova(manova.test, test = "Pillai") :
residuals have rank 36 < 64
The data is simulated data for 64 variables. The design is a 2*2 factorial with 10 replicates per treatment. Looking at the code for summary.manova, the error involves a problem with qr(). Does anyone have a suggestion as to how to
2001 Nov 08
2
Manova in R vs. SAS
While I was helping a SAS-using friend with an analysis I noticed some
differences in the multivariate test statistics, approximate F statistics,
and p-values in the manova function using R and proc GLM using SAS. The
univariate coefficients are identical. Is there a reason to expect R and SAS
to give different results?
Thanks,
Bill Kristan.
2003 Jun 10
1
Bootstraping with MANOVA
Hi,
Does anyone know what the error message mean?
> Boot2.Pillai <- function(x, ind) {
+ x <- as.matrix(x[,2:ncol(x)])
+ boot.x <- as.factor(x[ind, 1])
+ boot.man <- manova(x ~ boot.x)
+ summary(manova(boot.man))[[4]][[3]]
+ }
>
> man.res <- manova(as.matrix(pl.nosite) ~
+ as.factor(plankton.new[,1]))$residuals
> boot2.plank <-
2012 Aug 25
2
Standard deviation from MANOVA??
Hi,
I have problem getting the standard deviation from the manova output.
I have used the manova function: myfit <- manova(cbind(y1, y2) ~ x1
+ x2 + x3, data=mydata) .
I tried to get the predicted values and their standard deviation by using:
predict(myfit, type="response", se.fit=TRUE)
But the problem is that I don't get the standard deviation values, I only