similar to: lattice wireframe with logarithmically scaled axis?

Dear all I am trying to make a graphic with the "vioplot" package. I use the following code: library(vioplot) x1 <- GSMrxDL x2 <- WIFI x3 <- UMT vioplot(x1, x2, x3, ylim=c(0, 10), names=c("GSMrxDL", "WIFI", "UMT"), col="gold") title("NIS Strahlung", xlab="Sender", ylab="V/m") Now I want to scale the y-axis

Hello Everyone, I am using R ver. 2.10.1 (2009-12-14). I installed lattice today via install.packages. I am doing this minimal example: M = read.csv("/path/to/csv") cloud(x ~ y * z, data = M) this correctly gives me a scatterplot of the csv data which has 3 columns. Every column contains 1800 numeric 0 < values < 1300 when I want to plot the corresponding wireframe via

Dear expeRts, I would like to add two points to a wireframe plot. The points have (x,y,z) coordinates where z is determined to be on the wireframe [same z-value]. Now something strange happens. One point is perfectly plotted, the other isn't shown at all. It only appears if I move it upwards in z-direction by adding a positive number. So somehow it disappears in the wireframe-surface

Hello, I am trying to get a surface plot of a data set that looks like the following, 1 2 5.6 5 9 2.4 9 8 9.8 ... to (60,000 rows down) From my homework, the persp function only works with evenly spaced data points with the z data beeing in a matrix. my data is not in that format. the wireframe fxn gives me an error, no applicable method for "wireframe" the

Hello, I try to increase the distance between tick labels and ticks in a lattice wireframe plot. Here's a minimal example: ## Minimal example x <- y <- z <- c(1,2,3) df <- data.frame(x, y, z) wireframe(z ~ x*y, df, scales = list(arrows = FALSE, col = "black", font = 1, tck=0.6)) I tried the axis.components option

Hi, I am using function wireframe from package lattice to draw a 3D surface. I would like to add a few points on the surface. I read in a post from Deepayan Sarkar that "To do this in a wireframe plot you would probably use the panel function panel.3dscatter". Does someone have an example? When calling panel.3dscatter with only x, y and z arguments I get "argument

Hi, I have the following problem. Calling wireframe within a loop results into an empty window(s) #generate some data temp = expand.grid(A = 1:3,B = 1:3) temp = cbind(temp, y1 = rnorm(9)) temp = cbind(temp, y2 = runif(9)) #plot y1 and y2 in two different windows for(i in 1:2) { wireframe(y1 ~ A*B, temp, shade =T) windows() wireframe(y2 ~ A*B, temp, shade =T) } #However, calling it twice

Per the message from Alexander Nervedi, 29 April 2006: > I have to be making a riddiculously silly ommission. > when I run the fillowing i get the cloud plot ok. But I cant figure > out what I am missing out when I call wireframe. > Any help would be appreciated. > x<-runif(100) > y<-rnorm(100) > z<-runif(100) > temp <-data.frame(x,y,z) >

Hello R-classicist won't like the following question due to there's no minimal reproducible example and the question was posted already. Anyway I'm not able understand this rather complicated version of "add points to wireframe". what I have is matrix 3x2000 with a dem<-(x,y,z, coordinates) (not provided). with follwing code I want to produce the wireframe and add some

Dear List, I am using the wireframe function in the lattice package, and I am wondering if it is possible to invert the default axes orientation for x and y axes... what parameter should I look for? Best regards, Simone Gabbriellini

Hi all, I'd like to plot the Real and Imaginary parts of some f(z) as two different surfaces in wireframe (the row/column axes are the real and imag axes). I know I can do it by, roughly speaking, something like plotz <- expand.grid(x={range of Re(z)}, y={range of Im(z), groups=1:2) plotz$func<-c(Re(f(z),Im(f(z)) wireframe(func~x*y,data=plotz,groups=groups) But that seems like a

I'm trying to create a 3D plot using wireframe with certain parts removed. I would like to get rid of the part of the outer cube that crosses over the plot leaving the back two walls and the axes. It would also be useful to put lines in the plot separate from the wireframe call. I've looked through the documentation and have not been able to find such a request. Here is my code

I've been using lattice/wireframe succesfully to visualize some data. I have one question. I want to be able to change the viewpoint ( i.e. rotate the plotted figure a bit left or right or up and down ) Is there a way to do that? Or is there some other package around that could help? Thanks.

#Hi, # #somebody knows how to remove the outer box around a wireframe and reduce the height # # test = data.frame(expand.grid(c(1:10), c(1:10))) z = test[,1] + test[,2] test = cbind(test, z) names(test) = c("x", "y", "z") require(lattice) wireframe(z ~ x*y, data = test, par.box = c(col = "transparent") ) #not this one but the remaining outer box.

Hi, Im plotting some data with wireframe() like so: wireframe(result ~ u * r, myData, scales=list(arrows=FALSE)) However, I would really like to display something different for the displayed values of "u" rather than the actual values. This is because my u-values are a sequence of quantiles of myData, and I would like to display the quantiles used (e.g. "0.8 0.85 0.9

I have a question about wireframe 3-D plots and how to apply colors. I have a large dataset of river flow (m^3/s) over time, and I have coded these flows based on their height. I would like to produce a wireframe plot that colors the graph based on the flow code, i.e. I would like high flows to be red, medium to be green and low flows to be blue. Here is some sample data with the basic

Hi R-helpers I would like to plot some planes which are perpendicular to the x-y plane, such as x=y. Is there a way to do this in wireframe? I realize that I am not plotting a function of x, y since there are infinite number of z's that satisfy the above relation.... Hmm... Somewhat related, I would also like to plot a line in 3 d space... Finally, if you are feeling really brave, I

A quick question. I'm trying to plot a surface from a fitted model along with the original points, as in the following example: df<-data.frame(expand.grid(100*runif(1:100), 100*runif(1:100))) df$Var3<-rnorm(length(df$Var1), mean=df$Var1*df$Var2, sd=10) my.lm<-lm(Var3 ~ Var1*Var2, data=df) my.fun<-function(x,y) predict(my.lm, data.frame(Var1=x, Var2=y),

Hello, The following code produces a quadrilateral: q<-matrix(c(1,3,1,2,3,1,2,4,2,1,4,2),nrow=4,byrow=T) qc<-xyz.coords(q) wireframe(z~y*x,qc) I have 2 questions 1) How can i remove the bounding box i.e the cube encompassing the quadrilateral? 2) Is there any function to get the 2D coordinates of the quadrilateral actually used in the final plot ? I could manually

Hello Dear, I have a function, like z=f(x,y), and try a surface plot with this function. But, on the reference of "wireframe" requires data option, so I generated x and y, and computed z with them. But, still I have a problem to draw a surface plot. The code and errors are ################################################## mle_beta0=64.43707; mle_beta1=-24365.16; # generating for