similar to: Finding row in matrix with minimum column

If I create a vector thusly > v1 <- runif(20, min=0, max=1) > v1 [1] 0.9754443 0.6306228 0.3238158 0.3175769 0.6791534 0.6956507 0.3840803 [8] 0.1421328 0.8592398 0.4388306 0.9472040 0.4727435 0.5645302 0.7391616 [15] 0.6116199 0.2727754 0.2657867 0.5261744 0.8764804 0.2032126 And I want to create a logical vector the same length that is true if v1<.3 or v1 > .7 how do I do it

Friends I clearly donot understand how sapply and vapply work. What I have is a function that returns a matrix with an indeterminate number of rows (some times zero) but a constant number of columns. I cannot reliably use an apply function to assemble the matrices into a matrix. I am not sure it is possible. I can demonstrate the core of my confusion with this simple code. A.f <-

Friends I am trying to format a number to a string so 2189.745 goes to "2,189.35" and 309283.929 goes to "309,283.93" I have tried to use formatC(X, big.mark=",",drop0trailing=FALSE, format="f") but it does not get the number of decimals correct. Specifying digits does not work as that is significant digits. I could use a switch statement switching on

Friends I have an xts that I wish to access. Browse[2]> DATA.ba[[p]]["2012-03-20 00:59:57","bid"] bid 2012-03-20 00:59:57 1.4993 So far so good. Now putting the index into a variable: Browse[2]> Time [1] "2012-03-20 00:59:57 NZDT" Browse[2]> DATA.ba[[p]][Time, "bid"] bid Where has it gone? Looking closer....

Friends I am looking at Rcpp and I am a bit stuck on a simple matter. (I am calling R from c++, if there is a better way...) Given this simple example using the TTR package and the SMA function which returns a simple moving average.... Rcpp::NumericVector rv; for(int i = 0; i < 100; i++){ rv.push_back(rand()); } Rcpp::Environment TTR("package:TTR");

Friends I am extracting sub-sets of the rows of a matrix. Generally the result is a matrix. But there is a special case. When the result returned is a single row it is returned as a vector (in the example below an integer vector). If there are 0, or more than 1 rows returned the result is a matrix. I am doing this in a function and I cannot be sure how many rows I am removing. How can I do

It seems obvious to me that the empty string "" is length 0. cheers Worik [[alternative HTML version deleted]]

I have trouble with this: as.Date("Sep-1981", format="%b-%Y") Returns "NA" >From documentation for strftime '%b' Abbreviated month name in the current locale. (Also matches full name on input.) '%Y' Year with century. What am I doing wrong? cheers Worik [[alternative HTML version deleted]]

Friends This is an elementary question. Is there is a built in R function for finding a sub-string in another string? Like strstr in C. I can easily roll my own, but if there is a built in that is one less thing I can do wrong! cheers Worik [[alternative HTML version deleted]]

Friends I am starting on a (section of the) project where I need to build a matrix with on the order of 5 million rows and 200 columns I am wondering if I can stay in R. I need to do rollapply type operations on the columns, including some that will be functions of (windows of) two columns. I have been looking at the ff and bigmemory packages but am not sure that they will do. Before I get

Is there a simple way to put a legend outside the plot area for a simple plot? I found... (at http://www.harding.edu/fmccown/R/) # Expand right side of clipping rect to make room for the legend *par(xpd=T, mar=par()$mar+c(0,0,0,4))* # Graph autos (transposing the matrix) using heat colors, # put 10% of the space between each bar, and make labels # smaller with horizontal y-axis labels

After a lot of processing I get a matrix into M. I expected each row and column to be a vector. But it is a list. R-Inferno says... "Arrays (including matrices) can be subscripted with a matrix of positive numbers. The subscripting matrix has as many columns as there are dimensions in the array—so two columns for a matrix. The result is a vector (not an array) containing the selected

I have two pairs of related vectors x1,y1 and x2,y2 I wish to do a test for differences in means of x1 and y1, ditto x2 and y2. I am getting odd results. I am not sure I am using 'pt' properly... I have not included the raw vectors as they are long. I am interested if I am using R properly... > c(length(x1), length(y1), length(x2), length(y2)) [1] 3436 1619 2677 2378 First

I think I am whistling in the wind, but is there a modern symbolic debugger for R programmes? I am working through some one else's code, thousands of lines, that has the occasional bug in it, and a lot in my understanding of it. I cannot make setBreakpoint or findLineNum work. I get "No source refs found.". I am starting to loose my mind! A debugger where I could set

Friends I need to get R reading from a fifo. I want it to block till there is some data in the fifo, consume what input it gets there, do some thing with it then loop back and block again. Very simple. Yes? No. The example in the documentation works OK.. zz <- fifo("foo-fifo", "w+") writeLines("abc", zz) print(readLines(zz))

Hi, Let's say I have the following data: > a=matrix(c(1,2,4,4,2,1,1,2,4),nrow=3,byrow=T) > a [,1] [,2] [,3] [1,] 1 2 4 [2,] 4 2 1 [3,] 1 2 4 What syntax should I use to get R to tell me the column that corresponds to the maximum value for each row? For my example, I would like to get a vector that says 3, 1, 3 because the maximum value for row 1 is

I am sure this si a simple problem but the solution is evading me. I have a list of matrices all with the same number of columns but different number of rows. The first two columns label the row. The labels are allways the same for the same row numbers, just some matricies have more rows. For example using 3 column matrices... > q.1 <- function(r){return(cbind(seq(0, 10, by=1)[1:r],

I am puzzled by the scope rules that apply with sapply. If I want to modify a vector with sapply I tried... N <- 10 vec <- vector(mode="numeric", length=N) test <- function(i){ vec[i] <- i } sapply(1:N, test) vec but it not work. How can this be done? Worik [[alternative HTML version deleted]]

Friends I have a data frame, df that I want to extract some rows from Here is a sample of the data > head(df) TDate Expiry Underlie Strike CSettle PSettle Futures ExDate TTE 1 20080102 200801 200803 0.840 0.0000 0 0.9207 20080104 0.005479452 2 20080102 200801 200803 0.850 0.0000 0 0.9207 20080104 0.005479452 Rate Disc 1 0.0457 0.9997496 2 0.0457

Is it possible to get a line number with an error report? I have a long script and an error: Error in `[.xts`(x, xsubset) : subscript out of bounds It would be very helpful, and save a lot of time, if there was some indication in the error message which line the error was. I can find it using binary search but that is a painful process. cheers Worik [[alternative HTML version deleted]]