similar to: Use line break at scrip but avoid line break on graphics

Displaying 20 results from an estimated 400 matches similar to: "Use line break at scrip but avoid line break on graphics"

2011 Feb 15
1
ternary contour plot
Colin, If your propose is to create a ternary plot with points and vectors, I think easier do this with graphics based plots instead of trellis based plots. Although, with little work you can do with trellis too. I gave you a reproducible code to put an arrow in a ternary plot. I use the function locator() to extract coordinates. The code is the following
2011 Aug 06
1
multcomp::glht() doesn't work for an incomplete factorial using aov()?
Hi R users, I sent a message yesterday about NA in model estimates ( http://r.789695.n4.nabble.com/How-set-lm-to-don-t-return-NA-in-summary-td3722587.html). If I use aov() instead of lm() I get no NA in model estimates and I use gmodels::estimable() without problems. Ok! Now I'm performing a lot of contrasts and I need correcting for multiplicity. So, I can use multcomp::glht() for this.
2012 Apr 11
1
Lattice densityplot with semitransparent filled regions
Hello, I'm doing some graphics for a paper and a need customize such with filled region above the density curve. My attempts I get something very near what I need, but I don't solve the problem of use semitransparent filled. Below a minimal reproducible code. Someone has any idea? require(lattice) # toy data... dt <- expand.grid(A=1:2, B=1:3, y=1:50) dt$y <- rnorm(nrow(dt), dt$B,
2010 Feb 17
2
How to provide a result from D(f(x), "x") to a curve(f'(x)) ???
Hi all, I want to provide the result from D() to curve(), because I want to plot the k-th derivative of some functions. Actually, I copy from console the result given by D() and paste inside curve(). With a lot of functions and high degree differentiation this process is tedious. Can I provide directly?? # what I actually have done (very simple function) D(expression(x^3), "x") # copy
2011 Jun 01
1
xtable with conditional formatting using \textcolor
Hello list, I'm doing a table with scores and I want include colors to represent status of an individual. I'm using sweave <<results=tex>>= and xtable but I can't get a result I want. My attemps are #----------------------------------------------------------------------------- # code R da <- data.frame(id=letters[1:5], score=1:5*2) col <- function(x){
2010 May 26
1
Is possible a mini-plot into a big plot with Lattice?
Hello, I want to do with Lattice functions (qqmath, histogram) a figure like this below. n <- 1000 x <- rnorm(n) qqnorm(x); qqline(x) op <- par(fig=c(.02,.5,.5,.98), new=TRUE) hist(x, xlab="", ylab="", main="", axes=FALSE) box() par(op) Is possible? Thanks. Walmes Zeviani. _________________________________________________________________
2010 Feb 20
1
How get the single bar x coordinate in barchart when groups is used?
Hi all, I am using barchart() to plot values above the bars. When using groups argument we get bars grouped arround a given x level. By placing values above this bars we need to know the respective x coordinates. How can I get it? require(lattice) da <- expand.grid(x=1:5, z=1:3, w=1:2) da$y <- rpois(da$x, lambda=23) barchart(y~x|w, groups=z, data=da, horizontal=FALSE,
2011 Aug 06
1
How set lm() to don't return NA in summary()?
Hi, I've data from an incomplete fatorial design. One level of a factor doesn't has the levels of the other. When I use lm(), the summary() return NA for that non estimable parameters. Ok, I understant it. But I use contrast::contrast(), gmodels::estimable(), multcomp::glht() and all these fail when model has NA estimates. This is becouse vcov() and coef() has different dimensions. Is
2010 Jan 14
3
Barchart bar lengths not proportionate
When I use barchart (with default formatting options), I get bars whose lengths/heights are not proportional to their value. For example: http://drop.io/wbagm6s/asset/capture-png Many of the values in this chart are 1; however, because the blue bars extend to the left of the "0" tick mark, those bars appear to represent higher numeric values. Is there a way to make the length of the
2010 Mar 03
1
Correct nested design for GLM
Hi, I am currently running the following negative binomial GLM: glm89.nb <- glm.nb(AvGUD ~ Year*Trt*Micro + (0 + Micro/Trt/Year)) where Year has 3 levels, Trt has 2 levels, and Micro has 3 levels. >From what I have read the above model has a 3 way interaction (Year*Trt*Micro), and Micro is nest within Trt and Trt is nested with Year (0 + Micro/Trt/Year). I was hoping someone could
2010 Mar 01
3
help with lattice boxplots...
