similar to: factors

On 10/04/2017 04:54 AM, Mark Haney wrote: > Why is it so hard for people to understand that var/run IS NOT > PERSISTENT and was never meant to be?? Do they not teach basic Unix > concepts anymore? http://www.pathname.com/fhs/pub/fhs-2.3.html#VARRUNRUNTIMEVARIABLEDATA While FHS notes that *files* should be cleared during the boot process, it does not indicate that directories should

Hi all, I'm hoping there's a quick fix for this. I have two data frames and am running a loop to match similar rows. However the matching is not working well, and I suspect it is because of the different formats of columns. For example, in col. 1 of dataframe 1 the nummbers are formatted as 1,2,3,4,5,6,7,8,9...31 However in col. 1 dataframe 2 the numbers are

Hello again, I am simply trying to import a rectangular table of strings. The table's dimensions are 1990 x 2, yet my read.table() command can only find 362 of the rows (and they're not the first 362). I would've taken the time to figure out how to use scan, readLines, or some other tool that can read in character strings, and then parse and input to a table, but that seems like

Hi All: Let's say I have two dataframes (Condition1 and Condition2); each being on the order of 12,000 and 16,000 rows; 1 column. The entries contain dates. I'd like to calculate, for each possible pair of dates (that is: Condition1[1:10,000] and Condition2[1:10,000], the number of days difference between the dates in the pair. The result should be a matrix 12,000 by 16,000. Really,

Hi all, I'm feeling a little guilty to ask this question, since I've written a solution using a rather clunky for loop that gets the job done. But I'm convinced there must be a faster (and probably more elegant) way to accomplish what I'm looking to do (perhaps using the "merge" function?). I figured somebody out there might've already figured this out: I have

Excuse the basic question but how do I do an in place upgrade from src? 3.2.2 to say 3.2.4..... Cheers, Kristian

Hi All, I'm trying to use the "sample" function within a loop where the vector being sampled from (the first argument in the function) will vary in length and composition. When the vector is down in size to containing only one element, I run into the "undesired behaviour" acknowledged in the ?sample help file. I don't want sample(10,1) to return a number from

Wow.. thanks for the deluge of responses! Aggregate seems like the way to go here. But, suppose that instead of integers in column V2, I actually have dates (and instead of keeping the minimum integer, I want to keep the earliest date): > df =

Hi, A noobie question: I'm simply trying to run a conditional statement that evaluates if a substring is found within a larger string. I find that if it IS found, my function returns TRUE (great!), but if not, the condition does not evaluate to FALSE. ex): if( grep("hi", "hop", fixed = TRUE) ) print('yes, your substring is in your string') else

Hi all, I'm hoping this question has a simple answer, but I can't find it through searching or trying commands. I have a list of numeric vectors called 'husk'. I'd just like to treat the set of all numbers from all vectors in the list as if it were one large vector, because I'd like to extract information, such as what is the max entry from all the numbers. > husk

Working with SSL on fresh install of latest Ubuntu Artful + Dovecot seems broken somehow. Application is Dovecot listening for many SSL sites... Likely I've missed adding something simple to the config, related to local_name usage. Be great if someone can point out what I've missed, to setup multiple SSL certs for different host.domain entries in config. Thanks. _______ This works as

Anybody have an idea why I would get a non-integer value for the number of days here? > difftime('2004-08-05','2001-01-03',units='days') Time difference of 1309.958 days Would you just round off? Best, Jon

Last one for you guys: The command: length(gregexpr('cus','hocus pocus')[[1]]) [1] 2 returns the number of times the substring 'cus' appears in 'hocus pocus' (which is two) It's returning the number of **disjoint** matches. So: length(gregexpr('aa','aaa')[[1]]) [1] 1 returns 1. **What I want to do:** I'm looking for a way to count

Hi R-help, I am interested in comparing two vectors of data observations to see if they come from the same distrubution (and have settled on the Kolmogorov-Smirnov test to do this).. I'd prefer to use all my data points, but computationally speaking, this is proving to be troublesome due to the size of my vectors (the larger of the two is about 90 million observations). I suppose I could

Hi all, I'm trying to generate a grid of four plots. The first 2 appear just fine, but the final 2 will not appear in the grid, instead overwriting the first two. Any ideas on how to get them all in the same window would be greatly appreciated. Cheers, Jonathan library(fields) par(mfrow=c(2,2)) #2x2 plot windows plot(c(2,4),c(2,2)) # works fine plot(c(2,4),c(2,2)) # works fine

I'm sure this isn't said enough, so kudos to Timo for what has to be the best IMAP server anywhere, hands-down no qualifications! And to think, it's a one man operation ... although perhaps that is one of the reasons it is so good.

Hi Rusers, I found sometimes that the same values cannot be judged to be the same in R. Anybody knows the probelm? I think i ignored some minor detail. Thanks. Here is the example. ############ data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)

Hi, There must be an easy way to do this, but I'm not finding it.. I'd just like to know the syntax to move up and down folder levels, without necessarily entering a full file path. Also, how to construct file and folder paths using variables. For example 1, if I wanted to print to the screen the contents of a file called myFile.txt using the bash shell, I'd use the following:

Hi r-help community, This question isn't so much a syntax/coding one, but here goes: Let's say I have matrix of arbitrary dimensions and I'd like to reorder the rows in such a way that I could maximize the sum of the entries along the diagonal. For example, for this 3x3 matrix: [,1] [,2] [,3] [1,] 3 4 13 [2,] 9 1 2 [3,] 2 11 1 rearranging the rows

Hi All, My R installation is acting strangely and I'm hoping somebody might have an idea what's going on: I can't seem to load the "RMySQL" function. It seems to have installed without a problem, but when I enter: library(RMySQL) R tells me: Error in utils::readRegistry("SOFTWARE\\MySQL AB", hive = "HLM", maxdepth = 2) : Registry key