similar to: pls help: lattice graph with both negative and positive value, x and y cross at 0 and negative value bars are plotted just oppositive direction in contrast to positive

Full_Name: Chris Hane Version: 2.10.1 OS: Windows Submission from: (NULL) (198.203.181.181) When using barchart in the flexcust package, setting mcol=NULL to avoid the lollipops causes an error. Each panel shows the text message "Error using packet n replacement has length zero." where n is the panel number. > data(iris) > cl <- cclust(iris[,-5], k=3) > barplot(cl,

Given the following data frame ("freq.sp"), > str(freq.sp) `data.frame': 42 obs. of 4 variables: $ behav : Factor w/ 6 levels "approach","bowride",..: 1 1 1 1 1 1 1 2 2 2 ... $ species: Factor w/ 7 levels "COAST_SPOT","EAST_SPINR",..: 1 2 3 4 5 6 7 1 2 3 ... $ n : int 193 194 563 357 570 369 74 194 208 633 ... $ pct :

Hello, I am attempting to write a script that adds error bars to a barchart. I basing my attempt heavily on the following thread: http://tolstoy.newcastle.edu.au/R/e2/help/06/10/2791.html I can't seem to get around the problem that was discussed in the thread. The following example should illustrate my problem. Sorry about the messy example but I am 1) trying to make it as close as possible

Dear all, I'm trying to use the lattice barchart function to obtain a bar plot of a variable for different values of two factors. The thing I'm trying to do is something like this: > barchart(MyVar ~ season | place, data=mydataset) My problem is that the column MyVar has some negative values and I would like them to be represented as bars stacking down from zero instead of what

Dear r-help mailing list, this seems stupid, but I actually don't find the solution: if I have a vector of numbers x of length n, ranging, say, from -3 to 4, if I do barplot (x) all the values below 0 go downwards, and all the positive values go upward. How can I make them all begin from the minimum pointing upwards? Thanks! Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical

Dear Ron and Bert, First (and without considering why one would want to do this, e.g., adding a start of 1 to the data), the following works for me: ------ snip ------ > library(MASS) > BoxCoxLambda <- function(z){ + b <- boxcox(z + 1 ~ 1, + lambda = seq(-5, 5, length.out = 101), + plotit = FALSE) + b$x[which.max(b$y)] + } > mrow <- 500

Thanks John. ?boxcox says: ************************* Arguments object a formula or fitted model object. Currently only lm and aov objects are handled. ************************* I read that as saying that boxcox(lm(z+1 ~ 1),...) should run without error. But it didn't. And perhaps here's why: BoxCoxLambda <- function(z){ b <- MASS:::boxcox.lm(lm(z+1 ~ 1), lambda = seq(-5, 5,

No, I'm afraid I'm wrong. Something went wrong with my R session and gave me incorrect answers. After restarting, I continued to get the same error as you did with my supposed "fix." So just ignore what I said and sorry for the noise. -- Bert On Sat, Jul 8, 2023 at 8:28?AM Bert Gunter <bgunter.4567 at gmail.com> wrote: > Try this for your function: > >

Hi Bert, On 2023-07-08 3:42 p.m., Bert Gunter wrote: > Caution: This email may have originated from outside the organization. Please exercise additional caution with any links and attachments. > > > Thanks John. > > ?boxcox says: > > ************************* > Arguments > > object > > a formula or fitted model object. Currently only lm and aov objects

Hi, Firstly, apologies as I have posted this on community.rstudio.com too. I want to optimise a Box-Cox transformation on columns of a matrix (ie, a unique lambda for each column). So I wrote a function that includes the call to MASS::boxcox in order that it can be applied to each column easily. Except that I'm getting an error when calling the function. If I just extract a column of the

Dear R-users, i want to plot gene regulation data in a lattice barchart. To illustrate the problem i encounter, the following code uses the "barley"dataset: library(lattice) barley[["SD"]] <- 5 PLOT <- barchart(data=barley, yield~variety|site, groups=year,origin=0, as.table=TRUE, scales=list(x=list(relation="same", rot=30), y=list(alternating=3,tck=-1)),

Try this for your function: BoxCoxLambda <- function(z){ y <- z b <- boxcox(y + 1 ~ 1,lambda = seq(-5, 5, length.out = 61), plotit = FALSE) b$x[which.max(b$y)] # best lambda } ***I think*** (corrections and clarification strongly welcomed!) that `~` (the formula function) is looking for 'z' in the GlobalEnv, the caller of apply(), and not finding it. It finds

Hello R-Users! I'm using a heatmap to visualize a matrix of values between -1 and 3. How can I set the colors so that white is zero, below zero is blue of increasing intensity towards -1 and above zero is red of increasing intensity towards red? I tried like this (using the marray and gplots packages from bioconductor): mcol <- maPalette(low="blue", mid="white",

Dear R users, I am trying to use the following code to make a barchar plot. The bars in the plot turn out to be a little narrow. Is there any way to modify the width of the bars? Thank you! library(lattice) scores = gl(2, 5, label=c('Sensitivity', 'PPV'), length = 100) sequences = gl(5, 1, label=c('Lemna minor', 'Dugesia japonica A', 'Gymnosporangium

Hi, Can anyone please help me with how I could add labels with the value for each bar in a barchart? (similar to how data labels can be added in Excel) I have done a lot of searching but havent been lucky. Thanks, Raoul -- View this message in context: http://r.789695.n4.nabble.com/Data-Labels-in-a-barchart-Lattice-or-otherwise-tp2278027p2278027.html Sent from the R help mailing list archive at

Estimados Le consulto porque estoy intentando presentar unos datos de alguna forma un poco distinta, salir un poco de la costumbre. Primero describo los datos: Suponiendo una secuencia: golpe al auto -> torura de vidrio -> rotura de aciento otro auto golpe al auto -> -> rotura de aciento , a este por alguna causa no se le rompio el vidio o esa información es desconocida. Esta

Hi R Users, I'm trying to re-order the "site names" ("Waseca", "Morris", ...). I'm using following code: libarry(lattice) barchart(yield ~ variety | site, data = barley, groups = year, layout = c(6,1), aspect=.7, ylab = "Barley Yield (bushels/acre)", scales = list(x = list(abbreviate = TRUE, rot=45,

Hi R users, I'm kind stuck in my R experience... I want to have a multiple barchart with n windows, but with the same background for each window, and I want that background to be a recorded dotplot. First, is it possible ? If so, I guess I have to call a record plot in the panel function but how ? As there is no panel.plot and I can't use the recorded plot as an argument for the

Hi, I created the barchart below using the lattice package, however I can't seem to find a way to add another variable as a line (see the desired square/lines that I drew for the last 10 years of the plot). Can anyone help me with this? Your help is much appreciated! Code: Schart<-barchart(Catch~Year,data=SNA, scales=list(col = "black", tck = c(1, 0),x=list(rot=45)))

Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = "Barley Yield (bushels/acre)", scales = list(rot = 45)) My question is: Is there an application of "rot" in something like