Hi All, I need a small help with following code: I'm trying to convert "dashed lines" to regular ones; and changing default "blue" border color to say "black"... but I'm doing it wrong and its not working. Can anyone help please. Thanks, Code: require(lattice) ex <- data.frame(x=1:10, y=rep(c("A","B"), 5)) bwplot(y~x, data=ex,
2011 May 25
1
Adjusted Rate Ratios in R
I am trying to calculate Poisson regression based adjusted rate ratios in R, but R's default in glm does not code the intercept as the global rate. In SAS I use "cell means" coding so that the intercept is the global rate, but I do not know how to do this in R. If anyone knows a way to make glm use "cell means", or an how to find adjusted rate ratios I would be grateful.
2011 Jun 15
1
Legend in lattice
Dear all, I have been working in a plot based on figure 5.6 of the Lattice book (http://lmdvr.r-forge.r-project.org/figures/figures.html). I have already modified it to include the size of the circles as another variable, but I would like to modify the legend to show it (like they do it in http://www.jstatsoft.org/v15/i05/paper). I have divided my variable in intervals: DATA$s_Shape_2 <-
2012 Apr 12
1
Encoding of Sweave file error message
Hi I ran the following sweave file in R2.14.1 and upgraded to R2.15 yesterday with the same setup I got the following error message when I rand the following Sweave file > setwd("D:/Cic/Sweave/Parasite/Comb/12") > Sweave("D:/Cic/Sweave/Parasite/Comb/12/ParasiteComb12.Rnw") Error: c("'ParasiteComb12DS.Rnw'", "'ParasiteComb12.Rnw'")
2010 Jan 04
2
Piecewise regression in lmer
Dear all, I'm attempting to use a piecewise regression to model the trajectory of reproductive traits with age in a longitudinal data set using a mixed model framework. The aim is to find three slopes and two points- the slope from low performance in early age to a point of high performance in middle age, the slope (may be 0) of the plateau from the start of high performance to the
2009 Dec 07
5
confint for glm (general linear model)
Hi, I have a glm gives summary as follows, Estimate Std. Error z value Pr(>|z|) (Intercept) -2.03693352 1.449574526 -1.405194 0.159963578 A 0.01093048 0.006446256 1.695633 0.089955471 N 0.41060119 0.224860819 1.826024 0.067846690 S -0.20651005 0.067698863 -3.050421 0.002285206 then I use confint(k.glm)
2010 Mar 17
1
Cropped graph using lattice
I'm fitting data from a mixture experiment, and I'd like to present the results in a ternary graph with contours. I found this code by Walmes Zeviani http://n4.nabble.com/Triangular-filled-contour-plot-td1557386.html which is just what I want--except I would like the axis titles and labels to be proportionately larger than the ternary graph itself, for legibility in publication. When I
2010 Feb 16
3
Triangular filled contour plot
Hi all, I am working on a filled contour plot which shows a triangular matrix data set (as shown below). Is there a possibilty to draw a triangular filled contour in a equilateral triangle (like a ternary plot)? Thanks in advance Johannes http://n4.nabble.com/file/n1557386/Bild3.png -- View this message in context: http://n4.nabble.com/Triangular-filled-contour-plot-tp1557386p1557386.html
2010 Jan 16
1
Hierarchical Linear Model using lme4's lmer
Hi, I was wondering: I've got a dataset where I've got student 'project's nested within 'school's, and 'division' (elementary, junior, or senior) at the student project level. (Division is at the student level and not nested within schools because some students are registered as juniors & others as seniors within the same school.) So schools are random,
2010 Jan 22
1
confidence intervals for mean (GLM)
Dear useRs, How could I obtain the confidence intervals for the means of my treatments, when my data was fitted to a GLM? I need the CI's for the Poisson and Negative Binomial distributions. Here's what I have: mydata1 <- data.frame('treatments'=gl(4,20), 'value'=rpois(80, 1)) model1 <- glm(value ~ treatments, data=mydata1, family=poisson) means1 <-