similar to: Notes on R Objects

Hi all, I am hoping that someone can help me with a problem I am having with column headings. I have read a table into R using read.table: the rows are documents, and the columns are counts of regular expression matches (so that the column heading is the given regular expression). My problem is that read.table seems to be trying to interpret the regular expressions, or has trouble with the

Hello, I am currently attempting to introduce R at my company and am trying to import time series data from a text file into R to graph. The format of the text file is in date, data (e.g., 20040929 3.361). My problem is that I do not know how to get R to recognize the first column as a business date series. Or at the very least, I am unable to find a function that will grap the second column

I am trying to create basic descriptive statistics for a spatial dataset using moving windows of variable sizes. I found the filter(dataset, rep(1/a,1)) very useful for obtaining averages for a given moving window size "a" (a is the window size within a column of data in a matrix - the filter is applied to all columns automatically) I could not find anything analogous for

Hi, I have a dataframe that has a column of vectors that I need to extract off the character string before the first '.' character and put it into a separate column. I thought I could use 'strsplit' for it within 'transform', but I can't seem to get the right invocation. Here is a sample dataframe that has what I have, what I want, and what I get. Can someone tell

On Fri, Aug 7, 2015 at 12:01 PM, Matt Arsenault <Matthew.Arsenault at amd.com> wrote: > On 08/07/2015 11:35 AM, Jingyue Wu wrote: > > + the new llvm-dev > > On Fri, Aug 7, 2015 at 11:30 AM, Jingyue Wu <jingyue at google.com> wrote: > >> Hi folks, >> >> Unsurprisingly, leveraging the fact that certain address spaces don't >> alias can

I am new to R and trying to understand time series objects. I have 2 vectors, one containing rainfall values (lets call the vector "rain") and the other the time/date in seconds (lets call it "time"). Is there a method to create a time series object simply by giving the "rain" and "time" vectors as inputs? Something in the line of: time_series_object

Hi, I've just created: newEnvEval <- function(..., hash=FALSE, parent=parent.frame(), size=29L) { envir <- new.env(hash=hash, parent=parent, size=size); evalq(..., envir=envir); envir; } # newEnvEval() so that I can create an environment and assign objects to it in one go, e.g. env <- newEnvEval({ a <- 1; b <- 2; }); print(env$a); Does this already exists somewhere?

Just trying to create returns from prices, and do something like: returns.z = tail(prices.z,-1)/head(prices.z,-1) - 1 # should be equivalent to returns = exp(diff(log(prices.z))) - 1 Curiously, I get a zoo object back with zeros everywhere and also with the index having one fewer element than it should. Does anyone know how to pointwise divide zoo objects, and what exactly "/" is

Is it possible to refer to an object from within a method, as in *this *in Java? I can't find anything about this in the documentation. Sorry if I missed it. Thanks. *-- Russ Abbott* *_____________________________________________* *** Professor, Computer Science* * California State University, Los Angeles* * Google voice: 747-*999-5105 * blog: *http://russabbott.blogspot.com/ vita:

Dear all, I would like to log the calls to my functions. I am trying to do this using the function match.call(): fTest<-function(x) { theCall<-match.call() print(theCall) return(x) } > fTest(2) fTest(x = 2) [1] 2 I can see "theCall" printed into the console, but I don't manage to convert it into a character to write it into a log file

In a time series ts object, like the z1.ts below: z1 = array(1:235) z1.ts = ts(z1, frequency =12) I would like to select only a certain month, for instance the "February" data If I transform the data to a matrix, I have the problem that 235 is not a multiple of 12 I do not like to cut or add data, or program a loop to pick out the correct data. I am wondering if exist an easier

Hello all, I have a problem with one of my routing requirements when using IPSec along with a proprietary Mobile IP implementation. And sorry for such a long mail :( Here is a brief description of my situation: My client (mobile-node) has an IP address of 10.10.10.40, my gateway (actually home-agent) has an IP address of 10.10.10.1 and systems in my home network are in 10.0.0.0 network.

Is there an elegant way to do operations (+/-/*/ / ) on zoo/xts objects when one serie is monthly (end of month) and the other daily (weekdays only) - typically a monthly economic indicator and a stock index price? Thanks, TDB -- View this message in context: http://r.789695.n4.nabble.com/How-to-do-operations-on-zoo-xts-objects-with-Monthly-and-Daily-periodicities-tp3558081p3558081.html

Can someone explain why this happens when one of the list elements is named 'all'? > zz <- list( zoo(1:10,1:10), zoo(101:110,1:10), zoo(201:210,1:10) ) > names(zz)<-c('test','bar','foo') > do.call(cbind,zz) test bar foo 1 1 101 201 2 2 102 202 3 3 103 203 4 4 104 204 5 5 105 205 6 6 106 206 7 7 107 207 8 8 108 208 9

Dear all I have a work-flow issue with lm(). When I use > lm(y1~x1, anscombe) Call: lm(formula = y1 ~ x1, data = anscombe) Coefficients: (Intercept) x1 3.0001 0.5001 I get as expected the formula, "y1 ~ x1", in the print()ed results or summary(). However, if I pass through a formula object > (form <- formula(y1~x1)) y1 ~ x1 > lm(form, anscombe) Call:

Alright, I'm taking the plunge: We're switching our three AD DCs from Samba internal to BIND_DLZ back end. I needed a version of BIND with DLZ, as it appears support for that is not so ubiquitous. I went here first: https://wiki.samba.org/index.php/Using_BIND_DLZ_backend_with_secured_/_signed_DNS_updates We use Ubuntu 14.04 here, and the Debian/Ubuntu instructions fail on apt-get

I learnt that functions can be handled as objects, the same way the variables are. So, the following is perfectly valid: > f = function(a, b) { + print(a) + print(b) + } > > f1 = function(foo) { + foo(1,2) + } > > f1(f) [1] 1 [1] 2 > I also know that operators are functions, so, I can call: > '+'(1,2) [1] 3 > However, when I want to pass the

Hi All, I've been trawling through the documentation and listserv archives on this topic -- but as yet have not found a solution. I'm sure this is pretty simple with R, but I cannot work out how without resorting to ugly nested loops. As far as I can tell, grep, match, and %in% are not the correct tools. Question: given these vectors -- patrn <- c(1,2,3,4) exmpl <-

Fellow R programmers, I'd like to submit SQLDF statements with R objects as column names. For example, I want to assign "X" to "var1" (var1<-"X") and then refer to "var1" in the SQLDF statement. SQLDF needs to understand that when I reference "var1", it should look for "X" in the dataframe. This is necessary because my SQLDF

Dear all, I have following 2 zoo objects. However when I try to merge those 2 objects into one, nothing is coming as intended. Please see below the objects as well as the merged object: > dat11 V2 V3 V4 V5 2010-10-15 13:43:54 73.8 73.8 73.8 73.8 2010-10-15 13:44:15 73.8 73.8 73.8 73.8 2010-10-15 13:45:51 73.8 73.8 73.8 73.8 2010-10-15 13:46:21 73.8 73.8 73.8 73.8