similar to: Change pattern in histograms in ggplot2

Let''s start with an example: --- class Comment < ActiveRecord::Base end # dummy (to invent a "table namespace") class Review < ActiveRecord::Base end # ... dummy # is "review_comments" in the database class Review::Comment < ActiveRecord::Base belongs_to :thing end class Review::Thing < ActiveRecord::Base has_many :comments, :class_name =>

Hello, I''m looking for a cross-browsers library based on prototype.js that wraps XML dom. I tried to extend XML dom elements by using Object.extend and Element.extend without success. It works fine with firefox (Object.extend) but don''t work with IE (msxml). I suppose that IE objects are not ''prototype based'' objects. Is there a way to go around this issue like

Hi, We are currently porting our application to Windows 64 bits (amd64), and we are getting regressions from 32 bits relatively to LLVM 3.0's ability to get traversed by "foreign" Visual Studio C++ exceptions. That is, there is a crash when C++ exceptions which are thrown from Visual Studio code, are unwinding through LLVM code before being eventually catch by other Visual Studio

Hi, Let's say I have the following data: > a=matrix(c(1,2,4,4,2,1,1,2,4),nrow=3,byrow=T) > a [,1] [,2] [,3] [1,] 1 2 4 [2,] 4 2 1 [3,] 1 2 4 What syntax should I use to get R to tell me the column that corresponds to the maximum value for each row? For my example, I would like to get a vector that says 3, 1, 3 because the maximum value for row 1 is

Hi, I see from this post http://groups.google.com/group/rubyonrails-talk/browse_thread/thread/97e333daab05b725/8252c90cb9c36f6d?lnk=gst&q=passing+parameter+before_filter#8252c90cb9c36f6d it can specify the Proc in the before_filter function, but when specify when action apply this filter, it raise an syntax error, such as rthe following code before_filter {|controller|

Hi, I am trying to write a loop to recode my data from -999 to NA in R. What's the most efficient way to do this? Below is what I'm presently doing, which is inefficient. Thanks, Chris dat0 <- read.table("time1.dat") colnames(dat0) <- c("e1dq", "e1arcp", "e1dev", "s1prcp", "s1nrcp", "s1ints",

Hi, I am having trouble with syntax for a for loop. Here is what I am trying to do. class=c(rep(1,3),rep(2,3),rep(3,3)) out1=rnorm(length(class)) out2=rnorm(length(class)) out3=rnorm(length(class)) data=data.frame(class,out1,out2,out3) dat.split=split(data,data$class) for(i in 1:3){ sub[i]=dat.split[i] } However, the for loop doesn't work. I want to assign each split to a different

* Please cc me if you reply as I am a digest subscriber * Hi, I am wondering how I can run a multilevel survival model in R? Below is some of my data. > head(bi0.test) childid famid lifedxm sex age delta 1 22.02 22 CONTROL MALES 21.36893 0 2 13.02 13 MAJOR MALES 21.18001 0 3 64.02 64 CONTROL MALES 20.09377 0 4 5.02 5 CONTROL FEMALES

I get the following error when I run qplot() qplot(grade, read,data = hhm.long.m, geom = c("point", "smooth")) Error in smooth.construct.cr.smooth.spec(object, data, knots) : x has insufficient unique values to support 10 knots: reduce k. I am not sure how to tackle this problem. When I take a subsample (< 1000) than I am able to run that function but with my sample

Hi, I am trying to fit the following model: sr.reg.s4.nore <- survreg(Surv(age_sym4,sym4), as.factor(lifedxm), data=bip.surv) Where age_sym4 is the age that a subject develops clinical thought problems; sym4 is whether they develop clinical thoughts problems (0 or 1); and lifedxm is mother's diagnosis: BIPOLAR, MAJOR DEPRESSION, or CONTROL. I am interested in whether or not

I have 3 vectors: p1, p2, and p3. I would like each vector to be any possible value between 0 and 1 and p1 + p2 + p3 = 1. I want to graph these and I've thought about using scatterplot3d(). Here's what I have so far. library(scatterplot3d) p1 <- c(1,0,0,.5,.5,0,.5,.25,.25,.34,.33,.33,.8,.1,.1,.9,.05,.05) p2 <- c(0,1,0,.5,0,.5,.25,.5,.25,.33,.34,.33,.1,.8,.1,.05,.9,.05) p3 <-

I have a long list of posts posted on different days and many posts every day. I want them to arrange like following... Date1 ----- post1 post2 Date2 ----- post3 post4 post5 How can I (say) group them to appear all posts of one date under their related headng. Because records have so many different days, it is confusing me.. I need some generic solution. Thanks in advance. -- Posted via

I am curious if the following URL pattern is appropriate to use with REST and map.resources: Let''s say I want to build a website with information about cars. I decide that there will be a page to view/manage cars by model. The route for this is easily created: map.resources :cars The URLs look great. But now I want to introduce the ability to specify cars by year. I can do this by

Hi, I'd like to change scientific number formatting, 1,E+06, in y-axis values to 1 000 000 (number with 1000 separator). How to do this in ggplot..? I tried to use scale_discrete but couldn't get it to work. Below is a code I have this far: p<-ggplot(Data,aes(x=Date,y=PRINCIPAL)) p+geom_point() Thanks for any help! -Jack [[alternative HTML version deleted]]

I want to plot a multiline annotation including a mathematical expression using grid graphics (grid.text). This works fine for a single line, but the math expression is misplaced when I insert a line break ("\n" escape sequence): grid.text(expression(paste("Some words here\n more ", sigma))) Does someone have an idea how to fix that? TIA! Mark

Hello everybody, we were running into trouble after upgrading our samba PDC to a new hardware (and a new debian release). Before the upgrade we used 3.0.22 on a debian sarge machine without problems. Moving the installation to a new machine with debian etch (amd64, samba 3.0.24-6etch4) worked good at the first look. A closer look shows the following problems: - a domain member server (samba

Hi I have two questions about using ggplot2. First, I have multiple columns of data that I would like to combine into one histogram where each column of data would correspond to one bar in the histogram. Each column has 0 or 1s and I want my bars in the histogram to correspond to the sum of the 1s in each column. Does that make sense? Second, is there a way to completely turn off the legend?

Hi, I have 45 models that I have named: 1, 2, 3, ... , 45 and I am trying to plot them in order of ascending BIC values. I am however unclear as to how I can get the models to line up on the x-axis by BIC and not by numeric order. For example, if model 5 has a lower BIC than 1, I want it to be the first point on the left hand side of the curve. This seems to work in plot: plot(1:45,

Hi, I have 45 models that I have named: 1, 2, 3, ... , 45 and I am trying to plot them in order of ascending BIC values. I am however unclear as to how I can get the models to line up on the x-axis by BIC and not by numeric order. For example, if model 5 has a lower BIC than 1, I want it to be the first point on the left hand side of the curve. This seems to work in plot: plot(1:45,

Hi, I have longitudinal school suspension data on students. I would like to figure out how many students (id_r) have no suspensions (sus), i.e. have a code of '0'. My data is in long format and the first 20 records look like the following: > suslm[1:20,c(1,7)] id_r sus 11 0 15 10 16 0 18 0 19 0 19 0 20 0 21 0 21 0 22 0 24 0 24