similar to: Attempting to access an R list from within C code

Good morning R community, I have two questions (and a comment): 1) A problem with odfWeave. I have an odf document with a table that spans multiple pages. Each cell in the table is populated using \sexpr{<R stuff>}. This worked fine on my own machine (windows 7 box using any R2.x.y, for x>=11) and on a colleagues machine (Windows XP box running R2.11.1). However, on a third machine

Hi All, Inside my app\views\expenses\new.html.erb file, I had the code: <% form_for(@expense) do |f| %> [snip] <p> <%= f.label :vendor %><br /> <%= f.text_field :vendor %> <br /> <div id="vendor_droplist> <%= select_tag "test", options_for_select(@current_vendors.collect { |v| v.nickname }), {:multiple

dear everyone system:windows XP R2.13.0 I download the windows binary from website and successfully install it ,because I use a proxy server ,when I follow the instrction as follows: I set a system property R_HOME=C:\Program Files\R\R-2.13.0 " R_HOME\bin\i386\Rgui.exe http_proxy=http://211.83.105.140:808/" error:: '\i' is an unrecognized escape in character string starting

Hello there R-help, I'm not sure if this should be posted here - so apologies if this is the case. I've found a problem while using rle and am proposing a solution to the issue. Description: I ran into a niggle with rle today when working with vectors with NA values (using R 2.31.0 on Windows 7 x64). It transpires that a run of NA values is not encoded in the same way as a run of other

Hi, I'm using a Mac, I've downloaded R (base), and I'm trying to download the package R Commander. I thought I had already done this (both from the web and from within R) but it doesn't seem to be working - it's not there as a "search()" reveals. However, there are plenty of files on my system linked with Rcmdr - located in

Hello, I have the following problem when trying to use rm: In a top level script file I have a loop iterating over some index. The loop is not contained within a function, so the scope of variables declared in the loop is global. Within this loop I generate several variables which should be removed at the end of each iteration. To do this, I wrote a function to clean up the workspace. An example

Good morning R-help, I have an idiot question: I would like to use getSrcDirectory() and friends to allow me to identify where an R file has been called from when invoked using Rscript. If I understand the documentation correctly, the following example should work: In file test.R: options(keep.source=T) fn<-function(x){x<-x+1} srcDir<-getSrcDirectory(fn) print(srcDir) I

Dear R users, A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults. However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R: myfunction=function( list1=list

i did some searching through the archives and didn''t really find an answer to my question, so i''m going to just ask it. i have a situation where there are 3 sortable lists. list1, list2, and list3 i need list2 to accept divs from all 3 lists, but list1 and list3 to only accept divs from the list1 and list3 i''ve added two classes to the divs in my sortables: .rail

HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-colSums(x, na.rm=FALSE) z<-matrix(y,ncol=10) ?z<-as.dist(z) ?z ?# ?? 1?? 2?? 3?? 4?? 5??

Hi, This has bugged me for a bit. First question is how to keep classes with rbind, and second question is how to properly return vecotrs instead of lists after turning an rbind of lists into a data.frame list1=list(a=2, b=as.Date("20090102", format="%Y%m%d")) list2=list(a=2, b=as.Date("20090102", format="%Y%m%d")) rbind(list1, list2) #this loses the

Hi folks, I''m new to Rails. I picked up Simply Rails 2 by Patrick Lenz a few weeks ago and I finally sat down to get stuck into it. I have Rails installed on my iMac (OS X Leopard) and I can load up the Rails Welcome screen at localhost:3000 without any issues. My problem is with running IRB within Terminal. If I try to run: irb> 1 I receive the error: dyld: NSLinkModule() error

I have the following code: list1 <- list() for (i in list.files(pattern="filename1")){ x <- read.table(i) list1[[i]] <- x } list2 <- list() for (i in list.files(pattern="filename2*")){ x <- read.table(i) list2[[i]] <- x } anslist <- vector('list', length(list1)) for(i in 1:length(list1)) if (list1[[i]] & list2[[i]] >1)

I'm attempting to generalise a function that reads individual list components, in this case they are matrices, and converts them into 3 dimensional array. I can input each matrix individually, but want to do it for about 1,000 of them ... This works array2 <- abind(list1[[1]],list1[[2]],list1[[3]],along=3) This doesn't array2 <- abind(list1[[1:3]],along=3) This doesn't either

R-helpers: Say I have two lists of arbitrary elements, e.g.: list1=list(c(1:3),"R is fun!",c(3:6)) list2=list(c(10:5),c(5:3),c(13,5),"I am so confused") I would like to produce a single new list that is composed of all combinations of the "top level" of list1 and list2, e.g.: listcombo=list(list(list1[[1]],list2[[1]]),list(list1[[1]],list2[[2]]

Hi R users: I got this code to generate a graphic for each member of a lists. list1<-list(A=data.frame(x=c(1,2),y=c(5,6)),B=data.frame(x=c(8,9),y=c(12,6))) names1<-names(list1) sapply(1:length(list1),function(i) with(list1[[i]],plot(x,y,type="l",main=paste("Graphic of",names1[i])))) Is there a more elegant solution for not to use two separate lists? I would like to

Hello R-Help, ----------------------------------------------------------------------------------------------------------------------------------------- Issues (there are 2): 1) Possible bug when using lmtest::encomptest() with a linear model created using nlme::lmList() 2) Possible modification to lmtest::encomptest() to fix confusing fail when models provided are, in fact, nested. I have

Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent** list objects. For example please consider following: > list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2) <- c("a", "b") > list1[[1]] <- matrix(1:25, 5) > list1[[2]] <- matrix(2:26, 5) > list2[[1]] <- 10:14 > list2[[2]] <-

I am new to R, and I have been running into the following situation when I mistype a variable name in some code: > list1 <- list( a=1, b=2 ) > list2 <- list( a=1 ) > list2$b <- list1$c > list2 $a [1] 1 I would think at the point where I am trying to reference a field called "c" -- that does not exist -- in list1, there would be an error flagged. Instead, list1$c

I cannot understand why the following expression is accepted (and gives the expected result: to set column 3 and 4 of the first element of list1 -a data.frame list- as first element of list2): > list2[[1]]<-list1[[1]][3:4] ...while this one is not (to do the same iteratively from the first to the eleventh element of list1): > for (i in 1:11){list2[[i]]<-list1[[i]][3:4]} Error in